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This document explores fundamental graph algorithms, particularly Breadth-First Search (BFS) and Dijkstra’s algorithm for computing shortest paths. BFS operates layer by layer to determine the distance from a starting node to all other nodes in an undirected graph, ensuring efficient traversal. Dijkstra's algorithm enhances this by managing edge weights, employing priority queues for optimized performance. The analysis also discusses implementing these algorithms, addressing complexities and comparisons between Depth-First Search (DFS) and BFS.
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NatteeNiparnan Graph Algorithm:Breadth First Search
Distance of nodes • The distance between two nodes is the length of the shortest path between them SA 1 SC 1 SB 2
DFS and Length • DFS finds all nodes reachable from the starting node • But it might not be “visited” according to the distance
Ball and Strings We can compute distance by proceeding from “layer” to “layer”
Shortest Path Problem (Undi, Unit) • Input: • A graph, undirected • A starting node S • Output: • A label on every node, giving the distance from S to that node
Breadth-First-Search • Visit node according to its layer procedure bfs(G; s) //Input: Graph G = (V,E), directed or undirected; vertex s V //Output: visit[u] is set to true for all nodes u reachable from v for all u V : visit[u] = false visit[s] = true Queue Q = [s] (queue containing just s) while Q is not empty: u = eject(Q) previsit(u) visit[u] = true; for all edges (u,v) E: if visit[v] = false: visit[v] = true; inject(Q,v); postvisit(u)
Distance using BFS procedure shortest_bfs(G, s) //Input: Graph G = (V,E), directed or undirected; vertex s V //Output: For all vertices u reachable from s, dist(u) is set to the distance from s to u. for all u V : dist[u] = -1 dist[s] = 0 Queue Q = [s] (queue containing just s) while Q is not empty: u = eject(Q); for all edges (u,v) E: if dist[v] = -1: inject(Q,v); dist[v] = dist[u] + 1; Use dist as visit
DFS by Stack procedure dfs(G, s) //Input: Graph G = (V,E), directed or undirected; vertex s V //Output: visit[u] is set to true for all nodes u reachable from v for all u V : visit[u] = false visit[s] = true Stack S = [s] (queue containing just s) while S is not empty: u = pop(S) previsit(u) for all edges (u,v) E: if visit [v] = false: push(S,v) visit[v] = true; postvisit(u)
DFS vs BFS • DFS goes depth first • Trying to go further if possible • Backtrack only when no other possible way to go • Using Stack • BFS goes breadth first • Trying to visit node by the distance from the starting node • Using Queue
Graph with Length Dijkstra’s Algorithm
Edge with Length Length function l(a,b) = distance from a to b
Finding Shortest Path • BFS can give us the shortest path • Just convert the length edge into unit edge However, this is very slow Imagine a case when the length is 1,000,000
Alarm Clock Analogy • No need to walk to every node • Since it won’t change anything • We skip to the “actual” node • Set up the clock at alarm at the target node
Alarm Clock Algorithm • Set an alarm clock for node s at time 0. • Repeat until there are no more alarms: • Say the next alarm goes off at time T, for node u. Then: • The distance from s to u is T. • For each neighbor v of u in G: • If there is no alarm yet for v, set one for time T + l(u, v). • If v's alarm is set for later than T + l(u, v), then reset it to this earlier time.
Dijkstra’sAlgo from BFS procedure dijkstra(G, l, s) //Input: Graph G = (V;E), directed or undirected; vertex s V; positive edge lengths l // Output: For all vertices u reachable from s, dist[u] is set to the distance from s to u. for all u V : dist[u] = + prev(u) = nil dist[s] = 0 H = makequeue(V) (using dist-values as keys) while H is not empty: u = deletemin(H) for all edges (u; v) E: if dist[v] > dist[u] + l(u, v): dist[v] = dist[u] + l(u, v) prev[v] = u decreasekey(H, v)
Another Implementation of Dijkstra’s • Growing from Known Region of shortest path • Given a graph and a starting node s • What if we know a shortest path from s to some subset S’ V? • Divide and Conquer Approach?
Dijktra’sAlgo #2 procedure dijkstra(G, l, s) //Input: Graph G = (V;E), directed or undirected; vertex s V; positive edge lengths l // Output: For all vertices u reachable from s, dist[u] is set to the distance from s to u. for all u V : dist[u] = + prev(u) = nil dist[s] = 0 R = {} // (the “known region”) while R ≠ V : Pick the node v R with smallest dist[] Add v to R for all edges (v,z) E: if dist[z] > dist[v] + l(v,z): dist[z] = dist[v] + l(v,z)
Analysis • There are |V|ExtractMin • Need to check all edges • At most |E|, if we use adjacency list • Maybe |V2|, if we use adjacency matrix • Value of dist[] might be changed • Depends on underlying data structure
Choice of DS • Using simple array • Each ExtractMin uses O(V) • Each change of dist[] uses O(1) • Result = O(V2 + E) = O(V2) • Using binary heap • Each ExtractMin uses O(lg V) • Each change of dist[] uses O(lg V) • Result = O( (V + E) lg V) • Can be O (V2 lg V) Might be V2 Good when the graph is sparse
Fibonacci Heap • Using simple array • Each ExtractMin uses O( lg V) (amortized) • Each change of dist[] uses O(1) (amortized) • Result = O(Vlg V + E)
Graph with Negative Edge • Disjktra’s works because a shortest path to v must pass throught a node closer than v • Shortest path to A pass through B which is… in BFS sense… is further than A
Negative Cycle • A graph with a negative cycle has no shortest path • The shortest.. makes no sense.. • Hence, negative edge must be a directed
Key Idea in Shortest Path • Update the distance if dist[z] > dist[v] + l(v,z): dist[z] = dist[v] + l(v,z) • This is safe to perform • now, a shortest path must has at most |V| - 1 edges
Bellman-Ford Algorithm procedure BellmanFord(G, l, s) //Input: Graph G = (V;E), directed; vertex s V; edge lengths l (may be negative), no negative cycle // Output: For all vertices u reachable from s, dist[u] is set to the distance from s to u. for all u V : dist[u] = + prev(u) = nil dist[s] = 0 repeat |V| - 1 times: for all edges (a,b) E: if dist[b] > dist[a] + l(a,b): dist[b] = dist[a] + l(a,b)
Shortest Path in DAG • Path in DAG appears in linearized order procedure dag-shortest-path(G, l, s) //Input: DAG G = (V;E), vertex s V; edge lengths l (may be negative) // Output: For all vertices u reachable from s, dist[u] is set to the distance from s to u. for all u V : dist[u] = + prev(u) = nil dist[s] = 0 Linearize G For each u V , in linearized order: for all edges (u,v) E: if dist[v] > dist[u] + l(u,v): dist[v] = dist[u] + l(y,v)