1 / 4

Higher Chemistry

Higher Chemistry. Unit 3 Section 2 Hess’s Law Multiple Choice Questions. This is designed to be used by teachers to help students develop skills in answering multiple choice questions. Douglas Racey, Waid Academy, Anstruther, Fife, Scotland.

Télécharger la présentation

Higher Chemistry

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Higher Chemistry Unit 3Section 2 Hess’s LawMultiple Choice Questions This is designed to be used by teachers to help students develop skills in answering multiple choice questions. Douglas Racey, Waid Academy, Anstruther, Fife, Scotland

  2. Higher Chemistry Unit 3 - Section 2 Hess’s LawMultiple Choice Questions 1. What is the relationship between enthalpies p, q, r and s? S(s) + H2(g)  H2S(g) DH=p H2(g) + ½ O2(g)  H2O(l) DH=q S(s) + O2(g)  SO2(g) DH=r H2S(g) + 1½ O2(g)  H2O(l) + SO2(g) DH=s A. p = q + r – s B. p = s – q – r C. p = q – r – s D. p = s + r – q A. Answer

  3. Higher Chemistry Unit 3 - Section 2 Hess’s LawMultiple Choice Questions 2. The enthalpies of combustion of C(s), H2(g) and C4H9OH(l) (in kJmol-1) are as follows C(s) + O2(g)  CO2(g) DH=a H2(g) + ½O2(g)  H2O(l) DH=b C4H9OH(l) + 6O2(g)  4CO2(g) + 5H2O(l) DH=c What is the enthalpy change for the reaction shown below? 4C(g) + 5H2(l) + ½O2(g)  C4H9OH(l) A. c – 4a – 5b B. 2a + 10b - c C. 4a + 5b - c D. 2a + 5b + c C. Answer

  4. Higher Chemistry Unit 3 - Section 2 Hess’s LawMultiple Choice Questions 3. Consider the reaction pathway shown. DH = -210 kJmol-1 W Z D= -50 kJmol-1 DH = -86kJmol-1 X Y According to Hess’ Law, the DH value, in kJmol-1 for reaction Z to Y is A. +74 B. -74 C. +346 D.-346 C. Answer

More Related