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CHEM 1011. Calorimetry: The Determination of the Specific Heat of a Metal. Calorimetry. Calorimetry – the science of measuring heat transfer. Calorimetry. Principle of Conservation of Energy-

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## CHEM 1011

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**CHEM 1011**Calorimetry: The Determination of the Specific Heat of a Metal**Calorimetry**• Calorimetry – the science of measuring heat transfer.**Calorimetry**• Principle of Conservation of Energy- Energy can neither be created nor destroyed in any process, but can be transferred from one part of a system to another**Calorimetry**• Calorimeter – device used to measure heat – calorimeter cup and thermometer.**Calorimetry**• Specific heat – the amount of heat needed to raise temperature of 1 g of a substance 1° C. • Specific heat is an intensive property.**Calorimetry**• Specific heat values are generally lower for metals and higher for non-metals (see Table 9.1).**Calorimetry**• When a given mass of a substance undergoes a temperature change, the equation showing the relationship between quantity of heat, specific heat, mass, and temperature change is Q = SH x m x ΔT ΔT = Tfinal - Tinitial**Calorimetry**• Heat lost by one substance is equal to the heat gained by the other. Qlost = Qgained**Heat Capacity of the Calorimeter**• Because calorimeter absorbs heat, must calculate Ccal.**Heat Capacity of the Calorimeter**• Construct graph and extrapolate maximum temperature.**Heat Capacity of the Calorimeter**ΔT of cold water and calorimeter = (5) – (3)**Heat Capacity of the Calorimeter**ΔT of warm water = (5) – (4)**Heat Capacity of the Calorimeter**Heat lost by warm water = (2) x 1.00cal/gºC x (7)**Heat Capacity of the Calorimeter**Heat gained by cold water & calorimeter = - (8)**Heat Capacity of the Calorimeter**Heat gained by cold water = (1) x 1.00cal/gºC x (6)**Heat Capacity of the Calorimeter**Heat gained by the calorimeter = (9) – (10)**Heat Capacity of the Calorimeter**Heat capacity of calorimeter, Ccal = (11) / (6)**Specific Heat of a Metal**Mass of metal = (3) – (2)**Specific Heat of a Metal**• Construct graph and extrapolate maximum temperature.**Specific Heat of a Metal**ΔT of cold water and calorimeter = (7) – (5)**Specific Heat of a Metal**Heat gained by calorimeter and water = [(1) x 1.00cal/gºC x (8)] + [Ccal x (8)]**Specific Heat of a Metal**ΔT of the metal = (7) – (6)**Specific Heat of a Metal**Heat lost by the metal = - (9)**Specific Heat of a Metal**Specific heat of the metal = (11) / [(4) x (10)]**Specific Heat of a Metal**• According to the Law of Dulong and Petit, SHmetal x gram atomic mass = 6.3 cal/moleºC • Rearranged, it becomes gram atomic mass = 6.3 cal/moleºC / SHmetal**Specific Heat of a Metal**Atomic mass = 6.3 cal/moleºC / (12)

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