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# Potential and Kinetic Energy Problems

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1. Potential and Kinetic Energy Problems What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high?

2. Potential and Kinetic Energy Problems What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh

3. Potential and Kinetic Energy Problems What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh PE = 100N x 300m

4. Potential and Kinetic Energy Problems What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh PE = 100N x 300m PE = 30,000N*m

5. Potential and Kinetic Energy Problems What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high? PE = mgh PE = 100N x 300m PE = 30,000N*m PE = 30,000J

6. Potential and Kinetic Energy Problems 2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?

7. Potential and Kinetic Energy Problems KE = ½ mv2 2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?

8. Potential and Kinetic Energy Problems KE = ½ mv2 KE= ½ (14kg)(3m/s)2 2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? Square 1st

9. Potential and Kinetic Energy Problems KE= ½ mv2 KE= ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) 2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? Multiply 2nd

10. Potential and Kinetic Energy Problems KE= ½ mv2 KE= ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m 2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?

11. Potential and Kinetic Energy Problems KE= ½ mv2 KE= ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m 2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? Kg*m/s2

12. Potential and Kinetic Energy Problems KE= ½ mv2 KE= ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m 2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? Divide last

13. Potential and Kinetic Energy Problems KE= ½ mv2 KE= ½ (14kg)(3m/s)2 KE = ½ (14kg) (9m2/s2) KE = ½ 126 kg*m2/s2 = 126 N*m KE = 63 Joules 2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?

14. Potential and Kinetic Energy Problems 3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball?

15. Potential and Kinetic Energy Problems 3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE = ½ mv2

16. Potential and Kinetic Energy Problems 3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2

17. Potential and Kinetic Energy Problems 3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2x 2 2

18. Potential and Kinetic Energy Problems 3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2x 2 2 100kg*m2/s2 = (1kg)v2 1 kg 1kg

19. Potential and Kinetic Energy Problems 3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2x 2 2 100kg*m2/s2 = (1kg)v2 1 kg 1kg 100 m2/s2 = v2

20. Potential and Kinetic Energy Problems 3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball? KE= ½ mv2 50J = ½ (1kg)v2 2 x 50J = (1kg)v2x 2 2 100kg*m2/s2 = (1kg)v2 1 kg 1kg 100 m2/s2 = v2 10m/s = v

21. Potential and Kinetic Energy Problems 4. What is the potential energy of the rock?

22. Potential and Kinetic Energy Problems 4. What is the potential energy of the rock? Given in kg, not Newtons…must multiply mass times gravity

23. Potential and Kinetic Energy Problems 4. What is the potential energy of the rock? PE = mgh

24. Potential and Kinetic Energy Problems 4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m)

25. Potential and Kinetic Energy Problems 4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m) PE = 93,100 kg*m2/s2 kg*m/s2 = N *m

26. Potential and Kinetic Energy Problems 4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m) PE = 93,100 kg*m2/s2 kg*m/s2 = N *m PE = 93,100 N*m

27. Potential and Kinetic Energy Problems 4. What is the potential energy of the rock? PE = mgh PE = 95kg(9.8m/s2)(100m) PE = 93,100 kg*m2/s2 kg*m/s2 = N *m PE = 93,100 N*m PE = 93,100 J

28. Potential and Kinetic Energy Problems 5. What is the approximate difference in gravitational potential energy of the two shaded boxes?

29. Potential and Kinetic Energy Problems 5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh

30. Potential and Kinetic Energy Problems 5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg(9.8m/s2)(3.0m)

31. Potential and Kinetic Energy Problems 5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg(9.8m/s2)(3.0m) PE = 58.8 kg*m2/s2 or N*m

32. Potential and Kinetic Energy Problems 5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg(9.8m/s2)(3.0m) PE = 58.8 kg*m2/s2 or N*m PE = 58.8 J

33. Potential and Kinetic Energy Problems 5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh

34. Potential and Kinetic Energy Problems 5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg (9.8m/s2)(1.0m)

35. Potential and Kinetic Energy Problems 5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg (9.8m/s2)(1.0m) PE = 19.6 kg*m/s2 or N*m

36. Potential and Kinetic Energy Problems 5. What is the approximate difference in gravitational potential energy of the two shaded boxes? PE = mgh PE = 2.0kg (9.8m/s2)(1.0m) PE = 19.6 kg*m/s2 or N*m PE = 19.6 J

37. Potential and Kinetic Energy Problems 5. What is the approximate difference in gravitational potential energy of the two shaded boxes? 58.8J – 19.6J = 39.2J