1 / 9

Chapter 10 NOTES

Chapter 10 NOTES. PRACTICE PROBLEMS. Try it on your own!. A compound is formed when 9.03 g Mg combines completely with 3.48 g N. What is the percent composition of this compound? Known Mass of Mg = 9.03g Mass of N = 3.48 g Total mass of cmpd . = 12.51 g (9.03g + 3.48g) Unknown % Mg = ?

dyllis
Télécharger la présentation

Chapter 10 NOTES

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Chapter 10 NOTES PRACTICE PROBLEMS

  2. Try it on your own! • A compound is formed when 9.03 g Mg combines completely with 3.48 g N. What is the percent composition of this compound? Known • Mass of Mg = 9.03g • Mass of N = 3.48 g • Total mass of cmpd. = 12.51 g (9.03g + 3.48g) Unknown • % Mg = ? • % N = ?

  3. Solve • % Mg = 9.03 g x 100% = 72% 12.51 g • % N = 3.48 g x 100% = 28% 12.51g

  4. Try it on your own! • When a 14.2-g sample of mercury(II) oxide is decomposed into its elements by heating, 13.2 g Hg is obtained. What is the percent composition of the compound? Known • Mass of cmpd = 14.2g • Mass of Hg = 13.2 g • Mass of O = 1.0 g (14.2g – 13.2g) Unknown • % Hg = ? • % O = ?

  5. Solve % Hg = 13.2g x 100% = 93% 14.2g % O = 1.0g x 100% = 7% 14.2g

  6. Try it on your own! • Calculate the percent composition of ethane (C2H6). • Know: mass of C in 1 mol ethane= 2X12=24g • Mass of H in 1 mol ethane=1X6=6g • Unknown: Percent C? • Percent H? • Molar mass= 24g+6g= 30g

  7. Solve • %C= 24g X 100 = 80% 30g %H= 6g X 100= 20% 30g % equals 100!

  8. Try it on your own • Calculate the percent nitrogen in NH₄NO₃ • Know: mass of N in 1 mol NH₄NO₃= 14X2=28g • Know: molar mass NH₄NO₃= (14X2)+(4X1)+(3X16)= 28g • Unknown: percent N?

  9. Solve • % N = 28g X 100 = 35% 80g This is correct because: %H= 4g X100 = 5% 80g %O = 48g X 100= 60% 80g

More Related