1 / 29

The Mole a Review

The Mole a Review. CFISD Chemistry EOC Prep. Terms to describe more than one of something…. 1 Dozen = 12 of something. More terms to describe more than one of something…. 1 Stone= 14 pounds (140 lbs =10 stones). 1 ream = 500 sheets of paper. 1 cubic yard (y 3 ) = 27 ft 3 of stuff.

edana
Télécharger la présentation

The Mole a Review

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. The Mole a Review CFISD Chemistry EOC Prep

  2. Terms to describe more than one of something… 1 Dozen = 12 of something

  3. More terms to describe more than one of something… 1 Stone= 14 pounds (140 lbs =10 stones) 1 ream = 500 sheets of paper 1 cubic yard (y3) = 27 ft3 of stuff 1 yard

  4. Science prefixes to describe more than one of something… • 1 Liter = 1000 mL • 1 gram = 1000 mg • 1 m = 100 cm Liters grams moles meters seconds

  5. In chemistry, the most important term used to describe more than one of something and/or how much matter we have is the….. Mole

  6. What’s a Mole? 1 mole = 6.02 X 10 23 particles Formula Units Ions Atoms Molecules 6.02 x 1023 particles

  7. What is an atom? Smallest particle of an element that maintains the identity (#protons) of that element. C Carbon-12 C C 12 6 1s22s22p2 or [He]2s22p2

  8. What is a molecule? particles that contain one or more covalently bonded (nonmetal) atoms. CO2 molecule H H O=C=O Hydrogen molecule (diatomic)

  9. What is a formula unit? • the lowest ratio of cations (metals) to anions (nonmetals) in a neutral compound. NaCl

  10. What is an ion? BaCl2 1 Ba+2 + 2 Cl-1 • formed when an atom gains or loses an electron(s) • anion (-) cation (+) polyatomic ion ( + or -) • combine to form ionic compounds (metals and nonmetals) Formula Units Ba3(PO4)2 3 Ba+2 + 2 PO4-3

  11. Let’s Practice: • Name each substance and identify the types of particle present in the sample by placing an X in the corresponding box. • Pause the presentation to give yourself time to work prior to moving on.

  12. Check your answers:

  13. How can we determine how many moles of matter we have in a sample of matter? We know… • particles are too small to be counted by hand…. • we can measure mass and volume……. • the relationships between moles and mass an moles and volume. 6.02 x 1023 particles

  14. Molar Mass: mass of one mole Molar mass Equivalent amounts of Silicon 28.1 g Si = 1 mole Si = 6.02 x 10 23 atoms Si 6.02 x 1023 particles Molar Mass

  15. Molar Mass of Hydrogen Gas-H2 2 H 2(1.0g)= 2.0 g 2.0g H2 = 1 mole H2 = 6.02 x 1023 H2 molecules *Since there are 2 hydrogen atoms in each molecule, we could determine the number of hydrogen atoms by.. 2(6.02 x 1023) = 1.20 x 1024 hydrogen atoms

  16. Molar Mass of Mg(OH)2 1 Mg 1(24.3g) = 24.3 g 2 02(16.0g)= 32.0 g 2 H2(1.0g) = 2.0 g Mg(OH)2 = 58.3 g 58.3g Mg (0H)2 = 1 mole Mg(0H)2 = 6.02 x 1023Mg(0H)2 formula units *Since there are 2 hydroxide ions in each formula unit, we could determine the number of hydroxide ions by.. 2(6.02 x 1023) = 1.20 x 1024 hydroxide ions.

  17. Let’s Practice: • Determine the molar mass of each substance to the 10th place. • Pause the presentation to give yourself time to work prior to moving on.

  18. Check your answers:

  19. mass-mole-particle problems • Identify equivalent relationships for that substance • Write ratios using number given in the problem and equivalents • Solve: unit on answer, sig. fig or round Given = X (?) EquivEquiv

  20. Determine the number of moles in 48 g of hydrogen gas. Express your answer to 2 significant figures. 48g H2 X moles H2 Given 48 g H2 = X moles H2 Equivalents 2.0 g H2 1 mole H2 6.02 x 1023 2.0g H2 = 1 mole H2 = 6.02 x 1023 H2 molecules 1 mole x 48 g H2= X moles H2 x 1 mole 2.0 g H2 1 mole H2 Mole 6.02 x 1023 particles Molar Mass Answer: X = 24 moles of H2

  21. Determine the number of hydrogen molecules in 48 g of hydrogen gas. Express your answer to 3 significant figures. 48g H2 X molecules H2 48 g H2 = X molecules H2 2.0 g H2 6.02 x 1023 molecules H2 2.0g H2 = 1 mole H2 = 6.02 x 1023 H2 molecules 6.02 x 1023molecules H2 x 48 g = X molecules x 6.02 x 1023 molecules 2.0 g 6.02 x 1023 molecules H2 Answer: X = 1.44 x 1025 molecules of H2

