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Give Chapter 12 HW on Thursday test day

Give Chapter 12 HW on Thursday test day Then do 8 – Friday, 9 – Monday, 10 – Tuesday, 11 – Wednesday, 12 – Thursday the following week, then free review days Friday and Monday. R—05/31/12—HW #73: Pg 778-779: 1—11 all; Pg 825-826: 1—35 odd, 34 2) E 4) C 6) D 8) A 10) C

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Give Chapter 12 HW on Thursday test day

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  1. Give Chapter 12 HW on Thursday test day • Then do 8 – Friday, 9 – Monday, 10 – Tuesday, 11 – Wednesday, 12 – Thursday the following week, then free review days Friday and Monday

  2. R—05/31/12—HW #73: Pg 778-779: 1—11 all; Pg 825-826: 1—35 odd, 34 2) E 4) C 6) D 8) A 10) C 34) 288.89pi, 666.67pi

  3. Chapter 12 Review

  4. Is it a polyhedron? If so, count the faces, edges, and vertices. Also say whether or not it is convex. Yes 7 faces, 15 edges 10 vertices Convex Yes 6 faces, 12 edges 8 vertices Convex Euler’s Theorem: F + V = E + 2 (Like FAVE two, or cube method)

  5. Terms P  Perimeter of one base B  Area of base b  base (side) h  Height (relating to altitude) l  Slant Height TA  Total Area (Also SA for surface Area) LA  Lateral Area V  Volume

  6. Lateral Area of a right prism is the sum of area of all the LATERAL faces. = bh + bh + bh + bh = (b + b + b + b)h = Ph LA Total Area is the sum of ALL the faces. = 2B + Ph TA

  7. Cylinder

  8. Find the LA, SA of this rectangular prism. Height = 8 cm Radius = 4 cm 5 3 8 LA = SA = (22)5 = 110 units2

  9. Lateral Area of a regular pyramid is the area of all the LATERAL faces. Total area is area of bases. TA = B + Pl b b b b b + + + + l l l l l (b b b b b) + + + + =Pl l

  10. Cone

  11. Find Lateral Area, Total Area 13 cm 10 cm Slant Height = 15 in. Radius = 9 in

  12. Altitude is segment perpendicular to the parallel planes, also referred to as “Height”. Volume of a right prism equals the area of the base times the height of the prism. = Bh V Prism

  13. Find the V of this triangular prism. V = 8 4 3 5

  14. Find Volume Height = 8 cm Radius = 4 cm Cylinder

  15. Cone 13 cm 10 cm Slant Height = 15 in. Radius = 9 in

  16. Find SA and V with radius 6 m.

  17. Two shapes are similar if all the the sides have the same scale factor. If the scale factor of two similar solid is a:b, then The ratio of the corresponding perimeters is a:b The ratio of the base areas, lateral areas, and total areas is a2:b2 The ratio of the volumes is a3:b3 There be a problem where they give you area or volume, you must convert correctly to other ratio, set up proportion, then solve. We will talk about these.

  18. R—05/31/12—HW #73: Pg 778-779: 1—11 all; Pg 825-826: 1—35 odd, 34

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