1 / 131

LCHS Physics Mark Ewoldsen, Ph.D.

LCHS Physics Mark Ewoldsen, Ph.D. Definitions. Voltage : Electric Potential or Potential Difference (Energy added or used) V (volts) = Joules/Coulomb One volt = one coulomb of charge gains or loses one joule of energy. What is the difference between E and V?.

july
Télécharger la présentation

LCHS Physics Mark Ewoldsen, Ph.D.

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. LCHS Physics Mark Ewoldsen, Ph.D.

  2. Definitions • Voltage: Electric Potential or Potential Difference (Energy added or used) • V (volts) = Joules/Coulomb • One volt = one coulomb of charge gains or loses one joule of energy

  3. What is the difference between E and V? • E is the voltage supplied by a battery • V is the voltage measured across a resistor

  4. Batteries • Positive and Negative terminals • electrons leave negative terminal • Batteries use a chemical reaction to create voltage • Construction: Two different metals and Acid • e.g. Copper, Zinc, and Citrus Acid • e.g. Lead, Lead Oxide, Sulfuric Acid • e.g. Nickel, Cadmium, Acid Paste

  5. Definitions • Current: Flow of electric charge • I (amps) = Q/t = Coulombs/second • Higher current increases heat due to more collisions of ‘free’ electrons with atoms

  6. Effect of Currents on the Body • 0.001 A can be felt • 0.005 A is painful • 0.010 A causes involuntary muscle contractions • 0.015 A causes loss of muscle control • 0.070 A can be fatal if the current last for more than 1 second

  7. Speed of Electrons in Circuit • Light goes on ‘instantly’ when switch turned on • Electrons do not move at speed of light • c = 3 x 108 • Electrons – 6 x 105 m/s in random directions • Signal (energy) moves at speed of light due to electric energy field • Wire acts as pipe to guide electric field • Electrons in circuit do not come from battery but are from the wire

  8. Definitions • Resistance: measure of a material’s ability to resist the flow of of electrons • Ω (ohms) = J-s/C2 • Conductor – low resistance • materials with free electrons • e.g. copper, aluminum, gold, most metals • Insulator – high resistance • materials with no free electrons • e.g. glass, plastics, ceramics, wood

  9. Definitions • Resistance • Increases with length – L • Decreases with cross area – A • Resistivity – ρ • material dependent • temperature dependent R = ρL A

  10. Definitions • Power is the rate energy is converted into another form • Resistors transform electrical energy into light, mechanical or heat energy • Equation for Power: P = I V (Watts) – Joules/second

  11. A Ammeter: measures amp(ere)s Battery: Source of energy Resistor: Removes energy V Voltmeter: measures volt(age) Wires: Definitions

  12. Reading a Voltmeter

  13. Reading a Ammeter

  14. Making Circuits

  15. Making Circuits A

  16. Making Circuits A V

  17. Making Circuits V A V

  18. How many batteries? A V

  19. How many ammeters? A V

  20. How many voltmeters? A V

  21. How many light bulbs? A V

  22. Ohm’s Law: V = I R V = voltage, I = current, R = resistance For a given voltage, as the resistance goes up, the current will go down OR If the resistance is less, the current is more

  23. Ohm’s Law A V

  24. Ohm’s Law A V

  25. Constant Voltage • For a given pressure on a car’s accelerator • Voltage or energy input • By increasing the steepness of a hill • Changing resistance • The car’s speed will go down • Decrease the current or amps

  26. Turned on When light is first turned on • Filament is cold • The resistance is low and • since V = IR, current is high • High current means filament is more likely to burn out

  27. Ohm’s Law: V/I = R V = voltage, I = current, R = resistance For a given resistance, as the voltage goes up, the current goes up

  28. A A A A V V V V Ohm’s Law – Set Resistance

  29. http://www.physics.udel.edu/wwwusers/watson/scen103/98w/note0105.htmlhttp://www.physics.udel.edu/wwwusers/watson/scen103/98w/note0105.html

  30. In a simple one resistor circuit, what is the Resistance if the Voltage is 12-V and Current is 3-A?

  31. In a simple one resistor circuit, what is the Resistance if the Voltage is 120-V and Current is 5-A?

  32. In a simple one resistor circuit, what is the Voltage if the Resistance is 12- and Current is 3-A?

  33. In a simple one resistor circuit, what is the Voltage if the Resistance is 3- and Current is 17-A?

  34. In a simple one resistor circuit, what is the Current if the Resistance is 3- and Voltage is 17-V?

  35. In a simple one resistor circuit, what is the Current if the Resistance is 3- and Voltage is 120-V?

  36. Series Circuit

  37. Finding V, I & R for a Series Circuit • Determine total E (V from battery) • Find the total Resistance RT = R1 + R2 + R3 … • Determine IT by I = VT/RT • Since I is constant in a series circuit, find V (energy used) by each resistor using V = ITR

  38. Finding V, I & R for a Series Circuit • Determine E (V from battery)

  39. 12 V 3 Ω 2 Ω 1 Ω

  40. Finding V, I & R for a Series Circuit • Determine E (V from battery)- 12V • Find the total Resistance RT = R1 + R2 + R3 …

  41. 12 V 3 Ω 2 Ω 1 Ω 6 Ω= 3 Ω + 2 Ω+ 1 Ω

  42. Finding V, I & R for a Series Circuit • Determine E (V from battery)- 12V • Find the total Resistance - 6 Ω

  43. Finding V, I & R for a Series Circuit • Determine E (V from battery)- 12V • Find the total Resistance - 6 Ω • Determine IT by IT = VT/RT 2 A= 12 V/ 6 Ω

  44. Finding V, I & R for a Series Circuit • Determine E (V from battery)- 12V • Find the total Resistance - 6 Ω • Determine that IT = 2 A • Since I is constant in a series circuit, find V (energy used ) for each resistor using V = ITR

  45. 12V = 6V + 4V + 2V 12 V 6V = 2A * 3Ω 3 Ω 2 Ω 1 Ω 4V = 2A * 2Ω 2V = 2A * 1Ω

  46. Series Circuit • Current is the same at all points I = I1 = I2 = I3 = I4 • Volt is divided among all the resistor E = V1 + V2 + V3 • Resistance accumulates R = R1 + R2 + R3

  47. 12 V 3 Ω 4 Ω 1 Ω

  48. 12 V 3 Ω 4 Ω 1 Ω What is the total Resistance?

  49. 12 V 3 Ω 4 Ω 1 Ω What is the total Resistance? 8 Ω What is the current leaving the Battery?

More Related