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Rate-Time-Distance Problem

In this problem, two jets leave Denver at 9:00 A.M., one flying east and the other west. The eastern jet flies at a speed 50 km/h greater than the western jet. By 11:00 A.M., they are found to be 2500 km apart. To solve for their speeds, we define the speed of the westbound jet as "r," making the eastbound jet's speed "50 + r." After establishing a chart and forming equations based on their travel times, we derive their speeds as 600 km/h (west) and 650 km/h (east). The calculations confirm the distance apart after 2 hours.

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Rate-Time-Distance Problem

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  1. Rate-Time-Distance Problem By M. L. 8-23

  2. 5. • Two jets leave Denver at 9:00 A.M., one flying east at a speed 50 km/h greater than the other, which is traveling west. At 11:00 A.M. the planes are 2500 km apart. Find their speeds.

  3. Step 1 • Identify what the problem is asking you to find. • It is asking you to find the speed of each plane.

  4. Step 2 • Let r =the speed of the plane flying west. Then the plane flying east’s speed will be 50+r. Make a chart. Notice that the time for both planes will be 2h because there is a 2 hour difference between 9 and 11.

  5. Step 3 • Take the information from the chart to create an equation. • 2(50+r) + 2r = 2500

  6. Step 4 • Now solve the equation. • 2(50+r) + 2r = 2500 • 100 + 2r + 2r = 2500 • 100 + 4r = 2500 • 4r = 2400 • r = 600 west speed • 50 + r = 650 east speed

  7. Step 5 • Check: In 2h the plane traveling west will travel 600 X 2 = 1200 km and the plane traveling east will travel 650 X 2 = 1300 km. • 1200 + 1300 = 2500 km • The plane traveling east traveled at 650 km/h and the one traveling west traveled at 600 km/h .

  8. The End

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