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CH 2 Powerpoint Review

CH 2 Powerpoint Review. Stay at your assigned computer Talk only to the people at your computer Each person must turn in a paper today. 35 30 25 20 15 10 5 0 -5 -10 -15 -20 -25 -30 -35 -40. 1. TIME (s). DISTANCE ( m ).

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CH 2 Powerpoint Review

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  1. CH 2 PowerpointReview Stay at your assigned computer Talk only to the people at your computer Each person must turn in a paper today

  2. 35 30 25 20 15 10 5 0 -5 -10 -15 -20 -25 -30 -35 -40 1 TIME (s) DISTANCE ( m ) 2 4 6 8 10 12 14 16 18 2022 242628 3032 3436 3840 • What time interval (if any) has negative velocities in positive positions? • What time interval(s) if any has a positive acceleration? • Does the object ever change directions? • What is the total distance for the 40 seconds? • Construct a VT graph that shows the same motion as this DT graph.

  3. 35 30 25 20 15 10 5 0 -5 -10 -15 -20 -25 -30 -35 -40 1 TIME (s) DISTANCE ( m ) 2 4 6 8 10 12 14 16 18 2022 242628 3032 3436 3840 • What time interval (if any) has negative velocities in positive positions? • What time interval(s) if any has a positive acceleration? • Does the object ever change directions? • What is the total distance for the 40 seconds? • Construct a VT graph that shows the same motion as this DT graph.

  4. 2 If an object travels 78.4 km/hr for 45 min, and then 50.0 km/hr for 20.0 km, what was the average velocity for the whole trip?

  5. 3 An object is tossed 24.0 m/s upward. How high does it go?

  6. 4 Sketch a VT graph for each DT graph: A. B. C.

  7. 35 30 25 20 15 10 5 0 -5 -10 -15 -20 -25 -30 -35 -40 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 5 VELOCITY (m/s) TIME (s) • What is the total distance for the 20 s? • What is the displacement for the 20 s?

  8. 6 Two objects start at the same place and travel 300 m. Both start from rest at the same time and reach 300m at the same time. One object travels at constant speed, and the other accelerates. If the first object has an acceleration of 4 m/s2, what must the constant speed of the other object be?

  9. 7 What was the initial velocity of a ball thrown from a 80.0 m tall cliff, if it strikes the base of the cliff with a velocity of 62.0 m/s?

  10. THINKER QUESTION: 8 A brick is dropped from rest from the top of a 40 m tall building. On the way down it is observed passing a 1.2 m tall window in .10 s. What is the height of the bottom of the window? 40 m ?

  11. Now you will check and correct your answers Take the time to really understand each problem

  12. 35 30 25 20 15 10 5 0 -5 -10 -15 -20 -25 -30 -35 -40 1 TIME (s) DISTANCE ( m ) 2 4 6 8 10 12 14 16 18 2022 242628 3032 3436 3840 • What time interval (if any) has negative velocities in positive positions? ANSWER : 32-40 s

  13. + direction + faster & faster + a 35 30 25 20 15 10 5 0 -5 -10 -15 -20 -25 -30 -35 -40 1 TIME (s) DISTANCE ( m ) 2 4 6 8 10 12 14 16 18 2022 242628 3032 3436 3840 B. What time interval(s) if any has a positive acceleration? ANSWER: 4 – 12 s

  14. 35 30 25 20 15 10 5 0 -5 -10 -15 -20 -25 -30 -35 -40 1 TIME (s) DISTANCE ( m ) 2 4 6 8 10 12 14 16 18 2022 242628 3032 3436 3840 C. Does the object ever change directions? ANSWER: Yes , at t = 32s it starts going in the negative direction

  15. 10 m 35 30 25 20 15 10 5 0 -5 -10 -15 -20 -25 -30 -35 -40 1 30 m TIME (s) DISTANCE ( m ) 2 4 6 8 10 12 14 16 18 2022 242628 3032 3436 3840 35 m D. What is the total distance for the 40 seconds? ANSWER: 75 m

  16. -15 – (-30) 15 22 – 12 10 30 - (-15) 45 28 - 22 6 25 - 20 5 38 - 40 -2 V = ________ = _____ = 7.5 m/s V = ________ = _____ = 1.5 m/s V = ________ = _____ = - 2.5 m/s 35 30 25 20 15 10 5 0 -5 -10 -15 -20 -25 -30 -35 -40 (28,30) 1 (38, 25) (40, 20) TIME (s) 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 DISTANCE ( m ) (22,-15) (12,-30) E. Construct a VT graph that shows the same motion as this DT graph. Find velocity (slope): Find velocity (slope): Find velocity (slope):

  17. If an object travels 78.4 km/hr for 45 min, and then 50.0 km/hr for 20.0 km, what was the average velocity for the whole trip? 2 First PartThe RestWhole Trip d d d t t t v = v = v = d 20 .75 t 78.8 78.4 = 50.0 = v = In hr 1.15 Solve: d = 58.8 km Solve: t = .4 hr Solve: V = 68.5 km/hr

  18. An object is tossed 24.0 m/s upward. How high does it go? vf2 = vi2 + 2ad 0 = 242 + 2(-9.8)d 0 = 576 - 19.6d 19.6d = 576 d = 29.4 m 3 So right here I set my frame of reference…UP is positive vi = 24 + Pos direction - Getting slower a = -9.8 Goes UP until it stops! vf = 0 d = ?

  19. 4 Sketch a VT graph for each DT graph: A. B. C.

  20. You do NOT have to split them The way that I did – as long As you have all rectangles And triangles We should get the same answers 35 30 25 20 15 10 5 0 -5 -10 -15 -20 -25 -30 -35 -40 10 90 10 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 62.5 225 30 5 VELOCITY (m/s) TIME (s) • What is the total distance for the 20 s? • What is the displacement for the 20 s? 30 + 225 + 62.5 + 10 + 10 + 90 = 427.5 m 10 + 10 + 90 – 30 – 225 – 62.5 = - 207.5 m

  21. Constant Speed Object Accelerating Object d t v = vi = 0 d = 300 a = 4 t = ? d = vit + ½ at2 300 = ½ (4)t2 300 12.2 v = t = 12.2 s Two objects start at the same place and travel 300 m. Both start from rest at the same time and reach 300 m at the same time. One object travels at constant speed, and the other accelerates. If the first object has an acceleration of 4 m/s2, what must the constant speed of the other object be? 6 v = 24.6 m/s

  22. 7 What was the initial velocity of a ball thrown from a 80.0 m tall cliff, if it strikes the base of the cliff with a velocity of 62.0 m/s? vi = ? d = 80 so down is POS a = 9.8 vf = 62 vf2 = vi2 + 2ad 622 = vi2 + 2(9.8)(80) vi = +- 47.7 m/s

  23. 32.0m THINKER QUESTION: 8 A brick is dropped from rest from the top of a 40 m tall building. On the way down it is observed passing a 1.2 m tall window in .10 s. What is the height of the bottom of the window? Passing window: From top of building: d = ? a = 9.8 vf = 11.5 vi = 0 d = 1.2 a = 9.8 t = .10 vi = ? d = vit + ½ at2 vf2 = vi2 + 2ad 40 m 1.2 = vi(.10) + ½ (9.8)(.10)2 11.52 = 2(9.8)d ? vi = 11.5 m/s d = 6.76 m

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