1 / 11

3. Counting

3. Counting. Permutations Combinations Pigeonhole principle Elements of Probability Recurrence Relations. Permutations.

bron
Télécharger la présentation

3. Counting

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. 3. Counting Permutations Combinations Pigeonhole principle Elements of Probability Recurrence Relations

  2. Permutations Theorem 1. Suppose that two tasks T1 and T2 are to be performed in sequence. If T1 can be performed in n1 ways, and for each of these ways T2 can be performed in n2 ways, then the sequence T1T2 can be performed in n1n2 ways. • Theorem 1 is sometimes called the multiplication principle of counting. Theorem 2. Suppose that tasks T1, T2,…,Tk are to be performed in sequence. If T1 can be performed in n1 ways, and for each of these ways T2 can be performed in n2 ways, and for each of these n1n2 ways of performing T1T2 in sequence, T3 can be performed in n3 ways, and so on, then the sequence T1T2 … Tk can be performed in exactly n1n2…nk ways.

  3. Permutations Problem 1. How many different sequences, each of length r, can be formed using elements from a set A if • elements in the sequence may be repeated? • all elements in the sequence must be distinct? • A sequence of r distinct elements of A is called a permutation of n objects taken r at a time, with |A|=n • When r=n, the sequence is called a permutation of A, i.e. a distinct arrangement of the elements of a set A, with |A|=n, into sequence of length n

  4. Permutations Theorem 3. Let A be a set with n elements and 1rn. Then the number of sequences of length r that can be formed from elements of A, allowing repetition, is nr. Theorem 4. If 1rn, then nPr, the number of permutations of n objects taken r (distinct elements) at a time, is n·(n-1)· ··· ·(n-r+1)=n!/(n-r)! Theorem 5. The number of distinguishable permutations that can be formed from a collection of n objects where the first object appears k1times, the second objects k2 times, and so on, is n! k1!k2! ···kt!

  5. Combinations Problem 2. Let A be any set with n elements and 1rn. How many different subsets of A are there, each with r elements. • the traditional name for an r-element subsets of an n-element set A is a combination of A, taken r at a time, where order does not matter Theorem 1. Let A be a set with |A|=n, and let 1rn. Then the number of combinations of the elements of A, taken r at a time, that is the number of r-element subsets of A is n! r!(n-r)! • nCr = n!/r!(n-r)!, number of combinations of n objects taken r at a time.

  6. Combinations Theorem 2. Suppose k selections are to be made from n items without regards to order and that repeats are allowed, assuming at least k copies of each of the n items. The number of ways these selections can be made is (n+k-1)Ck. • In general, when order matters, we count the number of sequences or permutations; when order does not matter, we count the number of subsets or combinations

  7. Pigeonhole Principle • The Pigeonhole Principle If n pigeons are assigned to m pigeonholes, and m<n, then at least one pigeonhole contains two or more pigeons. • The principle provides an existence proof • The Extended pigeonhole Principle If n pigeons are assigned to m pigeonholes, then one of the pigeonholes must contain at least (n-1)/m +1 pigeons.

  8. Elements of Probability • Probabilistic experiments: do not yield exactly the same results when performed repeatedly • Deterministic experiments: whose outcome is always the same • sample space A, a set consisting of all the outcomes of an experiment • event E: a set of outcomes that satisfy some description • certain event A, impossible event  • new events can be formed from events E and F: EF occurs exactly when E or F occurs EF occurs if and only if both E and F occur E occurs if and only if E does not occur • events E and F are mutually exclusive or disjoint if EF={}, i.e. E and F cannot both occur at the same time • E1,E2,…,Ek are mutually exclusive or disjoint if at most one of the events can occur on any given outcome of the experiment

  9. Assigning Probabilities to Events • If event E has occurred nE times after n performances of the experiment, the fraction fE= nE/n is the frequency of occurrence of E in n trials • p(E), the probability of the event E, i.e. fE will tend to be p(E) when n becomes larger: the frequencies of occurrence of event E • Rules for assigning probabilities: P1: 0 p(E) 1 for every event E in A P2: p(A)=1 and p()=0 P3: p(E1E2… Ek)=p(E1)+p(E2)+… +p(Ek) whenever the events are mutually exclusive • If the probabilities are assigned to all events in such a way that P1, P2, P3 are always satisfied, then we have a probability space, and P1, P2, and P3 are called the axioms for a probability space.

  10. Assigning Probabilities to Events • Let A be a probability space and is finite, A={x1, x2, … , xm}, then each event {xk}, consisting of just one outcome, is called an elementary event • elementary probability corresponding to the outcome xk is pk=p({xk}). • elementary events are mutually exclusive • axioms of probability for elementary events: EP1: 0 pk1 for all k EP2: p1+p2+… +pn=1 • If E is any event in A, and E={xi1, xi2, … , xim}, then E={xi1} {xi2} … {xim} and p(E)=pi1+pi2+… +pim

  11. Equally Likely Outcomes • Assume that all outcomes in a sample space A are equally likely to occur: each has the same probability • random selection is to choose an object at random if all objects have an equal probability of being chosen • suppose |A|=n and these n outcomes are equally likely, then each elementary probability is 1/n, and for every event E, p(E)=|E|/|A| • The expected value of an experiment is the sum of the value of each outcome times its probability • Roughly speaking, the expected value describes the ‘average’ value for a large number of trials • Useful in analyzing the efficiency of algorithms, e.g. expected number of steps that the algorithm execute on an ‘average’ run to give the output

More Related