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# Chapter 2.7.

Precalculus – Spring 2005. Chapter 2.7. Modeling With Functions. Modeling. Modeling = a function that describes the dependence of one quantity on another Example : number of bacteria in a certain culture increases with time

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## Chapter 2.7.

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1. Precalculus – Spring 2005 Chapter 2.7. Modeling With Functions

2. Modeling • Modeling = a function that describes the dependence of one quantity on another • Example: number of bacteria in a certain culture increases with time • Goal: model the phenomenon by finding the precise function that relates the bacteria population to the elapsed time

3. Guidelines for Modeling with Functions • Expressthe Model inWords. Identify the quantity you want to model and express it, in words, as a function of the other quantities in the problem. • Choose the Variable. Identify all the variables used to express the function in Step 1. Assign a symbol, such as x, to one variable and express the other variables in terms of this symbol.

4. Guidelines for Modeling with Functions 3. Set up the Model. Express the function in the language of algebra by writing it as a function of the single variable chosen in Step 2. 4. Use the Model. Use the function to answer the question posed in the problem. (To find a maximum or a minimum, use the algebraic or graphical methods learned)

5. Example: Modeling the Volume of a Box A breakfast cereal company manufactures boxes to package their product. For aesthetic reasons, the box must have the following proportions: Its width is 3 times its depth and its height is 5 times its depth. • Find a function that models the volume of the box in terms of its depth. • Find the volume of the box if the depth is 1.5 in. • For what depth is the volume 90 in3? • For what depth is the volume greater than 60 in3?

6. Thinking about the problem Let’s experiment: If the depth is 1 in., then the width is 3 in. and the height is 5 in. So in this case the volume is V = 1*3*5= =15in3. Notice: the greater the depth the greater the volume. 3x 5x

7. Solution Step 1. Volume = depth * width * height Step 2. x = depth of the box width = 3x height = 5x Step 3. V(x) = x*3x*5x = 15 x3 Step 4. (b) V(1.5) = 15(1.5)3 = 50.625 in3 (c) V(x) = 90, so 15 x3 = 90, so x = 1.82 in (d) V(x) > 60, so 15x3 > 60, so x > 1.59 in.

8. Homework A gardener has 140 feet of fencing to fence in a rectangular vegetable garden. (a) Find a function that models the area of the garden she can fence. (b) For what range of widths is the area greater than 825 ft2? (c) Can she fence a garden with area 1250 ft2? (d) Find the dimensions of the largest area she can fence.

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