  22. Determine the mass of 3.6 x 10 24 formula units of Mg(OH)2. Express your answer to 2 significant figures. X g Mg(OH)23.6 x 1024fm Given 3.6 x 1024fm = X g Equivalents 6.02 x 1023fm 58.3 g 58.3g Mg (0H)2 = 1 mole Mg(0H)2 = 6.02 x 1023Mg(0H)2 formula units 58.3 g x 3.6 x 1024fm = X g x 58.3 g 6.02 x 1023fm 58.3 g calcualtor : X = 348.63 g of Mg(OH)2 Correct Answer x = 350 g of Mg(OH)2

  23. Molar Volume: volume of one mole of any ideal gas at STP. 22.4 L

  24. Mole Equivalents so far… 22.4 L Molar Volume = = = 2.0 g H2 = 22.4 L H2 = 1 mole H2 = 6.02 x 1023 H2molecules Mole 6.02 x 1023 particles Molar Mass

  25. Determine the volume in liters of 1.0 g of H2 gas at STP. Express your answer to 3 significant figures. 1.0 g H2 X Liters H2 Given 1.0 g H2 = X L H2 Equivalents 2.0 g H2 22.4 L H2 2.0 g H2 = 22.4 L H2 = 1 mole H2 = 6.02 x 1023 H2 molecules 22.4 L H2x 1.0 g H2= X L H2 x 22.4 L 2.0 g H2 22.4 L H2 Answer: X = 11.2 Liters of H2

  26. Molarity: concentration of a solution Liters of Solution x Molarity = moles of solute x Liters of solutions Liter of Solution MV=mol • Liters of Solution = Volume • Volume x Molarity = moles of solute • VM = mol of solute

  27. Advanced Level QuestionDetermine the #molecules of C6H12O6 present in 2.0 L of 0.1 M C6H12O6 solution to 2 sig figs. VM =Mole (2.0)(0.1)= 0.2molesC6H12O6 X molecules C6H12O6 Given 0.2 mole C6H12O6= X molecules C6H12O6 Equivalents 1.0 mole C6H12O6 6.02 x 10 23 Molecules C6H12O6 180g C6H12O6= 1 mole C6H12O6 = 6.02 x 1023 C6H12O6 molecules 6.02 x 1023molec x 0.2 moles C6H12O6= X molec C6H12O x 6.02 x 1023molec 1 mole C6H12O6 6.02 x 1023molec C6H12O6 Answer: X = (1.204) or 1.2 x 1023 molecules

  28. Mole Equivalents so far… 22.4 L Molar Volume = = = VM=mol 2.0 g H2 = 22.4 L H2 = 1 mole H2 = 6.02 x 1023 H2molecules Mole 6.02 x 1023 particles Molar Mass

