1 / 21

MALVINO

MALVINO. Electronic. PRINCIPLES. AC Models. Chapter 9. X C. R. R. R. SHORT. OPEN. The coupling capacitor. {. Good coupling: X C < 0.1 R. 1. For ac analysis, the capacitor is a short. 2. For dc analysis, the capacitor is open. +30 V. 5 k W. 1 M W. b dc = 100. 100 k W.

lane
Télécharger la présentation

MALVINO

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. MALVINO Electronic PRINCIPLES

  2. AC Models Chapter 9

  3. XC R R R SHORT OPEN The coupling capacitor { Good coupling: XC < 0.1 R 1. For ac analysis, the capacitor is a short. 2. For dc analysis, the capacitor is open.

  4. +30 V 5 kW 1 MW bdc = 100 100 kW 100 mV A base-biased amplifier with capacitive coupling A dc analysis reveals IB = 30 mA, IC = 3 mA and VC = 15 V.

  5. IB 30 mA t IC 3 mA t VC 15 V t

  6. + 15 V 0 +0.7 V 0 +30 V 5 kW 1 MW bdc = 100 100 kW 100 mV The base-biased amplifier with voltage waveforms

  7. A = 200 The voltage gain of an amplifier is the ac output divided by the ac input. vin vout vout A = vin

  8. The bypass capacitor Ac ground R XC Good bypassing: XC < 0.1 R

  9. +6.04 V +1.8 V 0 +1.1 V 0 A VDB amplifier with voltage waveforms +10 V 3.6 kW 10 kW 100 kW 2.2 kW 1 kW 100 mV

  10. +5.32 V 0 0 -0.7 V 0 A TSEB amplifier with voltage waveforms +10 V 3.6 kW 100 kW 100 mV 2.7 kW 1 kW -2 V

  11. IE Q VBE Input signal Large-signal operation produces distortion

  12. ie IE IEQ = 10 mA Less than 1 mA VBE Total emitter current: IE = IEQ + ie Small-signal operation: ie(PP) < 0.1IEQ

  13. The dc current gain is given as: IC bdc = IB The ac current gain is given as: ic ib bac = Use capital letters for dc quantities and lowercase letters for ac.

  14. IE VBE The size of the ac emitter current depends on the Q point.

  15. Total emitter current: IE = IEQ + ie Total base-emitter voltage: VBE = VBEQ + vbe The ac resistance of the emitter diode is defined as: vbe re’ = ie

  16. vbe re’ = ie IE Larger ie Smaller ie VBE Note that re’ varies with the operating point. This implies that re’ is a function of the dc emitter current.

  17. A very useful formula: 25 mV re’ = IE

  18. vbe zin(base) = ib iere’ zin(base) = ib The T model of a transistor: ic vbe = iere’ zin(base) ib re’ ie zin(base) = bre’

  19. The p model of a transistor is based on zin(base) = bre’ : ib zin(base) bre’ ic ie

  20. Amplifier analysis • Perform a complete dc analysis • Short all coupling and bypass capacitors • Visualize all dc supply voltages as ac grounds • Replace the transistor by its p or T model • Draw the ac equivalent circuit

  21. Data sheets • The four h parameters are traditional • hfe is the ac current gain • hie is equivalent to input impedance • bac = hfe • re’ = hie/hfe • hre and hoe are not needed for basic design and troubleshooting

More Related