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ALGEBRA 1 EOC REVIEW 5 PARALLEL, PERPENDICULAR LINES, MIDPOINT

ALGEBRA 1 EOC REVIEW 5 PARALLEL, PERPENDICULAR LINES, MIDPOINT. 1). A highway is being built parallel to the train tracks. The equation of the line for the tracks is 3 x – 7 y = 11. What is the slope of the highway?. y = 3 / 7 x – 11 / 7. A) 3 / 7. m = 3 / 7. B) 7 / 3.

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ALGEBRA 1 EOC REVIEW 5 PARALLEL, PERPENDICULAR LINES, MIDPOINT

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  1. ALGEBRA 1 EOC REVIEW 5 PARALLEL, PERPENDICULAR LINES, MIDPOINT

  2. 1) A highway is being built parallel to the train tracks. The equation of the line for the tracks is 3 x – 7 y = 11. What is the slope of the highway? y = 3/7 x – 11/7 A) 3/7 m = 3/7 B) 7/3 C) – 3/7 D) – 7/3

  3. 2) The equation of a line containing one side of a parallelogram is 2 x + 5 y = 8. The opposite side contains the point (5, - 4). What is the equation of the line containing the opposite side? A) y = - 2/5 x + 6 y = - 2/5 x + 8/5 m = - 2/5 B) y = - 2/5 x – 4 - 4 = - 2/5(5) + b C) y = - 2/5 x – 2 - 4 = - 2 + b D) y = 2/5 x – 3 - 2 = b y = - 2/5 x – 2

  4. 3) Line m is parallel to line n and passes through (5, - 4). If the equation of n is y = - 2/5 x + 2, which describes m? - 4 = - 2/5(5) + b - 4 = - 2 + b - 2 = b A) Line m has a slope of – 2/5 and a y-intercept of – 4. B) Line m has a slope of – 2/5 and a y-intercept of 6. C) Line m has a slope of – 2/5 and a y-intercept of – 2 . • Line m has a slope of 5/2 and a y-intercept of • - 4.

  5. 4) Which is an equation of a line parallel to (0, 1) (1/2, 0) B) y = - 2 x + 4 A) y = 2 x + 3 D) y = - ½ x + 4 C) y = ½ x + 2

  6. 5) Which is an equation of a line perpendicular to m of perpendicular: ½ B) y = - 2 x + 3 A) y = 2 x + 3 D) y = - ½ x – 1 C) y = ½ x + 1

  7. 6) First Street is perpendicular to L Street. The equation of L street on a map is represented by the equation y = 2 x + 6. What is the equation representing First Street if it passes through the point (- 4, 5)? B) y = - 2 x + 5 A) y = 2 x + 13 D) y = - ½ x + 5 C) y = - ½ x + 3 m of perpendicular: - ½ y = - 1/2 x + 3 5 = - 1/2(- 4) + b 3 = b 5 = 2 + b

  8. 7) Line q passes through (6, 4) and is perpendicular to the graph of the line y = - 2/3 x + 8. Which is the equation of line q? B) y = 3/2 x + 5 A) y = - 2/3 x + 8 D) y = 3/2 x – 5 C) y = 2/3 x m of perpendicular: 3/2 4 = 3/2(6) + b y = 3/2 x – 5 4 = 9 + b - 5 = b

  9. AB = 5 BC = 6 CD = 9 AD = 2 8) Given points A(7, 8), B(5, - 2), C(6, - 8) and D(8, 10), which of the following is true? SLOPES: A) AB is parallel to CD. B) AD is parallel to BC. C) AB is perpendicular to BC. D) None of these are true.

  10. 9) Consider the line y = m x + b where m > 0 and b > 0. What change occurs if m is multiplied by - 1? A) The y-intercept becomes positive. B) The y-intercept becomes negative. C) The slope becomes positive. D) The slope becomes negative.

  11. 10) Consider the line y = m x + b where m > 0 and b > 0. Suppose the the x-intercept is increased and the slope remains the same. What happens to the y-intercept? A) It moves up. B) It moves down. C) It moves right. D) It moves left.

