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Literal Equations

Literal Equations. 2.5. Objective. Objective. To rewrite and use literal equations & formulas . Essential Understanding…. Essential Understanding…. We will use the methods we’ve learned in this chapter to isolate any particular variable. Term:. Literal Equation (page 109).

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Literal Equations

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  1. Literal Equations 2.5

  2. Objective

  3. Objective • To rewrite and use literal equations & formulas.

  4. Essential Understanding…

  5. Essential Understanding… • We will use the methods we’ve learned in this chapter to isolate any particular variable.

  6. Term: • Literal Equation (page 109)

  7. Term: • Literal Equation Equation that involves two or more variables.

  8. One thing I would do…

  9. One thing I would do… When creating an equation from a real world situation, I would use the first letter of each object as the variable;

  10. One thing I would do… When creating an equation from a real world situation, I would use the first letter of each object as the variable; that way, it might be easier for you to remember what each variable represents.

  11. What is different about these…

  12. What is different about these… • They contain more than 1 variable.

  13. What is different about these… • They contain more than 1 variable. • You will not get a final number answer;

  14. What is different about these… • They contain more than 1 variable. • You will not get a final numerical answer; instead your goal is to isolate the variable

  15. What is different about these… • They contain more than 1 variable. • You will not get a final number answer; instead your goal is to isolate the variable • Alone on either side of the equation.

  16. Keep your textbooks on page 109

  17. Keep your textbooks on page 109 • 10x + 5y = 80

  18. Keep your textbooks on page 109 • 10x + 5y = 80 Coefficients represent the cost of each item, while the constant on the right represents the total cost or the total amount of money you have.

  19. Your turn…

  20. Your turn… • Got it on the top of page 110 (a)

  21. Your turn… • Got it on the top of page 110 (a) • 4 = 2m – 5n for m 4 + 5n = 2m = m

  22. Your turn… • Got it on the top of page 110 (a) • = m Values: n = -2  m = -3 n = 0  m = 2 n = 2  m = 7

  23. Choices in life:

  24. Choices in life: • When doing the evaluating part of equations, you can either:

  25. Choices in life: • When doing the evaluating part of equations, you can either: (a) Use literal equation solving to isolatethe variable; then, plug in the value given and evaluate.

  26. Choices in life: • When doing the evaluating part of equations, you can either: (a) Use literal equation solving to isolatethe variable; then, plug in the value given and evaluate. OR

  27. Choices in life: • When doing the evaluating part of equations, you can either: (b) Plug in the value right away and solve.

  28. Choices in life: • When doing the evaluating part of equations, you can either: (b) Plug in the value right away and solve. I’ll show you what I mean with part B.

  29. 10x + 5y = 80

  30. 10x + 5y = 80 Literal

  31. 10x + 5y = 80 Literal 5y = 80 – 10x y = 16 – 2x x = 3  y = 16 – 6 = 10

  32. 10x + 5y = 80 Literal 5y = 80 – 10x y = 16 – 2x x = 6  y = 16 – 12 = 4

  33. 10x + 5y = 80 • Solving Equations Literal 5y = 80 – 10x y = 16 – 2x x = 6  y = 16 – 12 = 4

  34. 10x + 5y = 80 • Solving Equations 10x + 5y = 80 Literal 5y = 80 – 10x y = 16 – 2x x = 6  y = 16 – 12 = 4

  35. 10x + 5y = 80 • Solving Equations 10x + 5y = 80 x = 3 Literal 5y = 80 – 10x y = 16 – 2x x = 6  y = 16 – 12 = 4

  36. 10x + 5y = 80 • Solving Equations 10x + 5y = 80 x = 3 30 + 5y = 80 Literal 5y = 80 – 10x y = 16 – 2x x = 6  y = 16 – 12 = 4

  37. 10x + 5y = 80 • Solving Equations 10x + 5y = 80 x = 3 30 + 5y = 80 5y = 50 y = 10 Literal 5y = 80 – 10x y = 16 – 2x x = 6  y = 16 – 12 = 4

  38. 10x + 5y = 80 • Solving Equations 10x + 5y = 80 x = 6 60 + 5y = 80 5y = 20 y = 4 Literal 5y = 80 – 10x y = 16 – 2x x = 6  y = 16 – 12 = 4

  39. Formulas:

  40. Formulas: P 110

  41. Formulas: P 110 No need to memorize (at least this year)

  42. Formulas: P 110 No need to memorize (at least this year) but you do need to solve for the variable asked for.

  43. Example: P = 2l + 2w for w

  44. Need to get w isolated P = 2l + 2w for w

  45. Need to get w isolated P = 2l + 2w for w Subtract 2l from both sides

  46. Need to get w isolated P = 2l + 2w for w P – 2l = 2w Subtract 2l from both sides

  47. Divide both sides by w’s coefficient P = 2l + 2w for w P – 2l = 2w Subtract 2l from both sides

  48. Divide both sides by w’s coefficient P = 2l + 2w for w P – 2l = 2w Hint: when you divide by a coefficient, put the entire expression over it.

  49. Divide both sides by w’s coefficient P = 2l + 2w for w P – 2l = 2w Hint: when you divide by a coefficient, put the entire expression over it.

  50. Other hints:

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