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This review covers the Depth-First Search (DFS) algorithm as an essential method for exploring graphs. DFS explores deeper into the graph as long as possible and backtracks when necessary. It defines colors for vertices (WHITE, YELLOW, BLACK) to indicate their state during traversal. The review also discusses types of edges identified during DFS—tree edges, back edges, forward edges, and cross edges—and how they relate to the structure of the graph. Sample code and examples illustrate DFS implementations clearly.
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CS 332: Algorithms Graph Algorithms David Luebke 16/6/2014
Review: Depth-First Search • Depth-first search is another strategy for exploring a graph • Explore “deeper” in the graph whenever possible • Edges are explored out of the most recently discovered vertex v that still has unexplored edges • When all of v’s edges have been explored, backtrack to the vertex from which v was discovered David Luebke 26/6/2014
DFS(G) { for each vertex u G->V { u->color = WHITE; } time = 0; for each vertex u G->V { if (u->color == WHITE) DFS_Visit(u); } } DFS_Visit(u) { u->color = YELLOW; time = time+1; u->d = time; for each v u->Adj[] { if (v->color == WHITE) DFS_Visit(v); } u->color = BLACK; time = time+1; u->f = time; } Review: DFS Code David Luebke 36/6/2014
DFS Example sourcevertex David Luebke 46/6/2014
DFS Example sourcevertex d f 1 | | | | | | | | David Luebke 56/6/2014
DFS Example sourcevertex d f 1 | | | 2 | | | | | David Luebke 66/6/2014
DFS Example sourcevertex d f 1 | | | 2 | | 3 | | | David Luebke 76/6/2014
DFS Example sourcevertex d f 1 | | | 2 | | 3 | 4 | | David Luebke 86/6/2014
DFS Example sourcevertex d f 1 | | | 2 | | 3 | 4 5 | | David Luebke 96/6/2014
DFS Example sourcevertex d f 1 | | | 2 | | 3 | 4 5 | 6 | David Luebke 106/6/2014
DFS Example sourcevertex d f 1 | 8 | | 2 | 7 | 3 | 4 5 | 6 | David Luebke 116/6/2014
DFS Example sourcevertex d f 1 | 8 | | 2 | 7 | 3 | 4 5 | 6 | David Luebke 126/6/2014
DFS Example sourcevertex d f 1 | 8 | | 2 | 7 9 | 3 | 4 5 | 6 | What is the structure of the yellow vertices? What do they represent? David Luebke 136/6/2014
DFS Example sourcevertex d f 1 | 8 | | 2 | 7 9 |10 3 | 4 5 | 6 | David Luebke 146/6/2014
DFS Example sourcevertex d f 1 | 8 |11 | 2 | 7 9 |10 3 | 4 5 | 6 | David Luebke 156/6/2014
DFS Example sourcevertex d f 1 |12 8 |11 | 2 | 7 9 |10 3 | 4 5 | 6 | David Luebke 166/6/2014
DFS Example sourcevertex d f 1 |12 8 |11 13| 2 | 7 9 |10 3 | 4 5 | 6 | David Luebke 176/6/2014
DFS Example sourcevertex d f 1 |12 8 |11 13| 2 | 7 9 |10 3 | 4 5 | 6 14| David Luebke 186/6/2014
DFS Example sourcevertex d f 1 |12 8 |11 13| 2 | 7 9 |10 3 | 4 5 | 6 14|15 David Luebke 196/6/2014
DFS Example sourcevertex d f 1 |12 8 |11 13|16 2 | 7 9 |10 3 | 4 5 | 6 14|15 David Luebke 206/6/2014
DFS: Kinds of edges • DFS introduces an important distinction among edges in the original graph: • Tree edge: encounter new (white) vertex • The tree edges form a spanning forest • Can tree edges form cycles? Why or why not? David Luebke 216/6/2014
DFS Example sourcevertex d f 1 |12 8 |11 13|16 2 | 7 9 |10 3 | 4 5 | 6 14|15 Tree edges David Luebke 226/6/2014
DFS: Kinds of edges • DFS introduces an important distinction among edges in the original graph: • Tree edge: encounter new (white) vertex • Back edge: from descendent to ancestor • Encounter a yellow vertex (yellow to yellow) David Luebke 236/6/2014
