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Drip Irrigation System Layout Design

ADVANTAGES. Water savingsCrop responseLabour savingsFertilizer savingsLess weed growth. Drip Irrigation System Layout

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Drip Irrigation System Layout Design

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    1. Drip Irrigation System Layout & Design

    2. ADVANTAGES Water savings Crop response Labour savings Fertilizer savings Less weed growth

    3. Saving in pesticides Possible use of saline water Early maturation Minimum soil crusting Field edge loss reduction ADVANTAGES

    4. Improved root penetration Irrigation of low intake soils Easy field operation ADVANTAGES

    5. LIMITATIONS Sensitivity to clogging Salinity hazards Moisture distribution problems High initial cost Dry soil & dust formation

    6. High skill required for Design Installation Operation Maintenance LIMITATIONS

    7. SYSTEM COMPONENTS Selection criteria General suitability Pressure flow characteristics Manufacturing variability

    8. Sensitivity to temperature Resistance to clogging Cost Risk SYSTEM COMPONENTS

    9. Types - Orifice emitter q = C A - Tube emitter q = 0.034 h.78 - Labyrinth emitter q = 0.125 h.78 SYSTEM COMPONENTS

    11. SYSTEM COMPONENTS (Contd.) Lateral lines Sub mains Main lines Mani folds Filters

    12. PROBLEMS IN FILTRATION Physical contamination Chemical contamination Effect of water source Fitness of filtration

    13. FILTERING EQUIPMENT & METHODS Pressure regulators Control valves Misc. fittings

    17. DESIGN Amount of water to apply q = C U . A. sc qm = Where : qm is av. Emitter discharge in lph H is total hr. of operation/day N is nos. of emitters/ plant q = C U . SI . Sm. sc

    18. Spacing of emitters Radius of coverage R = Max. spacing Sl X Sm DESIGN

    19. Uniformity of water distribution Flow variation < 20% Pressure variation < 20% DESIGN

    20. Lateral & mainlines Hazen William iq. H = 15.25 X L H = 5.35 (In decreasing flow lines) DESIGN

    21. DESIGN CHARTS Lateral for uniform slopes Lateral for non-uniform slopes Sub-main Main

    22. Example 1 GIVEN : L = 50 m H = 10 m S = 1% Emitter spacing = 0.3 m q = 4 lph / emitter

    23. FIND: Lateral dia. L/H = 5 Q = 4 X 150 = 600 lph = 0.167 lps FIG. 6 (a) 12 mm is acceptable Example 1

    24. Example 2 GIVEN: L = 120 m Dia = 16 mm H = 10 m Q = 0.13 lps

    25. SLOPE: 0 30 3% down 30 60 2% down 60 90 0% 90 120 3% down Example 2

    26. SOLUTION: I/L HI (m) HI/ L 0.25 0.9 0.0075 0.5 1.5 0.0125 0.75 1.5 0.0125 1 2.4 0.02 Example 2

    27. Plot I/L vs. HI/ L OHP 12 H = 5.35 X L = Example 2

    28. = 1.5 m = = .15 L/H = 120/10 = 12 Example 2

    29. Check pressure variation at 4 points at I/L 0.25, 0.5, 0.75, 1. Fig 8 Variations are (QD III) Less than 10% Example 2

    30. Example 3 GIVEN: A= 20 ha Fig 11 Subplot = 0.4 ha Q = 2 lps / subplot

    31. Fig 12, Plot mainline profile Plot reqd. pressure head Plot energy line Use Fig 10 OHP 14 with S = 1 % Find dia of mainline Table 5 Example 3

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