1 / 9

Chapter 3: Equilibrium of a Particle

Chapter 3: Equilibrium of a Particle. Example 3.1. The sphere has a mass of 6kg and is supported. Draw a free-body diagram of the sphere, the cord CE and the knot at C. Example 3.1. F CE. Cord CE. F EC. F CE. W = 58.9N. F CBA. F CD. F CE. Example 3.4.

blaze-winters
Télécharger la présentation

Chapter 3: Equilibrium of a Particle

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 3: Equilibrium of a Particle

  2. Example 3.1 The sphere has a mass of 6kg and is supported. Draw a free-body diagram of the sphere, the cord CE and the knot at C.

  3. Example 3.1 FCE Cord CE FEC FCE W = 58.9N FCBA FCD FCE

  4. Example 3.4 Determine the required length of the cord AC so that the 8kg lamp is suspended. The undeformed length of the spring AB is l’AB = 0.4m, and the spring has a stiffness of kAB = 300N/m.

  5. Example 3.4 TAC = 157N 30° FAB = 136N W = 78.5N +→ ∑Fx= 0; TAB – TACcos30° = 0 +↑ ∑Fy= 0; TABsin30° – 78.5N = 0 TAC = 157.0kN TAB = 136.0kN

  6. Example 3.8 The 100kg crate is supported by three cords, one of which is connected to a spring. Determine the tension in cords AC and AD and stretch of the spring.

  7. Example 3.8 z y x FD FC A 0.333FD FB FC cos120° W = 981N FB ∑Fx = 0; FB+ FCcos120°- 0.333FD = 0

  8. Example 3.8 z y x FD FC A FB FC cos135° 0.667FD W = 981N ∑Fy= 0; FCcos135°+ 0.667FD = 0

  9. Example 3.8 z y x FD FC A 0.667FD FC cos60° FB W = 981N 981 ∑Fz= 0; FCcos60° + 0.667FD- 981 = 0

More Related