  12. 11) On a map, Sarah’s house is located at (- 4, 6) and Jose’s house is located at (13, 7). What point is exactly halfway in between Sarah and Jose? A) (- 2.5, 9.5) B) (- 11, 5) C) (30, 8) D) (4.5, 6.5)

  13. 12) Points A and B form a segment that has a midpoint M. A is (9, 1) and M is (5, 3). Find the coordinates of B. 2(5) = 9 + x 10 = 9 + x A) (7, 2) 1 = x B) (13, - 1) 2(3) = 1 + y C) (1, 5) 6 = 1 + y B(1, 5) D) (11.5, 2.5) 5 = y

  14. 13) Point P (5, 7) and point Q (- 3, 9) are the endpoints of a diameter of a circle. What are the coordinates of point O, the center of the circle? A) (1, 8) B) (- 1, 8) C) (3.5, 11.5) D) (- 11, 11)

  15. 14) The library is directly between the Post Office and the local bank. The library is 3 blocks east and 2 blocks south of the center of town. The Post Office is 1 block east and 4 blocks north of the center of town. Find the location of the local bank from the center of town. 2(3) = 1 + x 2(-2) = 4 + y 5 = x - 8 = y A) 2 blocks east, 1 block north PO(1, 4) B) 3 ½ blocks east, 0 blocks north C(0, 0) C) 1 block west, 8 blocks south L(3, - 2) D) 5 blocks east, 8 blocks south B(5, - 8)

  16. 15) The coordinates of the vertices of a square are A(- 3, - 6), B(3, 2), C(- 3, 10) and D(- 9, 2). Find the area. FIND LENGTHS OF SIDES: Area = s2 = 102 = 100

  17. 16) Find the perimeter of the triangle with vertices A(- 5, 3), B(4, 2), and C(7, - 1). (Round the answer to the nearest tenth.) FIND LENGTHS OF SIDES: PERIMETER = 9.1 + 4.2 + 12.7 = 26

  18. 17) What is the length of the line segment between (- 4, - 5) and (5, 2)? (Round the answer to the nearest tenth.)

  19. 18) The distance between school and your house is miles. If your house is located at (10, 1), find a missing coordinate of school (x, 8). A) 3 (x – 10)2 + (- 7)2 = 50 B) 11 x2 – 20 x + 100 + 49 = 50 C) 8 x2 – 20 x + 149 = 50 D) 50 x2 – 20 x + 99 = 0 {9, 11} (x – 9)(x – 11) = 0

  20. 19) Four friends were driving from Charlotte to Chicago, Illinois. For Day 1 their speeds and driving time are listed in the table below. Who was closest to Chicago after Day 1? B) Jackie A) Darren D) Tony C) Maria

  21. 20) Jane walked three miles in 36 minutes. Sally walked 3872 yards in 22 minutes. Which best describes this situation? (1 mile = 1760 yards) 36 minutes = 36/60 = 3/5 hour 22 minutes = 22/60 = 11/30 hour 3872 yards = 3872/1760 miles = 2.2 miles A) Jane walked 1 mph faster than Sally. B) Sally walked 1 mph faster than Jane. C) Sally walked 3 mph faster than Jane. D) Jane walked 3 mph faster than Sally.

  22. 21) What is the equation of the line that goes through the midpoint of the segment joining (2, 3) and (- 4, 9) and is parallel to the graph of y = - 2 x + 1. m = - 2 6 = - 2(-1) + b 6 = 2 + b 4 = b M(- 1, 6) y = - 2 x + 4

  23. 22) A is located at (2, 4). B is located at (6, 0). C is the midpoint of the segment joining A and B. D is the midpoint of the segment joining A and C. Find the coordinates of C. D(3, 3) C(4, 2)

  24. 23) Two boys, Jake and Hiroshi, went for a walk. Hiroshi began walking 30 seconds earlier than Jake. Hiroshi walked at a speed of 8 feet per second. Jake walked at 10 feet per second. How many seconds after JAKE had started walking had the boys walked the same distance? Jake’s time: x x = 120 seconds Hiroshi’s time: x + 30 8(x + 30) = 10 x 8 x + 240 = 10 x 240 = 2 x

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