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Circular Motion

Circular Motion. Physics 6A. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB. U niform = Constant Speed C ircular = The Path is a Circle (or part of a circle) M otion = Speed is not zero. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB.

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Circular Motion

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  1. Circular Motion Physics 6A Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  2. Uniform = Constant Speed Circular = The Path is a Circle (or part of a circle) Motion = Speed is not zero Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  3. Uniform = Constant Speed Circular = The Path is a Circle (or part of a circle) Motion = Speed is not zero Examples of UCM: A car driving around a circular turn at constant speed Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  4. Uniform = Constant Speed Circular = The Path is a Circle (or part of a circle) Motion = Speed is not zero Examples of UCM: A car driving around a circular turn at constant speed A rock tied to a string and whirled in a circle Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  5. Uniform = Constant Speed Circular = The Path is a Circle (or part of a circle) Motion = Speed is not zero Examples of UCM: A car driving around a circular turn at constant speed A rock tied to a string and whirled in a circle Clothes in a dryer spinning at constant speed Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  6. Uniform = Constant Speed Circular = The Path is a Circle (or part of a circle) Motion = Speed is not zero Examples of UCM: A car driving around a circular turn at constant speed A rock tied to a string and whirled in a circle Clothes in a dryer spinning at constant speed A passenger on a Ferris wheel Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  7. Uniform = Constant Speed Circular = The Path is a Circle (or part of a circle) Motion = Speed is not zero Examples of UCM: A car driving around a circular turn at constant speed A rock tied to a string and whirled in a circle Clothes in a dryer spinning at constant speed A passenger on a Ferris wheel Earth orbiting the Sun (almost, but not quite true) Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  8. Uniform = Constant Speed Circular = The Path is a Circle (or part of a circle) Motion = Speed is not zero Examples of UCM: A car driving around a circular turn at constant speed A rock tied to a string and whirled in a circle Clothes in a dryer spinning at constant speed A passenger on a Ferris wheel Earth orbiting the Sun (almost, but not quite true) What do these motions have in common? Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  9. Uniform = Constant Speed Circular = The Path is a Circle (or part of a circle) Motion = Speed is not zero Examples of UCM: A car driving around a circular turn at constant speed A rock tied to a string and whirled in a circle Clothes in a dryer spinning at constant speed A passenger on a Ferris wheel Earth orbiting the Sun (almost, but not quite true) What these motions have in common: Constant speed (not constant velocity) Acceleration toward the center of the circle (constant magnitude) CENTRIPETAL is the word for this Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  10. We have a formula that we will use often for circular motion. For an object moving in a circular path, the centripetal (toward the center) acceleration is given by: You might also see arad, which stands for radial acceleration Here v stands for the linear speed and R is the radius of the circular path. v v arad arad Notice that the radial acceleration is always toward the center of the circle, and the velocity is always tangent to the circle. This is Uniform Circular Motion v arad arad arad v v Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  11. Example Problem 1 A centrifuge rotates at a rate of 1000 revolutions per minute. If the test tube in the centrifuge is 8.3 cm long, find the centripetal acceleration at the bottom of the test tube. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  12. Example Problem 1 A centrifuge rotates at a rate of 1000 revolutions per minute. If the test tube in the centrifuge is 8.3 cm long, find the centripetal acceleration at the bottom of the test tube. Here is a diagram of the centrifuge. The bottom of the test tube is 8.3 cm from the center, so we will use a radius of 8.3 cm in our formula. 8.3 cm Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  13. Example Problem 1 A centrifuge rotates at a rate of 1000 revolutions per minute. If the test tube in the centrifuge is 8.3 cm long, find the centripetal acceleration at the bottom of the test tube. Here is a diagram of the centrifuge. The bottom of the test tube is 8.3 cm from the center, so we will use a radius of 8.3 cm in our formula. We need to find the speed v 8.3 cm Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  14. Example Problem 1 A centrifuge rotates at a rate of 1000 revolutions per minute. If the test tube in the centrifuge is 8.3 cm long, find the centripetal acceleration at the bottom of the test tube. Here is a diagram of the centrifuge. The bottom of the test tube is 8.3 cm from the center, so we will use a radius of 8.3 cm in our formula. We need to find the speed v Convert from rpm to m/s: 8.3 cm The circumference of the circle is the distance traveled during each revolution Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  15. Example Problem 1 A centrifuge rotates at a rate of 1000 revolutions per minute. If the test tube in the centrifuge is 8.3 cm long, find the centripetal acceleration at the bottom of the test tube. Here is a diagram of the centrifuge. The bottom of the test tube is 8.3 cm from the center, so we will use a radius of 8.3 cm in our formula. We need to find the speed v Convert from rpm to m/s: 8.3 cm The circumference of the circle is the distance traveled during each revolution Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  16. Example Problem 1 A centrifuge rotates at a rate of 1000 revolutions per minute. If the test tube in the centrifuge is 8.3 cm long, find the centripetal acceleration at the bottom of the test tube. Here is a diagram of the centrifuge. The bottom of the test tube is 8.3 cm from the center, so we will use a radius of 8.3 cm in our formula. We need to find the speed v Convert from rpm to m/s: 8.3 cm The circumference of the circle is the distance traveled during each revolution Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  17. Example Problem 1 A centrifuge rotates at a rate of 1000 revolutions per minute. If the test tube in the centrifuge is 8.3 cm long, find the centripetal acceleration at the bottom of the test tube. Here is a diagram of the centrifuge. The bottom of the test tube is 8.3 cm from the center, so we will use a radius of 8.3 cm in our formula. We need to find the speed v Convert from rpm to m/s: 8.3 cm The circumference of the circle is the distance traveled during each revolution Now we can use our formula to find acceleration: Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  18. Example Problem 2 A Ferris wheel with radius 14m is turning about an axis at its center, as shown. The linear speed of a passenger on the rim is constant at 7 m/s. What are the magnitude and direction of the passenger’s acceleration a) at the top and b) at the bottom? Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  19. Example Problem 2 A Ferris wheel with radius 14m is turning about an axis at its center, as shown. The linear speed of a passenger on the rim is constant at 7 m/s. What are the magnitude and direction of the passenger’s acceleration a) at the top and b) at the bottom? First think about the direction of the acceleration: Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  20. Example Problem 2 A Ferris wheel with radius 14m is turning about an axis at its center, as shown. The linear speed of a passenger on the rim is constant at 7 m/s. What are the magnitude and direction of the passenger’s acceleration a) at the top and b) at the bottom? First think about the direction of the acceleration: At the top, the acceleration is downward (toward the center) Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  21. Example Problem 2 A Ferris wheel with radius 14m is turning about an axis at its center, as shown. The linear speed of a passenger on the rim is constant at 7 m/s. What are the magnitude and direction of the passenger’s acceleration a) at the top and b) at the bottom? First think about the direction of the acceleration: At the top, the acceleration is downward (toward the center), and at the bottom, the acceleration is upward (again, toward the center) Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  22. Example Problem 2 A Ferris wheel with radius 14m is turning about an axis at its center, as shown. The linear speed of a passenger on the rim is constant at 7 m/s. What are the magnitude and direction of the passenger’s acceleration a) at the top and b) at the bottom? First think about the direction of the acceleration: At the top, the acceleration is downward (toward the center), and at the bottom, the acceleration is upward (again, toward the center) We can find the magnitude from our formula for centripetal acceleration: Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  23. Example Problem 2 A Ferris wheel with radius 14m is turning about an axis at its center, as shown. The linear speed of a passenger on the rim is constant at 7 m/s. What are the magnitude and direction of the passenger’s acceleration a) at the top and b) at the bottom? First think about the direction of the acceleration: At the top, the acceleration is downward (toward the center), and at the bottom, the acceleration is upward (again, toward the center) We can find the magnitude from our formula for centripetal acceleration: Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  24. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  25. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Static friction is not strong enough to keep your tires from slipping on the pavement. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  26. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Static friction is not strong enough to keep your tires from slipping on the pavement. OK, let’s say you are riding your bike around a level curve and your maximum speed is v when the radius of the curve is R. Here are a couple of multiple choice questions: 1) What is your maximum speed if the radius of the curve is 2R? Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  27. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Static friction is not strong enough to keep your tires from slipping on the pavement. OK, let’s say you are riding your bike around a level curve and your maximum speed is v when the radius of the curve is R. Here are a couple of multiple choice questions: 1) What is your maximum speed if the radius of the curve is 2R? We will need to find a formula relating v and R. A diagram may help. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  28. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Static friction is not strong enough to keep your tires from slipping on the pavement. OK, let’s say you are riding your bike around a level curve and your maximum speed is v when the radius of the curve is R. Here are a couple of multiple choice questions: 1) What is your maximum speed if the radius of the curve is 2R? We will need to find a formula relating v and R. A diagram may help. View from above Notice that the friction force points toward the center of the curve. It is the centripetal force. friction Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  29. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Static friction is not strong enough to keep your tires from slipping on the pavement. OK, let’s say you are riding your bike around a level curve and your maximum speed is v when the radius of the curve is R. Here are a couple of multiple choice questions: 1) What is your maximum speed if the radius of the curve is 2R? We will need to find a formula relating v and R. A diagram may help. View from above Notice that the friction force points toward the center of the curve. It is the centripetal force. friction We know a formula for friction as well: Maximum static friction will give maximum speed. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  30. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Static friction is not strong enough to keep your tires from slipping on the pavement. OK, let’s say you are riding your bike around a level curve and your maximum speed is v when the radius of the curve is R. Here are a couple of multiple choice questions: 1) What is your maximum speed if the radius of the curve is 2R? We will need to find a formula relating v and R. A diagram may help. View from above Notice that the friction force points toward the center of the curve. It is the centripetal force. friction We know a formula for friction as well: Maximum static friction will give maximum speed. Solve for vmax Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  31. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Static friction is not strong enough to keep your tires from slipping on the pavement. OK, let’s say you are riding your bike around a level curve and your maximum speed is v when the radius of the curve is R. Here are a couple of multiple choice questions: 1) What is your maximum speed if the radius of the curve is 2R? We will need to find a formula relating v and R. A diagram may help. View from above Notice that the friction force points toward the center of the curve. It is the centripetal force. friction We know a formula for friction as well: Maximum static friction will give maximum speed. Solve for vmax If R is doubled, vmax increases by √2 Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  32. