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X- + H 3 O + HX + H 2 O

X- + H 3 O + HX + H 2 O. Add strong acid. Use Ka, [HX] & to calculate [H + ]. Recalculate [HX] & [X - ]. Buffer HX & X -. pH. Add strong base. HX + OH-  X- + H 2 O. Equilibrium calculation Use Henderson-Hasselbalch. Stoichiometric calculation.

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X- + H 3 O + HX + H 2 O

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  1. X- + H3O+HX + H2O Add strong acid Use Ka, [HX] & to calculate [H+] Recalculate [HX] & [X-] Buffer HX & X- pH Add strong base HX + OH-  X- + H2O Equilibrium calculation Use Henderson-Hasselbalch Stoichiometric calculation

  2. A buffer is made by adding 0.300 mol HC2H3O2 and 0.300 mol NaC2H3O2 to enough H2O to make 1.00 L of solution. The pH of the buffer is 4.74 • Calculate the pH of this solution after 0.020 mol NaOH is added • For comparison, calculate the pH that would result if 0.020 mol of NaOH was added to 1.00 L of pure H2O, neglecting volume changes

  3. Determine the pH of the original buffer described in previous example after the addition of 0.020 mol HCl

  4. Acid-Base Titrations • Switch to handout

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