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Trusses

Trusses. WORKSHEET10. to answer just click on the button or image related to the answer. let's go !!. what is a truss?. a triangular arrangement of members with rigid joints. a triangular arrangement of members with pinned joints. a beam with holes. same as a frame. a. b. d. c.

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Trusses

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  1. Trusses WORKSHEET10 to answer just click on the button or image related to the answer let's go !!

  2. what is a truss? a triangular arrangement of members with rigid joints a triangular arrangement of members with pinned joints a beam with holes same as a frame a b d c Question 1

  3. which members resist the bending moments? top chords a & b bottom chords c & d a & c vertical web members diagonal web members b & d d g a h e b c f Question 2a in a parallel chord truss

  4. which members resist the shear forces? top chords a & b bottom chords c & d a & c vertical web members diagonal web members b & d d g a h e b c f Question 2b in a parallel chord truss

  5. which members resist the compressive forces from the bending moment? top chords bottom chords middle top chords middle bottom chords a b d c Question 2c in a parallel chord truss

  6. where does the maximum compressive force from bending occur? at a (middle bottom chords) at b (middle top chords) at c (end diagonal web members) at d (vertical web members) a b d c Question 2d b c d in the parallel chord truss shown a

  7. at a (middle bottom chords) at b (middle top chords) at c (end diagonal web members) at d (vertical web members) a b d c Question 2e b c d in the parallel chord truss shown a where does the maximum tensile force from bending occur?

  8. at a (middle bottom chords) at b (middle top chords) at c (end diagonal web members) at d (vertical web members) a b d c Question 2f b c d in the parallel chord truss shown a where does the maximum shear force occur?

  9. where does the maximum compressive force from bending occur? at a (end top chords) at b (end bottom chords) at c (middle diagonal web members) at d (middle vertical web members) a b d c Question 3a d a in the triangular truss shown b c

  10. where does the maximum tensile force from bending occur? at a (end top chords) at b (end bottom chords) at c (middle diagonal web members) at d (middle vertical web members) a b d c Question 3b d a in the triangular truss shown b c

  11. where does the maximum shear force occur? at a (end top chords) at b (end bottom chords) at c (middle diagonal web members) at d (middle vertical web members) a b d c Question 3c d a in the triangular truss shown b c

  12. H 45o V 10.0 kN 14.1 kN 10kN 7.1 kN a b c Question 4a given the force shown what is the force in the horizontal component, H?

  13. 45o 10.0 kN 14.1 kN 10kN 7.1 kN a b c Question 4b H given the force shown what is the force in the vertical component, V? V

  14. V 6kN 30o H 12.0 kN 5.2 kN 7.1 kN a b c Question 5a given the force shown what is the force in the horizontal component, H?

  15. V 6kN 30o H 8.0 kN 3.0 kN 12.0 kN a b c Question 5b given the force shown what is the force in the vertical component, V?

  16. 6kN what is the resultant force? 10 kN at 45.00 to the horizontal 8kN 7 kN at 45.00 to the horizontal 10 kN at 36.870 to the horizontal a b c Question 6 given the forces shown use the parallelogram of forces or the triangle of forces

  17. when would we use the method of sections? to find the forces in all the members to find the force in only certain members because it’s the easiest a b c Question 7 when analysing a truss

  18. 4 bays @ 3m 2kN 2kN 2kN 1kN 1kN B C E 45o what do we do first? A D F make a cut through CE take moments 3m find the reactions b a c Question 8a using the Methods of Sections to find the value of the force in the member CE

  19. 4 bays @ 3m 2kN 2kN 2kN 1kN 1kN B C E 45o A D F RL = 8 kN RR = 8 kN what are the reactions? RL = 4 kN RR = 4 kN 3m RL = 8 kN RR = 4 kN b a c Question 8b using the Methods of Sections to find the value of the force in the member CE RR RL

  20. 4 bays @ 3m 2kN 2kN 2kN 1kN 1kN B C E 45o what do we do next? A D F make a cut through CE take moments 3m make a freebody b a c Question 8c using the Methods of Sections to find the value of the force in the member CE once we have the reactions RR = 4kN RL= 4kN

  21. 2kN 1kN B C E 2kN 1kN 3m A D F what do we do next? add in all the forces 4 kN 3m 3m use the equations of static equilibrium take moments b a c Question 8d using the Methods of Sections to find the value of the force in the member CE once we have made the cut

  22. 2kN 1kN B C E 2kN 1kN 3m A D F what do we do next? eliminate some of the unknowns 4 kN 3m 3m use the equations of static equilibrium take moments b a c Question 8e using the Methods of Sections to find the value of the force in the member CE once we have added in forces CE, CF and DF

  23. 2kN 1kN B C E 2kN 1kN 3m A D F ΣV = 0 4 kN 3m 3m ΣH = 0 ΣM = 0 b a c Question 8f using the Methods of Sections to find the value of the force in the member CE given ΣV = 0, ΣH = 0, ΣM = 0 which equation is the most useful here?

