1 / 9

Momentum and Energy

Momentum and Energy. Chapter 9, 10, 11 Physics Principles and Problems Zitzewitz, Elliot, Haase, Harper, Herzog, Nelson, Nelson, Schuler and Zorn McGraw Hill, 2005. The momentum of an object is the product of that object’s mass and velocity. p = m • v.

aldan
Télécharger la présentation

Momentum and Energy

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Momentum and Energy Chapter 9, 10, 11 Physics Principles and Problems Zitzewitz, Elliot, Haase, Harper, Herzog, Nelson, Nelson, Schuler and Zorn McGraw Hill, 2005

  2. The momentum of an object is the product of that object’s mass and velocity.p = m • v Therefore a large oil tanker (big m, small v) and moving bullet (small m, big v) could have equal momentums. http://kommandobryggan.se/ok/okbilder/oktavius2.jpg http://www.digicamhistory.com/HaroldEdgertonBulletSmall.jpg

  3. An impulse changes an object’s momentum. It is the product of force on an object and the amount of time that force is applied.F• ∆t = m• ∆v • The same impulse can be delivered in 2 ways: Increasing the force that is applied or increasing the time the force is applied. http://discovermagazine.com/2008/the-body/11-turn-your-fist-into-a-blocking-breaking-machine/karate.jpg http://sol.sci.uop.edu/~jfalward/physics17/chapter3/boxingglove.jpg

  4. Impulse - Momentum TheoremF • ∆t = pf - pior F • ∆t = mvf - mvi • A 2200-kg car traveling at 26-m/s can be stopped in 21-s by applying the brakes or in 0.22-s by hitting a wall. What is the force exerted on the car in both of these situations? pf = 2200-kg • 0-m/s = 0 pi = 2200-kg • 26-m/s = 57000-kg •m/s F = pf - pi0 - 57000 = -2700N OR 0 - 57000 = -260000N ∆t 21 0.22

  5. Conservation of Momentum • Within any closed (no change in mass), isolated (external forces are zero) system the momentum is conserved or does not change. http://webpages.uah.edu/~wilderd/momentum.jpg

  6. Elastic Collisions - Objects hit and bounce off m1v1 + m2v2 = m1v3 + m2v4where v1 and v2 are the velocities of the objects before the collision and v3 and v4 new velocities after the collision. Notice the masses haven’t changed. http://img.sparknotes.com/content/testprep/bookimgs/sat2/physics/0002/8ball.gif

  7. Inelastic Collisions - Objects hit and stick m1v1 + m2v2 = (m1 + m2)v3where v1 and v2 are the velocities of the objects before the collision and v3 is the new velocities of the combined masses. http://sol.sci.uop.edu/~jfalward/physics17/chapter3/trains.jpg

  8. Energy, Work and Power • Energy - the property or ability of an object to produce a change in itself or the world around it. • Work - a product of the force exerted on an object in the direction of motion and the object’s displacement. W = F • d (unit is the joule = N•m) • Kinetic Energy - energy resulting from motion. KE = 1/2mv2 • Work-Energy Theorem - work is equal to the change in kinetic energy. W = ∆KE • Work with Angle - a product of the force and the displacement, times the cosine of the angle between the force and the direction of displacement. W = Fdcos • Power - work done divided by the time taken to do the work. P = W / t (unit is the watt = J/s)

  9. Work and Power Problems • The third floor of a house is 8-m above street level. How much work is needed to move a 150-kg refrigerator to the third floor? • During a tug-of-war, team A does 2.2 x 105-J of work in pulling team B 8-m. What force did team A exert? • A wagon is pulled by a force of 38-N exerted on the handle at an angle of 42° with the horizontal. If the wagon is pulled in a circle of radius 25-m, how much work is done? • A lawn mower is pushed across a lawn by a force of 155-N along the direction of the handle, which is 22.5° above the horizontal. If 64.6-W of power is developed for 90-s, what distance is the mover pushed?

More Related