1 / 14

Calculating Empirical formulas

Calculating Empirical formulas. EMPIRICAL FORMULA. “Won’t you gimme three steps, Gimme three steps mister, Gimme three steps towards the …”. Calculating Empirical Formula. Convert grams to moles Calculate simplest mole ratio Write empirical formula. Step 1: Convert grams to moles.

Télécharger la présentation

Calculating Empirical formulas

An Image/Link below is provided (as is) to download presentation Download Policy: Content on the Website is provided to you AS IS for your information and personal use and may not be sold / licensed / shared on other websites without getting consent from its author. Content is provided to you AS IS for your information and personal use only. Download presentation by click this link. While downloading, if for some reason you are not able to download a presentation, the publisher may have deleted the file from their server. During download, if you can't get a presentation, the file might be deleted by the publisher.

E N D

Presentation Transcript


  1. CalculatingEmpiricalformulas

  2. EMPIRICAL FORMULA “Won’t you gimme three steps,Gimme three steps mister,Gimme three steps towards the …”

  3. Calculating Empirical Formula • Convert grams to moles • Calculate simplest mole ratio • Write empirical formula

  4. Step 1: Convert grams to moles. • When given percentages, assume a 100.00-gram sample of the unknown compound is available • Use the numbers given as percentages with the unit grams • Convert grams to moles using molar mass

  5. 10.89% Mg, 31.77% Cl, 57.34% O 10.89g Mg, 31.77gCl, 57.34g O 10.89 g Mg 1 mol Mg mol Mg = = 0.4481 mol Mg 24.3 g Mg 31.77 g Cl 1 molCl molCl = = 0.8949 molCl 35.5 g Cl 57.34 g O 1 molO mol O = = 3.584 mol O 16.0 g O

  6. Step 2: Calculate simplest mole ratio. • Divide the number of moles of each element by the smallest value calculated in Step 1 • If the result from the division is not a whole number, multiply it by the lowest factor that will result in a whole number • All other results must be multiplied by this same factor • Rounding, rather than multiplying, can only occur when the result is very close to a whole number

  7. 0.4481 mol Mg 0.8949 molCl 3.584 mol O 0.4481 mol Mg: = 1.000 = 1 0.4481 mol 0.8949 mol Cl: = 1.999 = 2 0.4481 mol 3.584 mol O: = 7.998 = 8 0.4481 mol

  8. Step 3: Write empirical formula. • The answers from Step 2 become the subscripts for each element in the empirical formula • Do not write subscripts of 1 • The empirical formula represents the simplest whole number ratio of elements in a compound

  9. Mg: 1 Mg Cl O Cl: 2 O: 8 1 2 8

  10. Mg(ClO4)2 MgCl2O8 Mg Cl O 1 2 8

  11. Determine the empirical formula for: • A compound containing 58.81% barium, 13.73 % sulfur, and 27.46% oxygen. • BaSO4 • A compound containing 36.5% sodium, 25.4% sulfur, and 38.1% oxygen. • Na2SO3

  12. p. 349: #144 and #145 Due Friday, 02/03 Empirical Formula HW

  13. Molecular Formula • Given: • Empirical formula (or data to calculate) • Molecular mass • To calculate molecular formula: molar mass of molecular formula molar mass of empirical formula

  14. Calculating Molecular Formula • The empirical formula of a compound is CH4. What is the molecular formula when the molecular mass is 64.0 g/mol? • C4H16 • A compound with a molar mass of 90.0 g/mol has the empirical formula CH2O. What is its molecular formula? • C3H6O3

More Related