1 / 8

Physics Review – Vectors

Physics Review – Vectors. Consider 0 o heading to be East, i.e. along the positive x-axis. An airplane flying from point A to point B travels along the following vectors: 35 o for 300 km 120 o for 100 km 100 o for 400 km

eagan
Télécharger la présentation

Physics Review – Vectors

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Physics Review – Vectors Consider 0o heading to be East, i.e. along the positive x-axis. An airplane flying from point A to point B travels along the following vectors: 35o for 300 km 120o for 100 km 100o for 400 km Determine the heading in degrees and the magnitude of the resultant.

  2. Physics Review – Vectors Consider 0o heading to be East, i.e. along the positive x-axis. An airplane flying from point A to point B travels along the following vectors: 35o for 300 km 120o for 100 km 100o for 400 km Determine the heading in degrees and the magnitude of the resultant. 35o for 300 km 120o for 100 km 100o for 300 km 300 100 300 Draw vectors. Add scale. 300 km 400 km

  3. Physics Review – Vectors 35o for 300 km 120o for 100 km 100o for 300 km 300 Y3 100 X3 Y2 X2 2. Draw the corresponding individual right triangles. Label the vertical & horizontal components. 300 Y1 X1 300 km 400 km

  4. Physics Review – Vectors 35o for 300 km 120o for 100 km 100o for 300 km 300 Y3 (180-100) = 80o 100 X3 Y2 (180-120) = 60o X2 300 Y1 3. Label the angles. 35o X1 300 km 400 km

  5. Physics Review – Vectors 35o for 300 km 120o for 100 km 100o for 300 km 300 Y3 R (180-100) = 80o 100 X3 Y2 (180-120) = 60o YT X2 4. Draw the resultant and its vertical & horizontal components. Label these. 300 Y1 Ө 35o XT X1 300 km 400 km

  6. Physics Review – Vectors 35o for 300 km 120o for 100 km 100o for 300 km • XT = X1 ‒ X2 ‒ X3 • Cos 35o = X1/300 X1 = 246 km • Cos 60o = X2/100 X2 = 50 • Cos 80o = X3/300 X3 = 52 • XT = 246‒ 50‒ 52XT = 144 km YT = Y1 + Y2 + Y3 300 Y3 R (180-100) = 80o 100 X3 5. Define the horizontal & vertical components of the resultant in terms of the components of the individual right triangles. Use trig function to determine the magnitudes of one set of components of the individual right triangles (I used Cos for X- dimensions). Y2 (180-120) = 60o YT X2 300 Y1 Ө 35o XT X1 300 km 400 km

  7. Physics Review – Vectors 35o for 300 km 120o for 100 km 100o for 300 km • XT = X1 ‒ X2 ‒ X3 • Cos 35o = X1/300 X1 = 246 km • Cos 60o = X2/100 X2 = 50 • Cos 80o = X3/300 X3 = 52 • XT = 246‒ 50‒ 52XT = 144 km • YT = Y1 + Y2 + Y3 • 3002 = X12 + Y12 Y1 = 172 • 1002 = X22 + Y22 Y2 = 87 • 3002 = X32 + Y32 Y3 = 295 • YT = 172+87+ 295 YT = 554 km 300 Y3 R (180-100) = 80o 100 X3 6. Use Pythag. Thm. to determine the magnitudes of the other set of components of the individual right triangles (I used this to determine Y- dimensions). Y2 (180-120) = 60o YT X2 300 Y1 Ө 35o XT X1 300 km 400 km

  8. Physics Review – Vectors 35o for 300 km 120o for 100 km 100o for 300 km • XT = X1 ‒ X2 ‒ X3 • Cos 35o = X1/300 X1 = 246 km • Cos 60o = X2/100 X2 = 50 • Cos 80o = X3/300 X3 = 52 • XT = 246‒ 50‒ 52XT = 144 km • YT = Y1 + Y2 + Y3 • 3002 = X12 + Y12 Y1 = 172 • 1002 = X22 + Y22 Y2 = 87 • 3002 = X32 + Y32 Y3 = 295 • YT = 172+87+ 295 YT = 554 km 300 Y3 R (180-100) = 80o 100 X3 R2 = XT2+ YT2 R = 572 km Tan Ө = YT / XT Ө = tan‒1 (YT / XT) Ө = 75o Y2 (180-120) = 60o YT X2 300 Y1 Ө 35o 7. Use Pythag. Thm. to determine the magnitude of the resultant. Use inverse trig function to determine Ө. XT X1 300 km 400 km

More Related