  24. 2kN 1kN B C E 2kN 1kN 3m A D F we will take moments about a point 4 kN 3m 3m we will calculate clockwise moments we will calculate anticlockwise moments b a c Question 8g using the Methods of Sections to find the value of the force in the member CE given that we will use ΣM = 0 what does that mean?

  25. 2kN 1kN B C E 2kN 1kN 3m A D F F A 4 kN 3m 3m D C b a d c Question 8h using the Methods of Sections to find the value of the force in the member CE given that we will take moments about a point about which point?

  26. 2kN 1kN B C E 2kN 1kN 3m A D F eliminates the forces CF and DF seems right 4 kN 3m 3m it is perpendicular to CE b a c Question 8i using the Methods of Sections to find the value of the force in the member CE why do we take moments about F?

  27. 2kN 1kN B C E 2kN 1kN 3m A D F 12 kN compression 12 kN tension 4 kN compression 4 kN 3m 3m 4 kN tension what is the value of the force in CE? b a d c Question 8j using the Methods of Sections to find the value of the force in the member CE

  28. 2kN 1kN B C E 2kN 1kN 3m A D F A E 4 kN 3m 3m C D where would we take moments? a b d c Question 8k using the Methods of Sections to find the value of the force in the member DF

  29. enough ! next question a Great Start a truss is a linear arrangement of short members, arranged to form triangles. The joints are pinned and the loads should be placed at the joints so that the members are only in tension or compression.

  30. let me try again let me out of here What! rigid joints make a frame not a truss

  31. let me try again let me out of here Sorry in some way you can think of trusses as beams with holes, i.e. the chords are the flanges and the web members are similar but trusses have specific arrangements to avoid bending moments.

  32. let me try again let me out of here What! trusses do not behave like frames frames have rigid joints trusses avoid bending moments

  33. enough ! next question you've got it it!! the chords (all of them) resist the bending moments

  34. let me try again let me out of here Nearly ! partly right

  35. let me try again let me out of here Oh! Oh! the web members DO NOT resist the Bending Moments

  36. enough ! next question you've got it it!! the web members (all of them) resist the shear forces

  37. let me try again let me out of here Oh! Oh! the chords resist the Bending Moments NOT the Shear Forces

  38. let me try again let me out of here Nearly ! partly right

  39. enough ! next question you've got it it!! the top chords (all of them) resist the compressive forces from the bending moment – just as the top part of a beam

  40. let me try again let me out of here Oh! Oh! think of a beam under bending

  41. let me try again let me out of here Not quite ! partly right

  42. enough ! next question you've got it it!! the top chords resist the compressive forces from the bending moment but the maximum forces occur in the middle (as in a simply supported beam)

  43. let me try again let me out of here a devil of an answer !! didn’t we say that it is the top chords that resist the compressive forces

  44. let me try again let me out of here a devil of an answer !! didn’t we say that it is the top chords that resist the compressive forces the web members do not resist the bending forces

  45. enough ! next question you've got it it!! the bottom chords resist the tensile forces from the bending moment but the maximum forces occur in the middle (as in a simply supported beam)

  46. let me try again let me out of here a devil of an answer !! didn’t we say that the top chords resist the compressive forces

  47. let me try again let me out of here a devil of an answer !! didn’t we say that the web members do not resist the bending forces

  48. enough ! next question you've got it it!! the web members resist the shear forces but the maximum forces occur at the end (as in a simply supported beam with a UDL)

  49. let me try again let me out of here a devil of an answer !! didn’t we say that the chords resist the forces from the bending moment and that it is the web members which resist the shear forces

  50. let me try again let me out of here possibly ! the maximum shear forces do occur at the ends just like in a simply supported beam with a UDL but not usually in the vertical members

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