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Find the area of a rectangle with l = 36 cm and w = 9 cm .

Find the area of a rectangle with l = 36 cm and w = 9 cm. A = lw. 324 cm 2. Find the area of a triangle with b = 23 cm and h = 14 cm. A = ½ bh. 161 cm 2. Find the area of a circle with r = 12 cm. A = p r 2. 452.2 cm 2. Find the missing measure. A = ?. 10.

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Find the area of a rectangle with l = 36 cm and w = 9 cm .

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  1. Find the area of a rectangle with l = 36 cm and w = 9 cm. A = lw 324 cm2

  2. Find the area of a triangle with b= 23 cm and h= 14 cm. A = ½bh 161 cm2

  3. Find the area of a circle with r= 12 cm. A = pr2 452.2 cm2

  4. Find the missing measure. A = ? 10 A = 2pr2 + s2 10 = 2p(52) + 102 = 50p + 100 ≈ 257 units2

  5. 12 12 A = (b1 + b2)h − bh = (11 + 17)(6) − 3(8) Find the missing measure. A = ? 9 3 11 = 84 − 24 8 3 = 60 units2

  6. Find the area of the colored region. 2 cm A = bh + bh A = 24 + 8 4 cm 8 cm = 32 cm2 3 cm

  7. 7 cm 5 cm 7 cm 5 cm Find the area of the colored region. A = s2 − s2 A = 72 − 52 = 24 cm2

  8. 12 12 A = bh − bh = 11(8) − (11)(4) 11 cm 8 cm 4 cm Find the area of the colored region. = 88 − 22 = 66 cm2

  9. 12 12 A = (b1 + b2)h − bh = (10 + 13)(6) −(9)2 10 m 2 m 9 m 6 m 13 m Find the area of the colored region. = 69 − 18 = 51 m2

  10. 4 m Find the area of the colored region. A = s2 − pr2 = 82 − p(42) = 64 − 16p ≈13.8 m2

  11. 34p2 23 = A C p = 34 B X Z p = ? Y Using the similar triangles, find the perimeter of ∆XYZ. 3 2p2 = 34(3) 2 2p2 = 102 p2 = 51 units

  12. 2 A136 ( ) 23 = X 3 Z A136 A = 36 Y 49 = A 2 C A = ? B Using the similar triangles, find the area of ∆ABC. 9A1 = 36(4) 9A1 = 144 A1= 16 units2

  13. At Fermilab in Batavia, Illinois, nuclear particles are accelerated around a circle that is 2 km in diameter. Determine the number of acres within this circular ring if 1 km2 = 247 acres. Round to the nearest acre. 776 acres

  14. If the sides of polygon A are twice the length of the sides in a similar polygon B, what is the ratio of their perimeters? their areas? perimeter 2:1; area 4:1

  15. Find the surface area and volume. 2 cm 8 cm S = pH + 2B 5 cm = [2(8 + 5)](2) + 2[8(5)] = 26(2) + 2(40) = 52 + 80 = 132 cm2 V = BH = [8(5)](2) = 80 cm3

  16. 4 m 7 m Find the surface area and volume. S = 2prH + 2pr2 = 2p(4)(7) + 2p(42) = 56p + 32p = 88p ≈ 276.3 m2 V = pr2H ≈ 351.7 m3 = p(42)(7) = = 112p

  17. 8 mm 6 mm 10 mm Find the surface area and volume. The altitude of 8 and half the base of the triangular end form a right triangle with hypotenuse c.

  18. 12 8 mm 6 mm 10 mm c = 73 Find the surface area and volume. c2 = 82 + b2, where b = s = 3 c2 = 82 + 32 = 73

  19. 12 12 8 mm 6 mm 10 mm = (2 73+ 6)(10) + 2[ (6)(8)] = [ (6)(8)](10) Find the surface area and volume. S = pH + 2B ≈ 23.1(10) + 48 ≈ 279 mm2 V = BH = 240 mm3

  20. 5 cm 4 cm 13 13 12 12 6 cm S = pl + B 6 cm = [4(6)](5)+ 62 V = BH = (62)(4) Find the surface area and volume. = 60 + 36 = 96 cm2 = 48 cm3

  21. 12 mm 13 mm 5 mm Find the surface area and volume. S = prl + pr2 = p(5)(13)+ p(52) = 65p + 25p = 90p ≈ 282.6 mm2

  22. 13 13 12 mm V = pr2H 13 mm = p(52)(12) 5 mm Find the surface area and volume. = 100p ≈314 mm3

  23. What is the volume of a cereal box 12 in. tall, 8 in. wide, and 2 in. thick? 192 in.3

  24. Find the volume of a waffle cone that is 15 cm tall and has a radius of 4 cm. 80 cm3≈ 251.2 cm3

  25. Give the mathematical significance of Genesis 6:22.

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