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Question 49

Question 49.

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Question 49

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  1. Question 49 • The combustion of .1584g benzoic acid increases the temperature of a bomb calorimeter by 2.54°C.Calculate the heat capacity of this calorimeter. (The energy released by combustion of benzoic acid is 26.42 kJ/g.) A .2130-g sample of vanillin (C8H8O3) is then burned in the same calorimeter, and the temperature increases by 3.25°C. What is the energy of combustion per gram of vanillin? Per mole of vanillin?

  2. To find the kJ of .1584g: 26.42kJ/g x .1584g = 4.18kJ/.1584g Next divide by the change in temp.: 4.18kJ / 2.54°C = 1.65kJ/°C Therefore, the heat capacity of the calorimeter is 1.65kJ/°C

  3. Use the equation: ΔT x heat capacity of calorimeter = Energy released by reaction. 3.25°C x 1.65kJ/°C = 5.3625kJ Then divide by the number of grams to find kJ/g: 5.3625kJ/.2130g = 25.18kJ/g

  4. Next multiply by the molar mass to find the kJ/mol: 25.18kJ/g x 152g/mol = 3830kJ/mol

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