1 / 34

Solid/Liquid Systems

Solid/Liquid Systems. Phase Diagrams Phase Rule Lever Rule. LIQUID. T. SOLID. X B. COOLING CURVE. START. LIQUID. T. SOLID. FINISH. X B. COOLING CURVE. liquid cools. T. solid forms and cools. solid cools. time. COOLING CURVE. liquid cools. T. solid forms and cools.

kera
Télécharger la présentation

Solid/Liquid Systems

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. Solid/Liquid Systems Phase Diagrams Phase Rule Lever Rule

  2. LIQUID T SOLID XB

  3. COOLING CURVE START LIQUID T SOLID FINISH XB

  4. COOLING CURVE liquid cools T solid forms and cools solid cools time

  5. COOLING CURVE liquid cools T solid forms and cools solid cools time How do I know its shape???

  6. THE PHASE RULE F = C + 2 - P F = degrees of freedom ( How many variables? ) C = components P = phases

  7. S o l i d P Liquid 100 KPa Gas T 273K 373K

  8. This is a one component system as it contains only water. Therefore, F = 1 + 2  P = 3  P

  9. P = 1 F = 2 Pressure & T vary independantly S o l i d P Liquid 100 KPa Gas T 273K 373K

  10. On line P = 2 F = 1 Pressure or T can vary S o l i d P Liquid 100 KPa Gas T 273K 373K

  11. S o l i d P Liquid 100 KPa Gas At the triple point P = 3 and F = 0 Pressure and T are fixed. T 273K 373K

  12. LIQUID T SOLID XB

  13. This is a two component system as it contains two different compounds. Therefore, F = 2 + 2  P = 4  P I use up one degree of freedom by fixing the pressure. F = 3  P

  14. P = 1 F = 2 T and XB vary. LIQUID P = 2 F = 1 T SOLID P = 1 F = 2 T and XB vary. XB

  15. COOLING CURVE liquid cools T solid forms and cools solid cools time How do I know its shape???

  16. COOLING CURVE The temperature can vary because the compositions can change. liquid cools T solid forms and cools solid cools time

  17. LIQUID T SOLID XB A tie line

  18. A tie line At a given temperature, a tie line tells us what the compositions of the two phases are. It can also tell how much of each is present.

  19. A tie line At a given temperature, a tie line tells us what the compositions of the two phases are. It can also tell how much of each is present. The compositions of the phases are deteremined from the ends of the line. The amounts are determined from the Lever Rule.

  20. Lever Rule f f f This is a tie line for system expressed in mass fraction. f = mass fraction for whole system f  = mass fraction of the  phase f  = mass fraction of the  phase

  21. Lever Rule f f f The system balances like a lever: m f  f = m f  f  m is the mass of the phase.

  22. A bit more complicated? The NaCl / NaBr system.

  23. NaBr / NaCl at 101 325 Pa o C LIQUID 800 760 720 .25 .50 .75 XNaCl

  24. NaBr / NaCl at 101 325 Pa o C LIQUID 800 X 760 Y 720 Z .25 .50 .75 XNaCl

  25. THREE TIE LINES: X is pure NaCl Crystals in equilibrium with a solution of NaCl and NaBr. 50 mole % NaCl Y Z

  26. NaBr / NaCl at 101 325 Pa o C LIQUID 800 X 760 Y 720 Z .25 .50 .75 XNaCl

  27. THREE TIE LINES: X is pure NaCl Crystals in equilibrium with a solution of NaCl and NaBr. Y is pure NaBr Crystals in equilibrium with a solution of NaCl and NaBr. 25 mole % NaCl Z

  28. NaBr / NaCl at 101 325 Pa o C LIQUID 800 X 760 Y 720 Z .25 .50 .75 XNaCl

  29. THREE TIE LINES: X is pure NaCl Crystals in equilibrium with a solution of NaCl and NaBr. Y is pure NaBr Crystals in equilibrium with a solution of NaCl and NaBr. Z is pure NaCl crystals and pure NaBr crystals.

  30. NaBr / NaCl at 101 325 Pa o C LIQUID 800 ? 760 720 .25 .50 .75 XNaCl

  31. This point is called a EUTECTIC or minimum melting point. 28 mole % NaCl at 731 o C.

  32. NaBr / NaCl at 101 325 Pa TWO COOLING CURVES o C X LIQUID 800 Y 760 720 .25 .50 .75 XNaCl

  33. T The T falls because 2 phases give degree of freedom. time (x) T The T is fixed because there are 3 phases and zero degrees of freedom. time (y)

  34. NaBr / NaCl at 101 325 Pa TWO COOLING CURVES o C X LIQUID 800 Y 760 720 .25 .50 .75 XNaCl

More Related