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Geometry Problem-Solving Techniques and Formulas for Area and Volume Calculations

Learn various geometry problem-solving techniques and formulas for calculating areas and volumes of shapes such as circles, pyramids, and more in this comprehensive guide. Understand concepts like circumference, surface area, and ratios. Explore how to apply mathematical principles to solve questions effectively.

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Geometry Problem-Solving Techniques and Formulas for Area and Volume Calculations

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  1. Contributing ProjectPg.526, 532, 542, 548 and 549 By : Ahmad Bassam Class: 7D Date: April 30 – May 1

  2. Pg. 526 Questions: 33-34

  3. Question 33: • Solution: 4+2+2=86+2+2=10 0.5(b1+b2)*h=area Side: (4+8)/2)*2=12 in2 Bottom: (6+10)/2)*2=16 in2 Ratio: 16 in2 for the bottom: 12 in2 for the side 2 8 4 2 6 10

  4. Question 34: • 2n*2n=4n Area is 4n 2n 2n 2n 2n

  5. Pg.532 Questions 28, 29, and 33

  6. Question 28 • To solve this problem do the opposite: • 1473/3.14=469.10 • Square root of 469.10= 21.65 • 2.65 *2=43.3 is the diameter

  7. Question 29 • 58 is the length of the arm which is the radius • First find the circumference: d*pie=c • (58+58)*3.14= 364.24 • Then multiply it by the number of laps per minute: 50 • 364.2412*50= 18,212 round= 18,200ft

  8. Question: 33 • A) 12*12*3.14=452 inch • B)7850

  9. Pg.542 Question 12 and 17

  10. Question 12: • The Surface Area: 2*pie*r*r+2*pie*r*h=318.71cm

  11. Question 17: • A) The area will get 8 times bigger when height and radius are doubled. • B) The circumference will be double when height and radius are doubled. • C)It will be quadrupled when height and radius are doubled.

  12. Pg.548 Question 28

  13. Question 28: • Surface area of a pyramid is: the area of each triangle times 4 plus the area of base • The triangles:.5*74*48=1776*4=7,104 • The base: 74*74=5476 • Add them together: 7104+5476= 12,580 ft2

  14. Pg.549 Question 30

  15. Question 30: • A)Don’t know • B) Don’t know • I didn’t understand them

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