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DIMENSIONAL ANALYSIS (also known as Factor-Label Method)

DIMENSIONAL ANALYSIS (also known as Factor-Label Method). Steps to Problem Solving. Read problem Identify data Make a unit plan from the initial unit to the desired unit Select conversion factors Change initial unit to desired unit Cancel units and check

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DIMENSIONAL ANALYSIS (also known as Factor-Label Method)

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  1. DIMENSIONALANALYSIS(also known as Factor-Label Method)

  2. Steps to Problem Solving • Read problem • Identify data • Make a unit plan from the initial unit to the desired unit • Select conversion factors • Change initial unit to desired unit • Cancel units and check • Do math on calculator • Give an answer using significant figures

  3. Conversions • If you know ONE conversion for each type of measurement, you can convert anything! • You must memorize and be able to use the metric conversions:

  4. Conversion Factors Fractions in which the numerator and denominator are EQUAL quantities expressed in different units Example: 1 ft = 12 in. Factors: 1 ft. and 12 in 12 in 1 ft. Example: 1 g = 102 cg. Factors: 1 g. and 102 cg 102 cg 1 g

  5. How many minutes are in 2.5 hours? Conversion factor 2.5 hr x 60 min = 150 min 1 hr By using dimensional analysis / factor-label method, the UNITS ensure that you have the conversion right side up, and the UNITS are calculated as well as the numbers!

  6. Sample Problem • You have $7.25 in your pocket in quarters. How many quarters do you have? 7.25 dollars4 quarters 1 dollar X = 29 quarters

  7. Sample Problem – Using Metric • You have 200 L of gasoline in your car. How many milliliters do you have? 200 liters103 milliliters 1 liter = 2 x 103 mL

  8. Learning Check SET UP THESE PROBLEMS USING DA - 2.22 cg = _______g 1.7 x 106 ng = ___________ g .288 g = __________mg 1.5 KL = ___________L

  9. Multi-Step Problems You are in Paris and want some peaches for lunch. The sign in the fruit stand indicates that peaches are 11.5 francs per kilogram. Given that there are approximately 5 francs to the dollar, calculate what a pound of peaches will cost in dollars. 455 g 1Kg 11.5 f 1 $ NOW WHAT?? 1 lb. 1000 g 1Kg 5 f 1 lb.

  10. Practice Problems • Mrs. Borden has 3 classes of Chemistry. Each class has 25 students in it and they are each required to pay $15.00 for their lab fee. How much money will she have at the end of the semester if everyone pays their fee? • Students in chemistry are required to write 10 lab reports per year. Each lab report has 6 sections each. Mrs. Borden requires that each section consists of a paragraph with no less than 7 sentences. How many paragraphs will each student write in 1 year time?

  11. Complex Units Many times a problem will ask for you to convert 2 different units in one problem. Example: Change miles per hour to feet per minute. Given 20 miles per hour, how many feet is that per minute? ( 5280 ft = 1 mile) 20 miles 5280 ft. 1 hour = 1760 ft./min. 1 hour 60 min. 1 mile

  12. YOU TRY IT • The density of gold is 19.3 g/mL. What is gold’s density in decigrams per liter?

  13. NEW UNITS • These are units you have never used but you must know for the rest of the year. 1 mole of any element or compound = its mass 1 mole of any element or compound = 6.02 x 1023 representative particles

  14. CONVERSION FACTORS • 1 mole of NaCl = mass of NaCl How to calculate mass, using the periodic table: Na = 23.0 g and Cl = 35.5 g 23.0 + 35.5 therefore 1 mole of NaCl = 58.5 g 58.5 g or 1 mole of NaCl 58.5 g

  15. Practice pROBLEM • You are given 3.5 moles of NaCl, how many grams of NaCl do you have? 3.5 moles NaCl 58.5 g NaCl = 204.75 g of NaCl 1 mole NaCl

  16. CONVERSION FACTORS • 1 mole of NaCl = 6.02 x 1023 particles of NaCl Nothing to calculate, the number of particles is the same for every element therefore 1 mole of NaCl = 6.02 x 1023Particles or 1 mole of NaCl 6.20 x 1023 particles

  17. Practice pROBLEM • You are given 3.5 moles of NaCl, how many particles of NaCl do you have? 6.20 x 1023 particles of NaCl 3.5 moles NaCl = 21.07 x 1023 particles of NaCl or 2.107 x 1024 particles 1 mole NaCl

  18. Multi-Step Problems • You are given 4.55 x 1025 particles of oxygen, how many grams of oxygen do you have? 4.55 x 1025 rp of O 1 mole of O 16.0 g of O = 12.09 x 102grams of O or 1.209 x 103 grams of O 6.02 x 1023 rp 1 mole of O

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