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Geometry Grab your clicker and get ready for the warm-up

Geometry Grab your clicker and get ready for the warm-up. The distance from a point to a line can be called the “ ” distance. P arallel Vertical Perpendicular Circumcenter Bisector. A point on a perpendicular bisector is from the two endpoints of the bisected segment. Equidistant

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Geometry Grab your clicker and get ready for the warm-up

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Presentation Transcript

  1. GeometryGrab your clicker and get ready for the warm-up

  2. The distance from a point to a line can be called the “ ” distance • Parallel • Vertical • Perpendicular • Circumcenter • Bisector

  3. A point on a perpendicular bisector is from the two endpoints of the bisected segment • Equidistant • Perpendicular • Corresponding • Centroid • Midpoint

  4. A point on an angular bisector is equidistant from the two of the angle • Angles • Vertices • Right Angles • Sides • Incenters

  5. The point of concurrency for the perpendicular bisectors of a triangle is called the • Incenter • Orthocenter • Midpoint • Circumcenter • Centroid • Midsegment

  6. The point of concurrency for the angular bisectors of a triangle is called the • Incenter • Orthocenter • Midpoint • Circumcenter • Centroid • Midsegment

  7. A median of a triangle goes from the vertex to the of the opposite side • Circumcenter • Angle • Perpendicular • Centroid • Side • Midpoint • Orthocenter

  8. The point of concurrency for the medians of a triangle is called the • Incenter • Orthocenter • Midpoint • Circumcenter • Centroid • Midsegment

  9. An altitude goes from a vertex and is to the opposite side • Circumcenter • Angle • Perpendicular • Centroid • Side • Midpoint • Orthocenter

  10. The point of concurrency for the altitudes of a triangle is called the • Incenter • Orthocenter • Midpoint • Circumcenter • Centroid • Midsegment

  11. The circumcenter of a triangle is equidistant from the • Vertices • Incenter • Centroid • Perpendicular • Sides

  12. The incenterof a triangle is equidistant from the • Vertices • Incenter • Centroid • Perpendicular • Sides

  13. The Pythagorean Theorem for this right triangle would state: • a2 + b2 = c2 • f2 + g2 + h2 = 180 • f2 + g2 = h2 • h2 + g2 = f • g2 + h2 = 90 • g2 + h2 = f2 • g2 – h2 = f2

  14. Given C is the centroidand that XC = 8, determine CK • 16 • 14 • 12 • 10 • 8 • 6 • 4 • 2 • 1

  15. Given C is the centroidand that CZ = 3, determine CJ • 9 • 3 • 6 • 1.5 • 4.5 • Not possible • None of the above

  16. Given C is the centroidand that YI = 15, determine YC • 9 • 12 • 3 • 6 • 1.5 • 4.5 • 7.5 • 8 • Not possible • None of the above

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