  29. Web References for images used in this presentation (retrieved on 4/13/13. • Basketball and 22.4 L http://www.google.com/imgres?imgurl=http://pegasus.cc.ucf.edu/~jparadis/chem2045/pictures/22L.gif&imgrefurl=http://pegasus.cc.ucf.edu/~jparadis/chem2045/chapter10.html&h=147&w=219&sz=27&tbnid=ogJOpxu6GCTuOM:&tbnh=84&tbnw=125&prev=/search%3Fq%3Dpictures%2Bof%2B22.4%2Bliter%26tbm%3Disch%26tbo%3Du&zoom=1&q=pictures+of+22.4+liter&usg=__pbaUf2wjX6a1QCS3o4osovMNDwY=&docid=HnBP11ioonyqcM&sa=X&ei=3etqUYT3EpLH0gHq6oHQCg&ved=0CDIQ9QEwAA&dur=805 • Yellow balloon: http://www.google.com/search?q=yellow+balloon&client=safari&rls=en&source=lnms&tbm=isch&sa=X&ei=j-xqUZTiEseQ0QGJ44DQCw&ved=0CAoQ_AUoAQ&biw=1440&bih=1027#imgrc=RnZz087BUeKrhM%3A%3Br5ITN3_h5rYk8M%3Bhttp%253A%252F%252Fimages2.wikia.nocookie.net%252F__cb20100827193456%252Fclubpenguin%252Fimages%252F3%252F37%252FYellow_Balloon_Pin.PNG%3Bhttp%253A%252F%252Fclubpenguin.wikia.com%252Fwiki%252FList_of_Pins%3B647%3B678 • Millimole: http://www.google.com/search?q=millimole&client=safari&rls=en&source=lnms&tbm=isch&sa=X&ei=yOxqUdHIIKre0gHd7oD4Bw&ved=0CAoQ_AUoAQ&biw=1440&bih=1027#imgrc=XGyh4GH4vmgjHM%3A%3BX1Qjwmj7WBBNfM%3Bhttp%253A%252F%252Fcen.acs.org%252Fcontent%252Fcen%252Farticles%252F89%252Fi43%252FChemistsHoliday-Indestructible-Data%252F_jcr_content%252Farticlebody%252Fsubpar%252Farticlemedia_0.img.jpg%252F1337102404241.jpg%3Bhttp%253A%252F%252Fcen.acs.org%252Farticles%252F89%252Fi43%252FChemistsHoliday-Indestructible-Data.html%3B250%3B363 • Periodic table: http://www.google.com/search?q=periodic+table+image&client=safari&rls=en&tbm=isch&tbo=u&source=univ&sa=X&ei=6OxqUcPkA83h0wHw14DABQ&ved=0CDAQsAQ&biw=1440&bih=1027#imgrc=SBmm9sVgZp9MEM%3A%3BdALekFEoH5_lJM%3Bhttp%253A%252F%252Fscienceshowoff.files.wordpress.com%252F2012%252F04%252Fperiodic-table-sso-sheet11.gif%3Bhttp%253A%252F%252Fscienceshowoff.wordpress.com%252F2012%252F04%252F04%252Fthe-periodic-table-of-science-showoff-is-this-everyone-so-far%252F%3B1271%3B656 • Purple flask: http://www.google.com/search?q=purple+flask+image&client=safari&rls=en&tbm=isch&tbo=u&source=univ&sa=X&ei=JO1qUZq5EoSQ0QHnroDwBQ&ved=0CDAQsAQ&biw=1440&bih=1027#imgrc=h7SivimwYPRtTM%3A%3BwYmQQuW75HtRCM%3Bhttp%253A%252F%252Fupload.wikimedia.org%252Fwikipedia%252Fcommons%252Fthumb%252Ff%252Ff1%252FConical_flask_purple.svg%252F120px-Conical_flask_purple.svg.png%3Bhttp%253A%252F%252Fcommons.wikimedia.org%252Fwiki%252FFile%253AConical_flask_purple.svg%3B120%3B120 • Cubic yard: http://www.google.com/url?sa=i&rct=j&q=cubic+yard+image&source=images&cd=&cad=rja&docid=w0Gch7gTHE_6mM&tbnid=uqJfNRmSGhjnHM:&ved=&url=http%3A%2F%2Fwww.flickr.com%2Fphotos%2Fzanateh%2F4515124645%2F&ei=2e1qUbHLLbC-0QHKq4GQCg&bvm=bv.45175338,d.dmQ&psig=AFQjCNHEtQDxpQ11StN00HoM5PxCaYACWQ&ust=1366048602181785 • Ream of Paper: http://www.google.com/url?sa=i&rct=j&q=ream+of+paper&source=images&cd=&cad=rja&docid=Y60ii69orYVCyM&tbnid=m3ezUv6o5oAxDM:&ved=&url=http%3A%2F%2Fwww.staples.com%2FDomtar-Earthchoice-Office-Paper-11-x17-Ream%2Fproduct_755068&ei=N-5qUY2cA-LD0QHM84HwBw&bvm=bv.45175338,d.dmQ&psig=AFQjCNGhH70tDfLrs6WLGTWCUq2jf6NLCA&ust=1366048695458617 • Stone: http://www.google.com/url?sa=i&rct=j&q=scales+and+weight+and+british&source=images&cd=&cad=rja&docid=H_YPOIYCpPszNM&tbnid=Su5-v-VUlOhE7M:&ved=&url=http%3A%2F%2Fgiventodistractingothers.blogspot.com%2F2012%2F06%2Fsalter-best-of-british-review.html&ei=Lu9qUa7eEdLA4AOJ54GwDQ&bvm=bv.45175338,d.dmQ&psig=AFQjCNG3YbWuWUvR9KY1QbdRsDyPTuokFw&ust=1366048942723534 • Eggs: http://www.google.com/url?sa=i&rct=j&q=egg+carton&source=images&cd=&cad=rja&docid=mLs9LFCNzzI7KM&tbnid=qp4du8xGzQy3bM:&ved=&url=http%3A%2F%2Fwww.strombergschickens.com%2Fproduct%2Fegg-cartons-250%2Fegg-selling&ei=CPBqUfc5lcngA_W9gOAI&bvm=bv.45175338,d.eWU&psig=AFQjCNFTO2PeEtDcliTrJp_VL4mXtBroOg&ust=1366049160452595 • Chemistry EOC Reference: www.tea.state.tx.us/WorkArea/linkit.aspx?LinkIdentifier...Share

More Related