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The net forward force on the propeller of a 3.2 kg model airplane is 7.0 N. What is the acceleration of airplane?. Given: Force (F) = 7.0 N, Mass (m) = 3.2 kg unknown = acceleration (a) Solve: a = F/m = 7.0 N/ 3.2 kg = 2.19 N/kg.

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## Given: Force (F) = 7.0 N, Mass (m) = 3.2 kg unknown = acceleration (a) Solve: a = F/m

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**The net forward force on the propeller of a 3.2 kg model**airplane is 7.0 N. What is the acceleration of airplane? Given: Force (F) = 7.0 N, Mass (m) = 3.2 kg unknown = acceleration (a) Solve: a = F/m = 7.0 N/ 3.2 kg = 2.19 N/kg**What net forces is needed to accelerate a 1900 kg automobile**forward at 3.0 m/s2 ? • Given: mass = 1900 kg, • a = 3.0 m/s2 • Unknown = F • Solve: F = m x a • F = 1900 kg x 3.0 m/s2 • = 5700 kg . m/s2 • OR F = 5700 N (Newton)**A base ball accelerates downward at 11.3 m/s2. If the**gravitational force is the only force acting on the base ball and it is 2.9 N, what is the base ball ‘s mass? 3 mGiven: F = 2.9 N, a = 11.3 m/s2 Unknown: mass Solve: mass = force/acceleration m = F/a = 2.9 N/11./S2 = 0.25 kg**A sailboat and its crew have a combined mass of 655 kg. If a**net force of 895 N is pushing the sailboat forward, what is the sailboat’s acceleration? • Given: F = 895 N mass = 655 kg • Unknown = acceleration • Solve: a = F/m a = 895N / 655 kg acceleration = 1.37 m/s2

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