SlideServe
Télécharger Obtenir Pro
Menu
Accueil Pro
Préférences
ApparenceLight Aide et commentaires
© SlideServe · v2026

Mastering Variable Solving: Algebra 1 Warm-Up and Quiz Presentation

jonah-henson avatar
jonah-henson
22 diapositives · 410 Views · Nov 01, 2014

This lesson presentation focuses on solving equations for a variable in algebra. Students will learn to rearrange formulas using inverse operations to isolate variables. Through examples such as finding the diameter of a bowl given its circumference and calculating time using distance and speed, learners will practice various methods for solving formulas. A quiz at the end reinforces understanding, covering topics like literal equations and applying different formulas. This interactive lesson aims to enhance student comprehension of fundamental algebraic concepts.

Mastering Variable Solving: Algebra 1 Warm-Up and Quiz Presentation - slide 1
01 / 22Mastering Variable Solving: Algebra 1 Warm-Up and Quiz Presentation
1 / 17

Télécharger la présentation

Mastering Variable Solving: Algebra 1 Warm-Up and Quiz Presentation
Une image / un lien ci-dessous est fourni (tel quel) pour télécharger la présentation

Politique de téléchargement : le contenu du site vous est fourni TEL QUEL pour votre information et votre usage personnel ; il ne peut être vendu, concédé sous licence ni partagé sur d’autres sites sans l’accord de son auteur.Le contenu vous est fourni TEL QUEL, pour votre information et votre usage personnel uniquement. Téléchargez la présentation en cliquant sur ce lien. Lors du téléchargement, si vous ne parvenez pas à télécharger une présentation, l’éditeur a peut-être supprimé le fichier de son serveur.Pendant le téléchargement, si vous ne parvenez pas à obtenir une présentation, le fichier a peut-être été supprimé par l’éditeur.

F I N

Plus de contenu associé

Transcription de la présentation

  1. 2-5 Solving for a Variable Warm Up Lesson Presentation Lesson Quiz Holt Algebra 1

  2. Warm Up Solve each equation. 1. 5 + x = –2 2. 8m = 43 3. 4. 0.3s + 0.6 = 1.5 5. 10k – 6 = 9k + 2 –7 19 3 8

  3. Objectives Solve a formula for a given variable. Solve an equation in two or more variables for one of the variables.

  4. Vocabulary formula literal equation

  5. A formula is an equation that states a rule for a relationship among quantities. In the formula d = rt, d is isolated. You can "rearrange" a formula to isolate any variable by using inverse operations. This is called solving for a variable.

  6. Example 1: Application The formula C = d gives the circumference of a circle C in terms of diameter d. The circumference of a bowl is 18 inches. What is the bowl's diameter? Leave the symbol  in your answer. Locate d in the equation. Since d is multiplied by , divide both sides by  to undo the multiplication. Now use this formula and the information given in the problem.

  7. The bowl's diameter is inches. Example 1: Application Continued The formula C = d gives the circumference of a circle C in terms of diameter d. The circumference of a bowl is 18 inches. What is the bowl's diameter? Leave the symbol  in your answer. Now use this formula and the information given in the problem.

  8. Check It Out! Example 1 Solve the formula d = rt for t. Find the time in hours that it would take Ernst Van Dyk to travel 26.2 miles if his average speed was 18 miles per hour. d = rt Locate t in the equation. Since t is multiplied by r, divide both sides by r to undo the multiplication. Now use this formula and the information given in the problem.

  9. Check It Out! Example 1 Solve the formula d = rt for t. Find the time in hours that it would take Ernst Van Dyk to travel 26.2 miles if his average speed was 18 miles per hour. Van Dyk’s time was about 1.46 hours.

  10. A = bh Since bh is multiplied by , divide both sides by to undo the multiplication. Example 2A: Solving Formulas for a Variable The formula for the area of a triangle is A = bh, where b is the length of the base, and is the height. Solve for h. Locate h in the equation. 2A = bh Since h is multiplied by b, divide both sides by b to undo the multiplication.

  11. Remember! Dividing by a fraction is the same as multiplying by the reciprocal.

  12. ms = w – 10e –w –w ms – w = –10e Example 2B: Solving Formulas for a Variable The formula for a person’s typing speed is ,where s is speed in words per minute, w is number of words typed, e is number of errors, and m is number of minutes typing. Solve for e. Locate e in the equation. Since w–10e is divided by m, multiply both sides by m to undo the division. Since w is added to –10e, subtract w from both sides to undo the addition.

  13. Example 2B: Solving Formulas for a Variable The formula for a person’s typing speed is ,where s is speed in words per minute, w is number of words typed, e is number of errors, and m is number of minutes typing. Solve for e. Since e is multiplied by –10, divide both sides by –10 to undo the multiplication.

  14. Remember! Dividing by a fraction is the same as multiplying by the reciprocal.

  15. f = i – gt + gt +gt Check It Out! Example 2 The formula for an object’s final velocity is f = i – gt, where i is the object’s initial velocity, g is acceleration due to gravity, and t is time. Solve for i. f = i – gt Locate i in the equation. Since gt is subtracted from i, add gt to both sides to undo the subtraction. f + gt = i

  16. A formula is a type of literal equation. A literal equation is an equation with two or more variables. To solve for one of the variables, use inverse operations.

  17. –y –y x = –y + 15 Example 3: Solving Literal Equations A. Solve x + y = 15 for x. x + y = 15 Locate x in the equation. Since y is added to x, subtract y from both sides to undo the addition. B. Solve pq = x for q. pq = x Locate q in the equation. Since q is multiplied by p, divide both sides by p to undo the multiplication.

  18. Check It Out! Example 3a Solve 5 – b = 2t for t. 5 – b = 2t Locate t in the equation. Since t is multiplied by 2, divide both sides by 2 to undo the multiplication.

  19. Solve for V Check It Out! Example 3b Locate V in the equation. Since m is divided by V, multiply both sides by V to undo the division. VD = m Since V is multiplied by D, divide both sides by D to undo the multiplication.

  20. Lesson Quiz: Part 1 Solve for the indicated variable. 1. 2. 3. 2x + 7y = 14 for y 4. for h P = R – C for C C = R – P for m m = x(k – 6) 5. for C C = Rt + S

  21. Lesson Quiz: Part 2 Euler’s formula, V – E + F = 2, relates the number of vertices V, the number of edges E, and the number of faces F of a polyhedron. 6. Solve Euler’s formula for F. F = 2 – V + E 7. How many faces does a polyhedron with 8 vertices and 12 edges have? 6