1 / 23

Section1.4 QUADRATIC EQUATIONS

Section1.4 QUADRATIC EQUATIONS This presentation is base on Power Point slides found at http://cwx.prenhall.com/bookbind/pubbooks/sullivan13/ with modifications by Jeffrey Linek Ed. D. Quadratic Equations. We can solve quadratic equations Graphically Algebraically by factoring

cai
Télécharger la présentation

Section1.4 QUADRATIC EQUATIONS

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. Section1.4 QUADRATIC EQUATIONS This presentation is base on Power Point slides found at http://cwx.prenhall.com/bookbind/pubbooks/sullivan13/ with modifications by Jeffrey Linek Ed. D.

  2. Quadratic Equations • We can solve quadratic equations • Graphically • Algebraically by factoring • Using the Completing the Square Method • Extracting a Zero or Root • Using the Quadratic Formula

  3. Factoring Solution Set:

  4. 2 ( ) x + 2 = 25 Solve: Extracting the Roots Solution set: {-7, 3}

  5. Solve by completing the square:

  6. Theorem Quadratic Formula

  7. Discriminant of a Quadratic Equation

  8. Two Real Roots

  9. Quadratic Equations Solve the following equation graphically. x2 - 4 = x + 6

  10. Solve the following equation graphically.x2 - 4 = x + 6 On the TI-83 press the Y= key and enter the equations Y1 = x2 - 4 and Y2 = x + 6

  11. Solve the following equation graphically.x2 - 4 = x + 6 Press the GRAPH key. The points of intersection are the solutions to the problem. We will use the intersect feature to find their values.

  12. Solve the following equation graphically.x2 - 4 = x + 6TI-83: The Intersect Feature Press the 2ndkey, then the TRACE key Select 5: intersect Then, press the ENTER key

  13. Solve the following equation graphically.x2 - 4 = x + 6TI-83: The Intersect Feature • The graph of the two equations will be displayed. The TI-83 will ask if the cursor is on the first graph. Press the ENTER key. • Next, the TI-83 will ask if the cursor is on the second graph. Press the ENTER key.

  14. Solve the following equation graphically.x2 - 4 = x + 6TI-83: The Intersect Feature Notice that the calculator asks you to guess at the answer, and that the cursor is midway between the two points of intersection. We will just press the ENTER key to see what happens.

  15. Solve the following equation graphically.x2 - 4 = x + 6TI-83: The Intersect Feature • Notice that the TI-83 solved for one of the points of intersection, namely, (-2.702, 3.298). We need to find the other point as well.

  16. Solve the following equation graphically.x2 - 4 = x + 6TI-83: The Intersect Feature • As we did earlier press the 2ndKey, the Trace Key, then the number 5 Key for 5: intersect. • Once again the calculator will ask if the cursor is on the first graph. This time, use the key to move the cursor closed to the point of intersection. Then, press the ENTER key >

  17. Solve the following equation graphically.x2 - 4 = x + 6TI-83: The Intersect Feature The TI-83 will ask if the cursor is on the second graph. Press the ENTER key.

  18. Solve the following equation graphically.x2 - 4 = x + 6TI-83: The Intersect Feature The calculator asks you to guess at the answer. We will just press the ENTER key to get the answer.

  19. Solve the following equation graphically.x2 - 4 = x + 6TI-83: The Intersect Feature The answer (3.702, 9.702) appears. However, we need to interpret the answer because our original equation did not contain y.

  20. Solve the following equation graphically.x2 - 4 = x + 6The answers. Remember that original we set Y1 = x2 - 4 and Y2 = x + 6. Therefore, Y1 = Y2 since, x2 - 4 = x + 6 Y1 and Y2 are result of placing a value for x into the equation x2 - 4 = x + 6 So, our answers are x = -2.702 or x = 3.702

  21. Now, solve the equation algebraically x2 - 4 = x + 6

More Related