130 likes | 243 Vues
Designed by Skip Tyler, Varina High School, this course helps students determine functions and relation types, understand function notation, and apply function values. Practice identifying functions with examples and learn to find the value of functions. Master the concepts with unique teaching methods. Perfect for students looking to strengthen their understanding of functions.
E N D
ObjectivesThe student will be able to: 1. To determine if a relation is a function. 2. To find the value of a function. SOL: A.7aef Designed by Skip Tyler, Varina High School
Functions A function is a relation in which each element of the domain is paired with exactly one element of the range. Another way of saying it is that there is one and only one output (y) with each input (x). f(x) y x
Function Notation Input Name of Function Output
2 3 5 4 3 0 2 3 f(x) f(x) f(x) f(x) Determine whether each relation is a function. 1. {(2, 3), (3, 0), (5, 2), (4, 3)} YES, every domain is different!
1 4 5 5 6 6 9 3 1 2 f(x) f(x) f(x) f(x) f(x) Determine whether the relation is a function. NO, 5 is paired with 2 numbers! 2. {(4, 1), (5, 2), (5, 3), (6, 6), (1, 9)}
Answer Now Is this relation a function?{(1,3), (2,3), (3,3)} • Yes • No
Vertical Line Test (pencil test) If any vertical line passes through more than one point of the graph, then that relation is not a function. Are these functions? FUNCTION! FUNCTION! NOPE!
Vertical Line Test FUNCTION! NO! NO WAY! FUNCTION!
Answer Now Is this a graph of a function? • Yes • No
Given f(x) = 3x - 2, find: = 7 1) f(3) 2) f(-2) 3(3)-2 3 7 = -8 3(-2)-2 -2 -8
Given h(z) = z2 - 4z + 9, find h(-3) (-3)2-4(-3)+9 -3 30 9 + 12 + 9 h(-3) = 30
Answer Now Given g(x) = x2 – 2, find g(4) • 2 • 6 • 14 • 18
Answer Now Given f(x) = 2x + 1, find-4[f(3) – f(1)] • -40 • -16 • -8 • 4