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Oxidation-Reduction Reactions (Redox). What is the difference between acid/base reactions and redox reactions?. Acid/base reactions proton transfer (p + ) Redox reactions electron transfer (e - ). Flow of electrons.
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Oxidation-Reduction Reactions (Redox)
What is the difference between acid/base reactions and redox reactions? • Acid/base reactions • proton transfer (p+) • Redox reactions • electron transfer (e-)
Flow of electrons • Electrons respond to differences in potential by moving from the region of high potential to the region of low potential. High Ep Low Ep e- - +
Flow of electrons low electronegativity high electronegativity e- Cl Li Lithium loses the e- tug-of-war with chloride.
Terminology • Cations: • positively charged ions • generally metals • NH4+ is the exception • Anions: • negatively charged ions • non-metals • complex ions
Oxidation: • When a substances loses e-. • Reduction: • When a substance gains e-.
oxidized reduced
Ca(s) + 2H+(aq) Ca2+(aq) + H2(g) • Ca(s) has lost two e- to 2 H+(aq) to become Ca2+(aq). Ca(s) has been oxidized to Ca2+(aq) • At the same time 2 electrons are gained by 2 H+(aq) to form H2(g) . We say H+(aq) is reduced to H2(g) .
Half-reactions • Ca(s)→ Ca2+(aq) + 2e- • Oxidation half reaction • 2H+(aq) + 2e- → H2(g) • reduction half reaction
Half-reactions add together Ca(s)→ Ca2+(aq) + 2e- 2H+(aq) + 2e- → H2(g) Ca(s) +2H+ + 2e-Ca2+ + 2e- +H2(g) Ca(s) +2H+(aq)Ca2+(aq)+H2(g) +
Half-reactions add together Cu(s)→ Cu2+(aq) + 2e- Ag+(aq) + e- → Ag(s) Cu(s) +2Ag+(aq) + 2e-Cu2+(aq) + 2e- +2Ag(s) Cu(s) +2Ag+(aq) Cu2+(aq)+2Ag(s) + ( ) x 2
Electron Transfer and Terminology • Lose Electrons: Oxidation • Gain Electrons: Reduction. OIL - OXIDATION IS LOSS OF ELECTRONS RIG - REDUCTION IS GAIN OF ELECTRONS
Iron • Iron comes from iron ore which is taken out of the ground by mining. • The pure iron is obtained by heating the ore at very high temperatures in a furnace with limestone to remove impurities. • The molten iron is taken out of the bottom of the furnace. It is further processed depending on how it is to be used.
Why is gaining electrons called reduction? • Reduction originally meant the loss of oxygen from a compound. • 2Fe2O3(s) + C(s)→ 4Fe(s) + 3CO2(g) • Iron ore is reduced to metallic iron. The size of the pile gets smaller, hence the word reduction.
Why is losing electrons called oxidation? • Oxidation originally meant the combination of an element with oxygen. • 4Fe(s) + 3O2(g)→ 2Fe2O3(g) C(s) + O2(g) → CO2(g)
It Takes Two: Oxidation-Reduction • In all reduction-oxidation (redox) reactions, one species is reduced at the same time as another is oxidized.
It Takes Two: Oxidation-Reduction Oxidizing Agent: • the species which causes oxidation is called the oxidizing agent. • substances that gains electrons • the oxidizing agent is always reduced
It Takes Two: Oxidation-Reduction • Reducing Agent: • the species which causes reduction is called the reducing agent. • the reducing agent is always oxidized. • substances that give up electrons
Example Cu(s) + 2 Ag+(aq)→ Cu2+(aq) + Ag(s) oxidated reduced R.A. O.A.
Summary: Redox Theory • A redox reaction is a chemical reaction in which electrons are transferred. • Number of electrons lost by one species equals number of electrons gained by the other species. • Reduction is a process in which e- are gained. • Oxidation is a process in which e- are lost • A reducing agent donates e- and is oxidized. • A oxidizing agent gains e- and is reduced. WS 15-1
Only one of these two reactions is possible. Which one? Cu(s) + 2 Ag+(aq)→ Cu2+(aq) + 2 Ag(s) Cu2+(aq) + 2 Ag(s) → Cu(s) + 2 Ag+(aq) Data table values EO, page 7 of your data books. 1) Cu(s) -- >> Cu 2+(aq) + 2 e- -0.34 EO ( R) 2) Ag +(aq) + e- -- >> Ag(s) +0.80 EO 1) Cu 2+(aq) + 2e- -- >> Cu (s) + 0.34 EO 2) Ag (s) -- >> Ag +(aq) + e-- 0.80 EO (R)
Electric potential (V), Eo • the electric potential under standard conditions of a half-reaction in which reduction is occurring. • Standard conditions: • 25oC with all ions at 1 M concentrations and all gases at 1 atm pressure
Standard Reduction Potentials • We cannot measure the potential of an individual half-cell! • We assign a particular cell as being our reference cell and then assign values to other electrodes on that basis.
The Standard Hydrogen electrode • Eo (H+/H2) half-cell = 0.000 V e- p{H2(g)} = 1.00 atm H2 (g) [H+] = 1.00 Pt gauze
Electric potential (V), Eo • If the net potential is a positive number then the reaction is spontaneous. • If the net potential is a negative number then the reaction is non-spontaneous. • Half cell potentials are not doubled or tripled as per balancing. We are only comparing potentials.
