1 / 11

Class 6

Class 6. Phase Diagrams And Microstructure. Homeworks. If everyone agrees, homeworks will be in the lab on a bench in alphabetical groups. Placed there this lunchtime so can be collected after 1.00pm Exam Multiple Choice – eg how does sodium and chlorine bond?.

aron
Télécharger la présentation

Class 6

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Class 6 Phase Diagrams And Microstructure

  2. Homeworks • If everyone agrees, homeworks will be in the lab on a bench in alphabetical groups. • Placed there this lunchtime so can be collected after 1.00pm • Exam • Multiple Choice – eg how does sodium and chlorine bond?

  3. Microstructures and Composition At eutectic composition, and temp, amount of a = 97.5-61.9/97.5-19.2 = 35.6/78.3= 45% amount of b = 61.9-19.2/97.5-19.2 = 42.7/78.3= 55% For 70% Pb 30% Sn, a phase if formed in a+liquid range, called pro eutectica. Amount of proeutectic a and eutectic a+b is obtained from inverse lever arm rule Amount of pro eutectic a = 61.9-30.0/61.9-19.2 =31.9/42.7=0.75=75% Amount of eutectic a+b = 30.0-19.5/61.9-19.2 = 10.5/42.4 = 0.25 = 25% The composition of the a will be the same independent of whether it is pro eutectic or eutectic at 80.8%Pb 19.2% Sn.

  4. Lead Tin Microstructures 38.1%Pb 61.9% Sn 90 %Pb 10%Sn 70% Pb 30%Sn 50%Pb 50%Sn

  5. Lead Tin Microstructures 15%Pb 85%Sn Equiaxed Single Phase Grain Structure

  6. Iron Carbon (Fe3C) Phase Diagram • Primary solid solubility • in a is 0.022wt% C, for • is 2.14 wt% C. Eutectoid reaction is important for steels. • > a + Fe3C at 727C. At 726C , a 99.978%Fe 0.022%C Fe3C 93.3%C 6.7%C Fe3C is a compound and a Metastable phase, not an equilibrium phase, but stable unless thermally changed. Eutectoid composition Is Fe 99.24%, C 0.76%

  7. Eutectoid Composition At 727C Eutecoid Reaction occurrs. • > a + Fe3C Above 727C all g, equiaxed. Below 727C, a + Fe3C Amounts of a and Fe3 C given by Inverse Lever Arm Rule. Amount of a = 6.7 – 0.76/ 6.7-0.022 = 5.94/6.678 = 0.89 = 89% a Amount of Fe3C = 0.76- 0.022/ 6.7-0.022 = 0.738 / 6.678 = 0.11 = 11% Fe3C a composition is 99.978%Fe, 0.022 C Fe3C composition if 93.3%Fe, 6.7%C

  8. Eutectoid Formation a Carbon moves from a g Fe3C Iron moves from carbide Growth Direction

  9. Eutectoid Alternate ferrite and cementite plate structure in Eutectoid steel.

  10. Hypereutecoid Strucutres Hypereutecoid – more carbon then eutectoid >0.76% Start in single phase austenite, g, range, grains of g. Cool into two phase region, then some g transforms to Fe3C on the existing g grain boundaries. Called “Pro Eutectoid” cementite. g composition follows phase boundary to the eutectiod composition, so at 727C the remaining g transforms to pearlite, the mixture of a + Fe3C. Cementite exists as Pro eutectoid and eutectoid forms.

  11. Hypoeutectoid Steels Hypoeutecoid steels – less carbon than eutectoid < 0.76% Start in single phase austenite, g, range, grains of g. Cool into two phase region, then some g transforms to a on the existing g grain boundaries. Called “Pro Eutectiod” ferrite. g composition follows phase boundary to the eutectiod composition, so at 727C the remaining g transforms to pearlite, the mixture of a + Fe3C. Ferrite exists as Pro eutectoid and eutectoid forms.( Pearlite has narrow plates in this case of a steel with 0.08%C)

More Related