DFS Example sourcevertex d f 1 |12 8 |11 13|16 2 | 7 9 |10 3 | 4 5 | 6 14|15 Tree edges Back edges David Luebke 246/6/2014
DFS: Kinds of edges • DFS introduces an important distinction among edges in the original graph: • Tree edge: encounter new (white) vertex • Back edge: from descendent to ancestor • Forward edge: from ancestor to descendent • Not a tree edge, though • From yellow node to black node David Luebke 256/6/2014
DFS Example sourcevertex d f 1 |12 8 |11 13|16 2 | 7 9 |10 3 | 4 5 | 6 14|15 Tree edges Back edges Forward edges David Luebke 266/6/2014
DFS: Kinds of edges • DFS introduces an important distinction among edges in the original graph: • Tree edge: encounter new (white) vertex • Back edge: from descendent to ancestor • Forward edge: from ancestor to descendent • Cross edge: between a tree or subtrees • From a yellow node to a black node David Luebke 276/6/2014
DFS Example sourcevertex d f 1 |12 8 |11 13|16 2 | 7 9 |10 3 | 4 5 | 6 14|15 Tree edges Back edges Forward edges Cross edges David Luebke 286/6/2014
DFS: Kinds of edges • DFS introduces an important distinction among edges in the original graph: • Tree edge: encounter new (white) vertex • Back edge: from descendent to ancestor • Forward edge: from ancestor to descendent • Cross edge: between a tree or subtrees • Note: tree & back edges are important; most algorithms don’t distinguish forward & cross David Luebke 296/6/2014
DFS: Kinds Of Edges • Thm 23.9: If G is undirected, a DFS produces only tree and back edges • Proof by contradiction: • Assume there’s a forward edge • But F? edge must actually be a back edge (why?) source F? David Luebke 306/6/2014
DFS: Kinds Of Edges • Thm 23.9: If G is undirected, a DFS produces only tree and back edges • Proof by contradiction: • Assume there’s a cross edge • But C? edge cannot be cross: • must be explored from one of the vertices it connects, becoming a treevertex, before other vertex is explored • So in fact the picture is wrong…bothlower tree edges cannot in fact betree edges source C? David Luebke 316/6/2014
DFS And Graph Cycles • Thm: An undirected graph is acyclic iff a DFS yields no back edges • If acyclic, no back edges (because a back edge implies a cycle • If no back edges, acyclic • No back edges implies only tree edges (Why?) • Only tree edges implies we have a tree or a forest • Which by definition is acyclic • Thus, can run DFS to find whether a graph has a cycle David Luebke 326/6/2014
DFS And Cycles • How would you modify the code to detect cycles? DFS(G) { for each vertex u G->V { u->color = WHITE; } time = 0; for each vertex u G->V { if (u->color == WHITE) DFS_Visit(u); } } DFS_Visit(u) { u->color = GREY; time = time+1; u->d = time; for each v u->Adj[] { if (v->color == WHITE) DFS_Visit(v); } u->color = BLACK; time = time+1; u->f = time; } David Luebke 336/6/2014
DFS And Cycles • What will be the running time? DFS(G) { for each vertex u G->V { u->color = WHITE; } time = 0; for each vertex u G->V { if (u->color == WHITE) DFS_Visit(u); } } DFS_Visit(u) { u->color = GREY; time = time+1; u->d = time; for each v u->Adj[] { if (v->color == WHITE) DFS_Visit(v); } u->color = BLACK; time = time+1; u->f = time; } David Luebke 346/6/2014
DFS And Cycles • What will be the running time? • A: O(V+E) • We can actually determine if cycles exist in O(V) time: • In an undirected acyclic forest, |E| |V| - 1 • So count the edges: if ever see |V| distinct edges, must have seen a back edge along the way David Luebke 356/6/2014