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Ch 5.2

Ch 5.2. Definite Integrals. Ch 5.2 Introduction. In 5.1 (the last section) we used MRAM, LRAM, and RRAM to approximate area. You will hear these referred to as Reimann Sums (named after Georg Freidrich Riemann) In 5.2 we find exact area, using “The Definite Integral”.

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Ch 5.2

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  1. Ch 5.2 Definite Integrals

  2. Ch 5.2 Introduction • In 5.1 (the last section) we used MRAM, LRAM, and RRAM to approximate area. • You will hear these referred to as Reimann Sums (named after Georg Freidrich Riemann) • In 5.2 we find exact area, using “The Definite Integral”

  3. Review of Sigma Notationfrom PreCalc/ALG 2 Sigma Notation enables us to express a large sum in compact form Where to end Where to begin

  4. Revisiting EX 1 from 5.1 A particle starts at x = 0 and moves along the x-axis with velocity v(t) = t² for t ≥ 0. When is the particle at t = 6? We had set up a midpoint approximation with 3 intervals of length 2. We could write the following: (2)

  5. What happens as the number of rectangles increases?We get a more and more accurate approximation of the area under the curve.

  6. *The Definite Integral is a Limit of Riemann Sums* Let f be a continuous function defined on a closed interval [a, b], partitioned into n subintervals of equal length Δx = (b-a)/n. Let the numbers be chosen arbitrarily in the kth interval. Then: The function is the integrand “Integral Sign” Upper limit of integration Differential (the variable of integration) Lower limit of integration *When you find the value of the integral you have evaluated the integral

  7. EX 2: Using the Notation The interval [-1,3] is partitioned into n subintervals of equal length Δx. Let denote the midpoint of the kth subinterval. Express the limit As an integral.

  8. You Try! #2-6 even on your classwork

  9. THM 1: The Existence of Definite Integrals All continuous functions are integrable. That is, if a function f is continuous on an interval [a,b], then its definite integral over [a,b] exists.

  10. How do I evaluate an “Integral”? In this chapter you will do it two different ways depending on the problem: • By the graph:calculating area based on geometric shapes which you already know the area for – but be careful with negative velocity. If f(x) ≤ 0, • By the antiderivative = = f(b) – f(a) a) b) EX 3: Evaluating with both methods

  11. What if the entire curve is below the x-axis? DEF PG 279: If an integrable function y = f(x) is nonpositive, the nonzero terms f()Δx in the Riemann sums for f over an interval [a, b] are negatives of rectangle areas. The limit of the sums, the integral of f from a to b, is therefore the negative of the area of the region between the graph of f and the x-axis.

  12. What if the function y = f(x) has both positive and negative values on the interval [a, b]? Then the Riemann sums for f on [a, b] add areas of rectangles that lie above the x-axis to the negatives of areas of rectangles that lie below the x-axis. ***The resulting cancellations mean that the limiting value is a number whose magnitude is less than the total area between the curve and the x-axis. This is why the integral is sometimes called referred to as net area of the region ***

  13. You Try! #8-12 even on your Classwork THM 2: The Integral of a Constant If f(x) = c where c is a constant, on the interval [a, b], then:

  14. EX 4: Evaluating an integral with area

  15. You Try! classwork # 14-22evenEVALUTE WITH AREAAAAA

  16. Properties of Integrals • Order of integration Rule: = - • Constant Multiple Rule: = k • Sum and Difference Rule: =

  17. Exploration 1 1 -2 0 2pi + 2 2 4 0 0 4

  18. Finish the classwork! • 5.2 In-Class Groupwork:pg 282 EX #2-28 even, 34, 40 • 5.2 HW: pg 283 EX #13-27odd, 33, 35, 39,

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