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Rabin & Karp Algorithm

Rabin & Karp Algorithm. Rabin-Karp – the idea. Compare a string's hash values, rather than the strings themselves. For efficiency, the hash value of the next position in the text is easily computed from the hash value of the current position. How Rabin-Karp works.

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Rabin & Karp Algorithm

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  1. Rabin & Karp Algorithm

  2. Rabin-Karp – the idea • Compare a string's hash values, rather than the strings themselves. • For efficiency, the hash value of the next position in the text is easily computed from the hash value of the current position.

  3. How Rabin-Karp works • Let characters in both arrays T and P be digits in radix-S notation. (S = (0,1,...,9) • Let p be the value of the characters in P • Choose a prime number q such that fits within a computer word to speed computations. • Compute (p mod q) • The value of p mod q is what we will be using to find all matches of the pattern P in T.

  4. How Rabin-Karp works (continued) • Compute (T[s+1, .., s+m] mod q) for s = 0 .. n-m • Test against P only those sequences in T having the same (mod q) value • (T[s+1, .., s+m] mod q) can be incrementally computed by subtracting the high-order digit, shifting, adding the low-order bit, all in modulo q arithmetic.

  5. A Rabin-Karp example • Given T = 31415926535 and P = 26 • We choose q = 11 • P mod q = 26 mod 11 = 4 3 1 4 1 5 9 2 6 5 3 5 31 mod 11 = 9 not equal to 4 3 1 4 1 5 9 2 6 5 3 5 14 mod 11 = 3 not equal to 4 3 1 4 1 5 9 2 6 5 3 5 41 mod 11 = 8 not equal to 4

  6. Rabin-Karp example continued 3 1 4 1 5 9 2 6 5 3 5 15 mod 11 = 4 equal to 4 -> spurious hit 3 1 4 1 5 9 2 6 5 3 5 59 mod 11 = 4 equal to 4 -> spurious hit 3 1 4 1 5 9 2 6 5 3 5 92 mod 11 = 4 equal to 4 -> spurious hit 3 1 4 1 5 9 2 6 5 3 5 26 mod 11 = 4 equal to 4 -> an exact match!! 3 1 4 1 5 9 2 6 5 3 5 65 mod 11 = 10 not equal to 4

  7. Rabin-Karp example continued 3 1 4 1 5 9 2 6 5 3 5 As we can see, when a match is found, further testing is done to insure that a match has indeed been found. 53 mod 11 = 9 not equal to 4 3 1 4 1 5 9 2 6 5 3 5 35 mod 11 = 2 not equal to 4

  8. Analysis • The running time of the algorithm in the worst-case scenario is bad.. But it has a good average-case running time. • O(mn) in worst case • O(n) if we’re more optimistic… • Why? • How many hits do we expect? (board)

  9. Multiple pattern matching • Given a text T=T1…Tn and a set of patterns P1…Pk over the alphabet Σ, such that each pattern is of length m, find all the indices in T in which there is a match for one of the patterns. • We can run KMP for each pattern separately. • O(kn) • Can we do better?

  10. Bloom Filters • We’ll hold a hash table of size O(k) (the number of patterns) • For each offset in the text we’ll check whether it’s hash value matches that of any of the patterns.

  11. Analysis Expected: O(max(mk, n))

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