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The Mole Diagram

The Mole Diagram. Objective: Learn how to use visual aides to do conversions. Think of the mole as equal to two things. 1.00 mole CO 2 = _________ g CO 2 1.00 mole CO 2 = __________molecules. Now suppose you have 88.0 grams of CO 2 Use the diagram to convert to molecules.

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The Mole Diagram

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  1. The Mole Diagram Objective: Learn how to use visual aides to do conversions.

  2. Think of the mole as equal to two things • 1.00 mole CO2 = _________ g CO2 • 1.00 mole CO2 = __________molecules

  3. Now suppose you have 88.0 grams of CO2 • Use the diagram to convert to molecules.

  4. Now use the diagram to find the grams of CO2 in 3.0 x 1023 molecules of CO2

  5. Sulfur Trioxide • Set up a diagram to convert 30g of Sulfur trioxide to molecules • 30 grams to molecules

  6. The mole is equal to three things • At STP one mole of any gas has a volume of 22.4 liters. • STP stands for StandardTemperaturePressure • T = 0o C or 273 K P = 1.0 atmosphere • 14. 7 psi

  7. The Volume of one mole of GAS is equal to 22.4 liters @STP • The volume of one mole of iron is not equal to 22.4 liters @STP because iron is not a gas. • The volume of one mole of oxygen @STP is equal to 22.4 liters because oxygen is a gas.

  8. Pick the ones that have a molar volume = 22.4 Liters • Which of the elements below would have a molar volume equal to 22.4 liters @ STP? • Fe C N2 Cl2 S He

  9. So a mole diagram for a gas looks like this • With one thing added

  10. Use the diagram to find the volume of 7.0 grams of nitrogen

  11. HW #20 Page 188 Calculate the molar mass for each of the following substances. a. barium perchlorate d. copper(II) nitrate b. magnesium sulfate e. tin(IV) chloride c. lead(II) chloride f. phenol, C6H6O

  12. #21 • Change the 49.2 mg to 49.2 grams. • SO3 = 80 grams for one mole. • (49.2/ 80) = 0.614 moles Calculate the number of moles of the indicated substance in each of the following samples. a. 49.2 mg of sulfur trioxide b. 7.44 104 kg of lead(IV) oxide c. 59.1 g of chloroform, CHCl3 d. 3.27 g of trichloroethane, C2H3Cl3 e. 4.01 g of lithium hydroxide

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