1 / 6

4.7 Stoichiometry of Precipitation Reactions

4.7 Stoichiometry of Precipitation Reactions. Section 4.7 Stoichiometry of Precipitations. Show the complete dissociation of each of the following compounds in water and determine how many moles of each ion are in each of the following: a. 4.0 moles of sodium carbonate dissolved in water

lula
Télécharger la présentation

4.7 Stoichiometry of Precipitation Reactions

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript

  1. 4.7 Stoichiometry of Precipitation Reactions

  2. Section 4.7 Stoichiometry of Precipitations • Show the complete dissociation of each of the following compounds in water and determine how many moles of each ion are in each of the following: • a. 4.0 moles of sodium carbonate dissolved in water • b. 46.5 g of rubidium fluoride dissolved in water • c. 9.32 x 1021atoms of iron (III) chloride dissolved in water • d. 7.8 moles of ammonium sulfate dissolved in water

  3. Problem: How many moles of each ion are in each of the following: • a. 4.0 moles of sodium carbonate dissolved in water MolNa+ = ? 2 mol Na+ 4.0 mol Na2CO3 X ------------------ = 1 mol Na2CO3 2 : 1 ratio 8.0 mol Na+ and 4.0 mol CO32- are present

  4. Problem: How many moles of each ion are in each of the following: • b. 46.5 g of rubidium fluoride dissolved in water MolRb+ = ? 1 molRbF 1 molRb+ 46.5 g RbF X ------------------ X ------------ = 104.47 g RbF 1 molRbF 1 : 1 ratio 0.445 molRb+ and 0.445 mol F- are present

  5. Problem: How many moles of each ion are in each of the following: • c. 9.32 x 1021atoms of iron (III) chloride dissolved in water MolFe3+ = ? 1 molFeCl3 1 mol Fe3+ 9.32 X 1021atoms FeCl3 X ------------------ = X ------------ 6.022 X 1023 atoms FeCl3 1 mol FeCl3 1:3 ratio 0.0155 mol Fe3+ and 0.0465 molCl-are present

  6. Problem: How many moles of each ion are in each of the following: • d. 7.8 moles of ammonium sulfate dissolved in water MolNH4+ = ? 2 molNH4+ X ------------------ 7.8 mol (NH4)2SO4 = 1 mol(NH4)2SO4 2:1 ratio 15.6 molNH4+ and 7.8 molSO4-2 are present

More Related