Cu2+(aq) + 2Ag(s)→ Cu(s) + 2Ag+(aq) Cu2+ + 2e- → CuEo = 0.34 2Ag → 2Ag+ + 2e- Eo = -0.80 Cu2+(aq) + 2Ag(s)→ Cu(s) + 2Ag+(aq) Eo = -0.46 Negative potential, non-spontaneous Compare the two half reactions that make up the reaction. +
Cu(s) + 2Ag+(aq)→ Cu2+(aq) + 2Ag(s) Cu(s)→ Cu2+ + 2e- Eo = -0.34 2Ag+ + 2e- → 2AgEo = 0.80 Cu(s) + 2Ag+(aq)→ Cu2+(aq) + 2Ag(s) Eo = 0.46 Positive potential, spontaneous Compare the two half reactions that make up the reaction.
Problem • Write the oxidation/reduction half reactions and the net ionic equation when zinc is placed in Ni(NO3)2 solution. Identify the O.A. and R.A. and state if the reaction is spontaneous or non-spontaneous.
Problem A piece of zinc is placed in a solution of nickel nitrate Ni(NO3)2 Spectator ion • Ni(NO3)2→ Ni2+(aq) + 2NO3- (aq) Zn(s) + Ni2+(aq) → ? • Oxidation: Zn(s) → Zn2+(aq) + 2e- +0.76 • Reduction: Ni2+(aq) + 2e- → Ni(s) - 0.26 Add half reactions
Problem Zn is Oxidized Zn(s) + Ni2+(aq) → Zn2+(aq) + Ni(s)+0.50 Ni2+ is Reduced R.A. O.A. Positive potential, spontaneous
NOTE*** Spontaneous shortcut • Locate the O.A. on the left and the R.A. on the right of the table. • If the O.A. is higher up on the table than the R.A. then the reaction is spontaneous. O.A. R.A. O.A. R.A. SPONTANEOUS REACTION NON-SPONTANEOUS REACTION
highest attraction for electrons weak attraction for electrons
Problem • Explain what happens when nickel is placed in a zinc nitrate solution. Ni(s) + Zn2+(aq)→ ? + ? REDUCING AGENT OXIDIZING AGENT ARE ON LEFT SIDE O.A. R.A. NICKEL Ni ZINC NITRATE Zn2+ and NO3 -
Ni(s) Zn2+(aq) R.A. is above the O.A. On the table NON SPONTANEOUS
Disproportionation redox reactions where the OA and the RA are the same species. ( p 577 – text) Example: Fe2+ (aq) and Fe 2+ (aq) Fe2+ (aq) + 2 e - Fe (s) reduction of Fe2+ 2[ Fe2+ (aq) Fe3+(aq) + e - ]oxidation of Fe2+ 3 Fe 2+(aq) Fe(s) + 2 Fe3+(aq) net reaction NON – SPONTANEOUS REACTION
DISPROPORTIONATION TRY THE REACTION WHERE Cu 1+ ACTS AS THE OXIDIZING AND REDUCING AGENTS TRY THE REACTION WHERE Cr2+ ACTS AS THE AS THE OXIDIZING AND REDUCING AGENTS
Predicting redox reactions • List all species present. • Choose the strongest oxidizing and reducing agent. • Write the reduction half reaction, as written in the data book. • Write the oxidation half reaction, reverse the equation in the data book. • Balance number of electrons. • Add the two half reactions together to form the net ionic equation. • Predict if reaction is spontaneous or not.
Problems • A mixture of bromine gas and chlorine gas is added to a solution of copper (II) sulphate and a copper strip. (water) ( CuSO4) (Br2(g)) (Cl2(g) ) ( Cu(s) ) • NOTE( Go down S.O.A. / Go up S.R.A.) Is the reaction spontaneous? Cl2(g) + 2e-→ 2 Cl-(aq) Cu(s)→ Cu2+(aq) + 2e- Br2(g) Cl2(g) H20(l) Cu2+(aq) Cu(s) SOA * Cl2(g) + Cu(s) → 2 Cl-(aq) + Cu2+(aq) SRA * SPONTANEOUS
Problems Is the reaction spontaneous? • Lead is placed in a zinc nitrate solution.(list species) NO3-(aq) H20(l) Zn2+(aq) Pb(s) Non-spontaneous OA is below RA Zn2+(aq) + 2e- Zn (s) SOA Pb(s) Pb 2+(aq) + 2e- SRA R.A. Zn2+(aq) + Pb(s) Zn(s) + Pb2+ O.A.
Problems • A few drops of Hg(l) are dropped into a solution which is 1.0 M in both sulphuric acid and potasium permanganate. MnO4-(aq) SO42-(aq) H20(l) K+(aq) Hg(l) H+(aq) OA Is the reaction spontaneous? H+ hydrogen ion (From acid) O.A. RA R.A YES
Problems • A few drops of Hg(l) are droped into a solution which is 1.0 M in both sulphuric acid and potasium permanganate. ( ) x2 MnO4-(aq) + 8 H+(aq) + 5e-→ Mn2+(aq) + 4 H2O(l) Hg(l)→ Hg2+(aq) + 2e- ( ) x5 Oxidized 2MnO4-(aq) + 16H+(aq) + 5Hg(l) → 2Mn2+(aq) + 8H2O(l) + 5Hg2+(aq) (Balance electrons) LHS = RHS
General Rules • Metal (+) ions are oxidizing agents. • Nonmetal (-) ions are reducing agents. • Metal elements are reducing agents. • Nonmetal elements are oxidizing agents.