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Bottom left corner at (0,0), rest of coordinates at (2, 0), (0, 2) and (2, 2)

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kira
12 diapositives · 296 Views · Sep 04, 2014

Bottom left corner at (0,0), rest of coordinates at (2, 0), (0, 2) and (2, 2) 9. Coordinates at (0,0), (0, 1), (5, 0) or (0,0), (1, 0), (0, 5) 10. Using Midpt Formula: E (0, 5) and F (6, 5) Distance Formula BC = 6 = EF 11. (0, 0), (0, 2m), (2m, 2m), (2m, 0)

#bottom left corner at (0,0), rest of coordinates at (2, 0), (0, 2) and (2, 2) #bottom left corner at (0,0), rest of coordinates at (2, 0), (0, 2) and (2, 2) ppt #powerpoint #presentation
Bottom left corner at (0,0), rest of coordinates at (2, 0), (0, 2) and (2, 2) - slide 1
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Bottom left corner at (0,0), rest of coordinates at (2, 0), (0, 2) and (2, 2)
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  1. Bottom left corner at (0,0), rest of coordinates at (2, 0), (0, 2) and (2, 2) • 9. Coordinates at (0,0), (0, 1), (5, 0) or (0,0), (1, 0), (0, 5) • 10. Using Midpt Formula: E (0, 5) and F (6, 5) Distance Formula BC = 6 = EF • 11. (0, 0), (0, 2m), (2m, 2m), (2m, 0) • 12. (0, 0), (0, x), (3x, x), (3x, 0) • 17. P = 2s + 2t units A = st square units • 18. (n, n) • 19. (p, 0) • 24. Distance Formula: KL = 2; MP = 2; LM = 3; PK = 3 KM = KM (Reflex) SSS • 25. You’re assuming figure has rt angle • 26. a. BD = 38 in. CE = 24 in. • b. B (24, 0) C (24, 28) D(24, 38) E(0, 38) • 38. 112 • 39. 22

  2. Warm Up • 1. Find each angle measure. • True or False. If false explain. • 2. Every equilateral triangle is isosceles. • 3. Every isosceles triangle is equilateral. 60°; 60°; 60° True False; an isosceles triangle can have only two congruent sides.

  3. Recall that an isosceles triangle has at least two congruent sides. The congruent sides are called the legs. The vertex angle is the angle formed by the legs. The side opposite the vertex angle is called the base, and the base angles are the two angles that have the base as a side. 3 is the vertex angle. 1 and 2 are the base angles.

  4. The length of YX is 20 feet. Explain why the length of YZ is the same. Reading Math The Isosceles Triangle Theorem is sometimes stated as “Base angles of an isosceles triangle are congruent.” Example 1: The mYZX = 180 – 140, so mYZX = 40°. Since YZXX,∆XYZ is isosceles by the Converse of the IsoscelesTriangle Theorem. Thus YZ = YX = 20 ft.

  5. Example 2A: Finding the Measure of an Angle Find mF. mF= mD = x° Isosc. ∆ Thm. mF+ mD + mA = 180 ∆ Sum Thm. Substitute the given values. x+ x + 22 = 180 Simplify and subtract 22 from both sides. 2x= 158 Divide both sides by 2. x= 79 Thus mF = 79°

  6. Example 2B: Finding the Measure of an Angle Find mG. mJ= mG Isosc. ∆ Thm. Substitute the given values. (x+ 44) = 3x Simplify x from both sides. 44= 2x Divide both sides by 2. x= 22 Thus mG = 22° + 44° = 66°.

  7. The following corollary and its converse show the connection between equilateral triangles and equiangular triangles.

  8. Example 3A: Using Properties of Equilateral Triangles Find the value of x. ∆LKM is equilateral. Equilateral ∆  equiangular ∆ The measure of each  of an equiangular ∆ is 60°. (2x + 32) = 60 Subtract 32 both sides. 2x= 28 Divide both sides by 2. x= 14

  9. Example 3B: Using Properties of Equilateral Triangles Find the value of y. ∆NPO is equiangular. Equiangular ∆  equilateral ∆ Definition of equilateral ∆. 5y – 6 = 4y + 12 Subtract 4y and add 6 to both sides. y= 18

  10. Remember! 1 2 A coordinate proof may be easier if you place one side of the triangle along the x-axis and locate a vertex at the origin or on the y-axis. Example 4: Using Coordinate Proof Prove that the segment joining the midpoints of two sides of an isosceles triangle is half the base. Given: In isosceles ∆ABC, X is the mdpt. of AB, and Y is the mdpt. of AC. Prove:XY = AC.

  11. Example 4 Continued By the Midpoint Formula, the coordinates of X are (a, b), and Y are (3a, b). By the Distance Formula, XY = √4a2 = 2a, and AC = 4a. Therefore XY = AC. 1 2 Proof: Draw a diagram and place the coordinates as shown.

  12. 12. Angle add. mATB = 40°. mBAT = 40° (Alt Int s) ATB  BAT (def of ) Since ΔABT is isos by converse of isos Δ thm, BT = BA = 2.4 mi • 13. 69° 33. 20 • 33° 34. 3 • 15. 130° or 172° 40. Two sides of a Δ are  iff the s • 16. 31 ° opp. those sides are  • 17. 92 • 18. 48 • 19. 26 • 20. 20 • 28. m1= 58°; m2 = 64°; m3 = 122° • 29. m1= 127°; m2 = 26.5°; m3 = 53° • 30.