1 / 32

Parabola

Parabola. Examples. Give four examples of equations of parabola all having the vertex (2,3), but one is facing upward, one downward, one to the right and one to the left. Identify the axis of symmetry. Solution. Vertex (2,3). Examples (1) – (4).

keon
Télécharger la présentation

Parabola

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Parabola

  2. Examples Give four examples of equations of parabola all having the vertex (2,3), but one is facing upward, one downward, one to the right and one to the left. Identify the axis of symmetry.

  3. Solution

  4. Vertex (2,3)

  5. Examples (1) – (4) Identify the parabola having the given equation and its axis of symmetry and graph it.

  6. Decide Which parabola have the following Equations & Graph:

  7. Decide Which Parabola have the Given Equations & Graph:

  8. Finding points of the graphx=2y2

  9. Decide Which Parabola have the Given Equations & Graph:

  10. Finding points of the graphx=-3(y-1)2+2

  11. What are the x-intercepts and the y-intercepts?

  12. Decide Which Parabola have the Given Equations & Graph:

  13. Finding points of the graphy=-x2-2x+15 = - (x+1) 2 + 16

  14. What are the x-intercepts and the y-intercepts?

  15. Decide Which Parabola have the Given Equations & Graph:

  16. Finding points of the graphx=-2y2+4x+5 = 2 (y+1) 2 + 3

  17. What are the x-intercepts and the y-intercepts?

  18. More Examples

  19. Example (1)Graph y=x2 - 6x + 7 The graph is facing upward. Why? y= x2 - 6 x + 7 = (x- 3 )2 – 9 + 7 = (x- 3 )2 – 2 The vertex of the parabola is (3 , - 2 ) The intersection with the y-axis is(0,7) y=x2 - 6x + 7 Why? The intersections with the x-axis: (3+√2 , 0 ) and (3-√2 , 0 ) Why?

  20. Example (2)Graph y=2x2 + 2x + 3 The graph is concave upward. Why? y=2[x2 +x] + 3 = 2[(x+½)2–¼] + 3 = 2(x+½)2–½ + 3 = 2(x+½)2 + 5/2 The vertex of the parabola is ( - ½ , 5/2 ) The intersection with the y-axis is (0,3) Why? No intersections with the x-axis: Why?

  21. Example (3)Graph y=-x2 - 4x + 12 The graph is concave downward. Why? y= -(x2 +4x ) + 12=-[(x+ 2 )2 – 4] + 12 = -(x+2)2 + 16 The vertex of the parabola is (-2 , 16 ) The intersection with the y-axis is (0,12) Why? y=-x2 - 4x + 12=-(x2 +4x - 12)=-(x+6)(x-2) The intersections with the x-axis: (2 , 0 ) and (-6 , 0 ) Why?

  22. QuestionDo it now!Do not see the next slide before you do it! Graph y=x2 + 2x - 3

  23. Solutiony=x2 +2x - 3 The graph is concave upward. Why? y=x2 +2x – 3 = = (x+1)2 – 1 – 3 = (x+1)2 - 4 The vertex of the parabola is (-1 , -4 ) The intersection with the y-axis is (0,-3) y = x2 + 2x - 3=(x+3)(x-1) why? The intersections with the x-axis: (-3 , 0 ) and (1 , 0 ) Why?

More Related