1 / 8

EXAMPLE 3

In the diagram, 1, 2, and 3 are all congruent and GF = 120 yards, DE = 150 yards, and CD = 300 yards. Find the distance HF between Main Street and South Main Street. Corresponding angles are congruent, so FE , GD , and HC are parallel. Use Theorem 6.6. EXAMPLE 3.

amara
Télécharger la présentation

EXAMPLE 3

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. In the diagram, 1, 2, and 3 are all congruent and GF = 120 yards, DE = 150 yards, and CD = 300 yards. Find the distance HFbetween Main Street and South Main Street. Corresponding angles are congruent, so FE,GD, and HCare parallel. Use Theorem 6.6. EXAMPLE 3 Use Theorem 6.6 City Travel SOLUTION

  2. = = = 300+150 CD HG 450 CD + DE HG + GF GF DE DE 150 150 = HF HF GF 120 120 EXAMPLE 3 Use Theorem 6.6 Parallel lines divide transversals proportionally. Property of proportions (Property 4) Substitute. Simplify. Multiply each side by 120 and simplify. HF =360 The distance between Main Street and South Main Street is 360 yards.

  3. In the diagram, QPRRPS. Use the given side lengths to find the length of RS. Because PR is an angle bisector of QPS, you can apply Theorem 6.7. Let RS= x. Then RQ = 15 – x. ~ EXAMPLE 4 Use Theorem 6.7 SOLUTION

  4. PQ 7 15 – x x RQ 3 RS PS = = EXAMPLE 4 Use Theorem 6.7 Angle bisector divides opposite side proportionally. Substitute. 7x = 195 – 13x Cross Products Property x = 9.75 Solve for x.

  5. Find the length of AB. 3. for Examples 3 and 4 GUIDED PRACTICE SOLUTION Corresponding angles are congruent, so the three vertical lines are parallel. Use Theorem 6.6.

  6. = AB 18 16 15 ANSWER So, the length ofABis 19.2 for Examples 3 and 4 GUIDED PRACTICE Parallel lines divide transversals proportionally. AB =19.2 Simplify.

  7. 4. DC AC Because DA is an angle bisector of CAB, you can apply Theorem 6.7. Let AB= x. DB AB = for Examples 3 and 4 GUIDED PRACTICE SOLUTION Angle bisector divides opposite side proportionally.

  8. 2 x = 4 = ANSWER 4 2 The length ofx = 4 4 4 2 x 4 4 2 4x = for Examples 3 and 4 GUIDED PRACTICE Substitute. Cross Products Property Solve for x.

More Related