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Aplicatie vectori

Aplicatie vectori. Maximul dintr-un vector. Problema. Se citesc de la tastatura notele a n elevi la un extemporal. Se cere sa se gaseasca nota maxima atinsa la extemporal precum si numarul elevilor care au atins aceasta nota. Analiza datelor. Date de intrare:

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Aplicatie vectori

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  1. Aplicatie vectori Maximul dintr-un vector

  2. Problema • Se citesc de la tastatura notele a n elevi la un extemporal. Se cere sa se gaseasca nota maxima atinsa la extemporal precum si numarul elevilor care au atins aceasta nota

  3. Analiza datelor • Date de intrare: n, numar natural => numarul elevilor v, vector de dimensiune n => cele n note • Date de iesire: max, numar natural => nota maxima k, numar natural => numarul de elevi care au atins nota max

  4. Un exemplu • N=20 • V=(6,8,9,5,9,5,7,10,7,5,8,10,8,10,7,9,10,9,8,4)

  5. Un exemplu • N=20 • V=(6,8,9,5,9,5,7,10,7,5,8,10,8,10,7,9,10,9,8,4) • Rezolvare: • Pasul 1.: cautare element maxim: max=10

  6. Un exemplu • N=20 • V=(6,8,9,5,9,5,7,10,7,5,8,10,8,10,7,9,10,9,8,4) • Rezolvare: • Pasul 1.: cautare element maxim: max=10 • Pasul 2.: numarare aparitii element maxim: k=3

  7. Un exemplu • N=20 • V=(6,8,9,5,9,5,7,10,7,5,8,10,8,10,7,9,10,9,8,4) • Rezolvare: • Pasul 1.: cautare element maxim: max=10 • Pasul 2.: numarare aparitii element maxim: k=3 • Pasul 3.: afisare rezultat: Nota maxima este 10 si a fost atinsa de 3 elevi

  8. Elaborare algoritm • Algoritmul in limbajul Pascal Program extemporal; Type vector=array[1..50] of byte; Var v:vector; n,I,max,k:byte; Begin write(‘Dati numarul de elevi: ‘); read(n); for i:=1 to n do begin write(‘nota elevului cu nr ‘,I,’ : ‘); read(v[i]); end; max:=v[1]; for i:=2 to n do if v[i]>max then max:=v[i]; k:=0; for i:=1 to n do if v[i]=max then k:=k+1; write(\Nota maxima este ‘,max,’ si a fost atinsa de ‘,k,’elevi’); end

  9. Problema • Se citesc n numere intregi. Sa se afiseze cel mai mare numar obtinutdin prima cifra a fiecarui numar

  10. Analiza datelor • Date de intrare: n, numar natural => numarul de numere de n ori cate un a => cele n numere • Date de iesire: nr => numarul maxim care se poate forma • Date de manevra> d, vectorul care contine prima cifra a fiecarui numar citit

  11. Algoritmul problemei • var d:array[1..20] of byte; • a,i,c,aux,j,nr,n:longint; • begin • write('dati nr de nr');readln(n); • writeln('Dati elem: '); • for i:=1 to n do • begin • readln(a); • aux:=a; • while aux<>0 do begin • c:=aux mod 10; • aux:=aux div 10; end; • d[i]:=c end; • for i:=1 to n-1 do • for j:=i+1 to n do • if d[i]<d[j] then begin • aux:=d[i]; • d[i]:=d[j]; • d[j]:=aux end; • for i:=1 to n do nr:=nr*10+d[i]; • writeln('Cel mai mare nr este: ',nr); • readln • end.

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