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Using the IBA on Titan

Using the IBA on Titan. Nuclear Model Codes at Yale Computer name: Titan. Connecting to SSH: Quick connect Host name: titan.physics.yale.edu User name: phy664 Port Number 22 Password: nuclear_codes cd phintm

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Using the IBA on Titan

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  1. Using the IBA on Titan

  2. Nuclear Model Codes at YaleComputer name: Titan Connecting to SSH: Quick connect Host name: titan.physics.yale.edu User name: phy664 Port Number 22 Password: nuclear_codes cd phintm pico filename.in (ctrl x, yes, return) runphintm filename (w/o extension) pico filename.out (ctrl x, return)

  3. Lets first do the three symmetries. Okey, dokey? Sph. Deformed

  4. Relation of IBA Hamiltonian to Group Structure

  5. 2.7 2.9 2.5 3.1 2.2 3.3 +2.0 +2.9 +1.4 +0.4 +0.1 -1 -0.1 -0.4 -2.0 -3.0 Now some calculations for real nuclei N = 10 R4/2

  6. Lets do some together Pick a nucleus, any collective nucleus 152-Gd (N=10) 186-W (N=11) Data 0+ 0 keV 0 keV 2+ 344 122 4+ 755 396 6+ 1227 809 0+ 615 883 2+ 1109 737 R4/2 = 2.19 z~ 0.4 3.24 z ~ 0.7 R0/2 = -1.43 c ~ -1.32 +1.2 c ~ -0.7 For N = 10 and k = - 0.02 MeVe = 4 x 0.02 x 10 [ (1 – z)/ z] e = 0.8 x [0.6 /0.4] ~ 1.2 MeV e = 0.8 x [0.3/0.7] ~ 0.33 MeV At the end, need to normalize energies to first J = 2 state. For now just look at energy ratios. These parameters are starting points.

  7. c Mapping the Entire Triangle with a minimum of data H =ε nd -  Q  Q Parameters: , c (within Q) /ε 2 parameters 2-D surface /ε varies from 0 to infinity /ε

  8. 0+ 4+ 2+ 2.5 1 2+ 0 0+ ζ H = c [ ( 1 – ζ ) nd - O(6) Qχ ·Qχ ] ζ = 1, χ = 0 4NB 0+ 2γ+ χ 3.33 4+ 2+ 0+ 2.0 4+ 1 2+ 2+ 1 ζ 0 0+ 0+ 0 U(5) SU(3) ζ = 0 ζ = 1, χ = -1.32 Spanning the Triangle

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