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Static friction is not strong enough to keep your tires from slipping on the pavement. OK, let’s say you are riding your bike around a curve and your maximum speed is v when the radius of the curve is R. Here are a couple of multiple choice questions: 1) What is your maximum speed if the radius of the curve is 2R? 2) What is your maximum speed if the radius is R, but the road is wet, so that your coefficient of static friction is only 1/3 of the value when the road is dry? Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  33. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Static friction is not strong enough to keep your tires from slipping on the pavement. OK, let’s say you are riding your bike around a curve and your maximum speed is v when the radius of the curve is R. Here are a couple of multiple choice questions: 1) What is your maximum speed if the radius of the curve is 2R? 2) What is your maximum speed if the radius is R, but the road is wet, so that your coefficient of static friction is only 1/3 of the value when the road is dry? We can use our formula from part 1) Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  34. Ride your bike around a curve and you will notice that if you go too fast, your tires will slip and you will fall. Why does this happen? Static friction is not strong enough to keep your tires from slipping on the pavement. OK, let’s say you are riding your bike around a curve and your maximum speed is v when the radius of the curve is R. Here are a couple of multiple choice questions: 1) What is your maximum speed if the radius of the curve is 2R? 2) What is your maximum speed if the radius is R, but the road is wet, so that your coefficient of static friction is only 1/3 of the value when the road is dry? We can use our formula from part 1) If µs decreases to µs/3 then vmax will decrease by √3. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  35. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  36. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  37. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The normal force is the force of the wall pushing inward. This is a centripetal force (it points toward the center of the circle). friction Normal mg Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  38. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The normal force is the force of the wall pushing inward. This is a centripetal force (it points toward the center of the circle). We can write down our formula for centripetal force: friction Normal mg Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  39. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The vertical forces must balance out if the person wants to avoid the crocodile pit, so we can write down a formula: friction What type of friction do we want – static or kinetic? Normal mg Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  40. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The vertical forces must balance out if the person wants to avoid the crocodile pit, so we can write down a formula: friction By putting the maximum force of static friction in our formula, we are assuming the man is just on the verge of sliding. Normal mg Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  41. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The vertical forces must balance out if the person wants to avoid the crocodile pit, so we can write down a formula: friction We can replace N with the expression we found earlier. Normal mg Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  42. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The vertical forces must balance out if the person wants to avoid the crocodile pit, so we can write down a formula: friction Normal mg Now that we have this formula, how do we use it? Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  43. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The vertical forces must balance out if the person wants to avoid the crocodile pit, so we can write down a formula: friction Normal mg Notice that the mass canceled out, so based on the given information we should solve for µ. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  44. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The vertical forces must balance out if the person wants to avoid the crocodile pit, so we can write down a formula: friction Normal mg The radius and speed are given, but the speed is in rpm, so we will need to convert it to m/s. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  45. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The vertical forces must balance out if the person wants to avoid the crocodile pit, so we can write down a formula: friction Normal mg The radius and speed are given, but the speed is in rpm, so we will need to convert it to m/s. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  46. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The vertical forces must balance out if the person wants to avoid the crocodile pit, so we can write down a formula: friction Normal mg Substitute the values for g, R and v Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  47. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drops out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? We can start by drawing a free-body diagram of the forces on the person. The vertical forces must balance out if the person wants to avoid the crocodile pit, so we can write down a formula: friction Normal mg So if the coefficient is 0.44 the person will be on the verge of sliding down into the pit. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

  48. Wheel of Doom! This carnival ride is a giant metal cylinder which will spin around and pin the occupants to the wall. The fun part is when the floor drop out from below and the patrons see a spike-filled pit of angry crocodiles awaiting them should they fall. As safety inspector, your problem will be to determine when it will be unsafe to ride. The given information is this: Radius of cylinder = 20m. Speed of rotation = 10 rpm. a) Will leather-clad Biker Bob (mass = 100kg ;coeff. of static friction = 0.6) be safe? b) How about Disco Stu, a 75kg man wearing a silk shirt and polyester pants (µs=0.15)? Biker Bob is safe (his 0.6 coefficient is larger than 0.44 , so static friction is enough to hold him in place) friction Disco Stu is doomed! (his 0.15 coefficient is too small, so static friction fails to hold him in place) Normal mg Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

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