1 / 6

SYSTEMS of EQUATIONS WORD PROBLEMS

SYSTEMS of EQUATIONS WORD PROBLEMS. A farmer grows only pumpkins and corn on her 420-acre farm. This year she wants to plant 250 more acres of corn than pumpkins. How many acres of each crop should the farmer plant?. Let x = pumpkins Let y = corn

kristy
Télécharger la présentation

SYSTEMS of EQUATIONS WORD PROBLEMS

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. SYSTEMS of EQUATIONS WORD PROBLEMS

  2. A farmer grows only pumpkins and corn on her 420-acre farm. This year she wants to plant 250 more acres of corn than pumpkins. How many acres of each crop should the farmer plant? • Let x = pumpkins • Let y = corn • Group acres with acres and crops with crops

  3. x + y = 420 The number of acres for pumpkins and the acres for corn x + 250 = y There are 250 more acres of corn than there are pumpkins x+ x + 250 = 420 substitute x + 250 for y in the first equation 2x + 250 = 420 Combine like terms 2x = 170 Subtract 250 from both sides x = 85 There are 85 acres of pumpkins 420 – 85 There are 335 acres of corn

  4. A perfume maker has stocks of two perfumes on hand. Perfume A sells for $15 per ounce. Perfume B sells for $35 per ounce. How much of each should be combined to make a 3-oz bottle of perfume that can be sold for $63.

  5. A + B = 3 Ounces of each bottle of perfume $15A + $35B = $63 The prices of each bottle to make the new bottle A = 3 – B Isolate one of the values 15(3-B) + 35B = 63 Substitute the value of A for A 45 – 15B + 35B = 63 Distribute the 15 45 + 20B =63 Combine like terms 20B = 18 Subtract 45 from both sides B = .9 Divide both sides by 20 A + .9 = 3 Substitute .9 for B A = 2.1 Subtract .9 from both sides Final Answer 2.1 of Perfume A .9 of Perfume B

  6. YOUR TURN

More Related