html5-img
1 / 7

Adding Vectors

Adding Vectors. Example of adding two vectors neither at right angles to one another nor on an x or y axis. The Process:. First draw the vectors on an x:y axis, showing them attached head to tail. Second, determine the x and y components of V1. Third, determine the x and y components of V2.

benjamin
Télécharger la présentation

Adding Vectors

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Adding Vectors Example of adding two vectors neither at right angles to one another nor on an x or y axis.

  2. The Process: • First draw the vectors on an x:y axis, showing them attached head to tail. • Second, determine the x and y components of V1. • Third, determine the x and y components of V2. • Fourth, Add the x components of the vectors together. • Fifth, Add the y components of the vectors together. • Sixth, Use the sum of the x components as the x component of the resultant vector; Use the sum of the y components as the y component of the resultant vector. • Seventh, proceed to “add” the resultant’s x and y values.

  3. The Problem:

  4. Resolve the 1st vector into its x and y components. V1y = V1 * Sin 60 or V1 * Cos 30 = 0.866 Km, N V1x = V1 * Cos 60 or V1 * Sin 30 = 0.5 km, E

  5. Resolve the 2nd vector into its x and y components. V2y = V2 * Sin 30 or V2 * Cos 60 = 1 Km, N V2x = V2 * Cos 30 or V2 * Sin 60 = 1.732 Km, E

  6. Next, add the components. V1y + V2y = 0.866 Km + 1.000 Km = 1.866 Km, N V1x + V2x = 0.500 Km + 1.732 Km = 2.232 Km, E

  7. Determine the resultant: 1st use c^2 = a^2 + b^2 c = (a^2 + b^2)^(1/2) c = [(1.866 km)^2 + (2.232 km)^2]^(1/2) So c = 2.909 km 2nd use Angle = Inv Tan (Ry / Rx) = Inv Tan (1.886 km / 2.232 km) = 39.9 degrees; The direction is N of E. So R (the resultant) is equal to 2.909 Km, 39.9 deg N of E or 2.909 Km, 50.1 deg from N, or E of N

More Related