1 / 30

OSI layer Network Subnetting & VLSM

OSI layer Network Subnetting & VLSM. Nyoman suryadipta , st , ccnp Rev 0.2 18 Okt 2013. Tujuan. Mengetahui dasar Subnetting Mengenal konsep VLSM Mengidentifikasi Subnet CIDR Menganalisis Perhitungan Subnetting menggunakan VLSM Merencanakan Desain Jaringan berbasis VLSM.

atira
Télécharger la présentation

OSI layer Network Subnetting & VLSM

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. OSI layer Network Subnetting & VLSM Nyomansuryadipta, st, ccnp Rev 0.2 18 Okt 2013 Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  2. Tujuan • MengetahuidasarSubnetting • Mengenalkonsep VLSM • Mengidentifikasi Subnet CIDR • MenganalisisPerhitunganSubnettingmenggunakan VLSM • MerencanakanDesainJaringanberbasis VLSM Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  3. Subnetting Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  4. Sub = Pembagian • Netting = Jaringan • JadiSubnetting = PembagianJaringan • DibagiberdasarkanJumlahAlamat IP Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  5. Untukmembagialamat IP di Jaringansubnettingmelakukanpenguncian/pembatasan • Berdasarkan subnet mask Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  6. Subnet Asli / Default Subnet/Classful Subnet • Kelas A : 1-126 • Subnet mask : 255.0.0.0 • Kelas B : 128-191 • Subnet mask : 255.255.0.0 • Kelas C : 192-223 • Subnet Mask : 255.255.255.0 Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  7. Default Subnet Mask Kelas C Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  8. IP : 192.168.1.X Subnet mask: 255.255.255.0 ataubisaditulis /24 Biner : 11111111.11111111.11111111.00000000 2^8 = 256 Valid = 256 – 2 = 254 IP Valid yang bisadigunakan : 192.168.1.1 s/d 192.168.1.254 Jadi IP Valid diperolehdenganmelakukan 2 pangkat x dari Bit 0 Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  9. IP : 172.16.x.x Subnet mask: 255.255.0.0 ataubisaditulis /16 Biner : 11111111.11111111.00000000.00000000 2^16 = 65536 Valid = 65536 – 2 = 65534 IP Valid yang bisadigunakan : 172.16.1.1 s/d 172.16.254.254 Dikurangi 2 karenadipakaiuntukalamat broadcast & Network Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  10. Powers of Two Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  11. Study Case • BuatlahperencanaanSubneting Perusahaan PT MajuMundurjika di kantortersebutterdapat 600 PC • Jawab : • 192.168.1.x/24 Jumlah IP = 254 • 192.168.2.x/24 JumlahIP = 254 • 192.168.3.x/24 Jumlah IP = 254 • Total alokasi IP = 762 • Sisa = 162 IP Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  12. CIDR – Classless Interdomain Routing • Adalahmetodepenggunaan subnet mask tanpamelihatKelasAlamat IP, seringdiseingkatmenggunakannotasi slash “/” Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  13. CIDR – Classless Interdomain Routing • Misal • IP Kelas A menggunakan Subnet mask kelas C • IP : 10.10.1.1 • Subnet mask 255.255.255.0 ataudisingkat /24 Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  14. VLSM Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  15. VLSM • Variable Length Subnet Mask – Yaitupenggunaan Subnet mask denganpanjang yang bervariasitidakmengacuke Subnet mask asli Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  16. Tujuan VLSM adalahmembagiAlamat IP sesuaikebutuhan agar tidakterbuangpercuma • Manfaat VLSM sangatterasa di lingkungan ISP / PenyelenggaraJaringan Internet, karena ISP harusmenghemat IP Publik yang akandiberikankePelanggan Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  17. VLSM • Subnet mask asli • Kelas A : 255.0.0.0 • Kelas B : 255.255.0.0 • Kelas C : 255.255.255.0 Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  18. VLSM • Modifikasi VLSM • Contoh : • Kelas A : 255.128.0.0 atau /9 • Kelas B : 255.255.192.0 atau /18 • Kelas C : 255.255.255.252 atau /30 Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  19. Tanpa VLSM A B Roti berukuranbesardandibagi Ke 4 Orang sama rata Jikatidakhabisbanyaksisaterbuang Dan tidakbisadibagike orang lain D C Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  20. Dengan VLSM A B Roti berukuranbesardandibagi Ke 4 Orang sesuaiporsimakanmasing-masing Jikatidakhabissisabisadibagike orang lain SISA C D Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  21. Tanpa VLSM JalanArief Rahman Hakim Gang I No 1 s/d 64 Jalan Arief Rahman Hakim Gang II No 1s/d 64 JalanArief Rahman Hakim Gang III No 1 s/d 64 Jalan Arief Rahman Hakim Gang IV No 1 s/d 64

  22. Dengan VLSM JalanArief Rahman Hakim Gang I No 1 s/d 100 JalanArief Rahman Hakim Gang II No 1 s/d 50 JalanArief Rahman Hakim Gang IIII No 1 s/d 50 JalanArief Rahman Hakim Gang IV No 1 s/d 30 JalanArief Rahman Hakim Gang V No 1 s/d 24

  23. /23 = 11111111.11111111.11111110.00000000 /27 = 11111111.11111111.11111111.11100000 /9 = 11111111.10000000.00000000.00000000 Notasi subnet mask diatasmewakilki bit yang bernilai 1

  24. Tuliskan subnet mask dariNotasi CIDR berikut 192.168.1.1/23 /25 = 11111111.11111111.11111111.10000000 128+64+32+16+8+4+2+1=255 128+0+0+0+0+0+0+0=128 Jadi Subnet mask : 255.255.255.128

  25. Berapakahjumlah valid host /25 = 11111111.11111111.11111111.10000000 2^7 = 128 JadiJumlah valid host = 128 – 2 = 126

  26. Case Study • Misalsebuah ISP akanmendistribusikan IP Publikkepelanggannyadengankebutuhansebagaiberikut : • Pelanggan A butuh 30 IP • Stok IP Publik yang dimiliki ISP adalah 200.100.100.0/24 • Bagaimanakanpembagian subnet dengan VLSM ?

  27. Cari host yang mendekatidenganrumus: 2^N - 2 Yang mendekati 30 adalah 2^5 – 2 = 30 subnet : 255.255.255.224 ataunotasi CIDR = /27 biner : 11111111.11111111.11111111.111 00000 Subnet mask/Network ID 128 + 64 + 32 = 224 Jumlah Host 2^ 5 – 2 = 30

  28. Practice - TentukanJumlah Valid Host & subnet mask VLSM berikut : • /24 • /25 • /26 • /27 • /28 • /29 • /30 • /31 • /32 Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

  29. Practice • Disebuahperusahaanterdapat 4 departemenbuatlahmapping VLSM dengankebutuhanberikut (kelas IP bebas) • Gambarkan & tentukan subnet mask • DeptA 60 Host • Dept B 22 Host • Dept C 5 Host • Dept D 22 Host

  30. Finish Narotama University – Computer Science Faculty - Nyoman Suryadipta, ST. CCNP

More Related