1 / 2

Analysis of Derivative and Line Equation for Quadratic Function in 2007

This document explores the relationship between a quadratic function and its derivative. The function is expressed as f(x) = x² - 7. By calculating its derivative, we find that f'(x) = 2x, which gives the slope at any point x. Specifically, at x = -3, the slope f'(-3) is evaluated to be -6. Using this slope and a point on the curve, the equation of the tangent line is derived in the form y = -6x - 16. The analysis highlights the importance of derivatives in understanding the behavior of functions.

elvina
Télécharger la présentation

Analysis of Derivative and Line Equation for Quadratic Function in 2007

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 2007 f(x) = x2-7 f’(x) = 2x So the ’lutning’ is given by 2x. So f’(x) = 2.-3 = -6. When x -3, y= x2 – 7  y = 2 x=-3; y= 2, k= -6 y=kx + m  y-kx=m  m=2-(-6.-3) = -16 Y= -6X- 16

  2. 2007

More Related