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3.2 Solving Systems Algebraically

3.2 Solving Systems Algebraically. Solving System Algebraically Substitution. y = 2x + 5 x = -y + 14. Solving System Algebraically Substitution. y = 4x – 7 y = ½ x + 7. Solving System Algebraically Elimination. x + 6y = 10 2x + 5y = 6. Solving System Algebraically Elimination.

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3.2 Solving Systems Algebraically

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  1. 3.2 Solving Systems Algebraically

  2. Solving System AlgebraicallySubstitution y = 2x + 5 x = -y + 14

  3. Solving System AlgebraicallySubstitution y = 4x – 7 y = ½ x + 7

  4. Solving System AlgebraicallyElimination x + 6y = 10 2x + 5y = 6

  5. Solving System AlgebraicallyElimination 2x + 5y = -1 3x + 4y = -5

  6. When to use substitution? A variable in an equation is isolated Both equations are in y = mx +b form

  7. When to use elimination? Equations are in standard form ax + by = c

  8. Special Case #1 x + 3y = 10 2x + 6y = 19 The solution to they system is false because 0 = -1. There is no solution because the lines are parallel.

  9. Special Case #2 2x – 5y = 8 -4x + 10y = -16 The solution to they system is always true because 0 = 0. There is an infinite number of solutions is because they are the same line.

  10. Parametric Equations • Parametric Equations are equations that express the coordinates of x and y as separate functions of a common third variable, called the parameter. • You can use parametric equations to determine the position of an object over time.

  11. Parametric Example • Starting from a birdbath 3 feet above the ground, a bird takes flight. Let t equal time in seconds, x equal horizontal distance in feet, and y equal vertical distance in feet. The equation x(t)= 5t and y(t)=8t+3 model the bird’s distance from the base of the birdbath. Using a graphing calculator, describe the position of the bird at time t=3.

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